Simplify The Expression:$\left(-2 Y^5 X^4 \cdot X^5\right)^5$

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Understanding the Problem

When dealing with exponents, it's essential to remember the rules of exponentiation. The expression (βˆ’2y5x4β‹…x5)5\left(-2 y^5 x^4 \cdot x^5\right)^5 involves both multiplication and exponentiation. To simplify this expression, we need to apply the rules of exponentiation, specifically the power of a product rule.

The Power of a Product Rule

The power of a product rule states that when a product of factors is raised to a power, each factor in the product is raised to that power. Mathematically, this can be represented as:

(ab)n=anβ‹…bn(ab)^n = a^n \cdot b^n

In the given expression, we have (βˆ’2y5x4β‹…x5)5\left(-2 y^5 x^4 \cdot x^5\right)^5. Using the power of a product rule, we can rewrite this expression as:

(βˆ’2y5x4)5β‹…(x5)5\left(-2 y^5 x^4\right)^5 \cdot \left(x^5\right)^5

Applying the Power of a Product Rule

Now that we have applied the power of a product rule, we can simplify each factor raised to the power of 5.

Simplifying the First Factor

The first factor is (βˆ’2y5x4)5\left(-2 y^5 x^4\right)^5. To simplify this, we need to apply the power of a power rule, which states that when a power is raised to another power, the exponents are multiplied. Mathematically, this can be represented as:

(am)n=amβ‹…n\left(a^m\right)^n = a^{m \cdot n}

Using this rule, we can rewrite the first factor as:

(βˆ’2)5β‹…(y5)5β‹…(x4)5(-2)^5 \cdot \left(y^5\right)^5 \cdot \left(x^4\right)^5

Simplifying the Second Factor

The second factor is (x5)5\left(x^5\right)^5. Using the power of a power rule, we can rewrite this factor as:

x5β‹…5x^{5 \cdot 5}

Simplifying the Expression

Now that we have simplified each factor, we can rewrite the original expression as:

(βˆ’2)5β‹…(y5)5β‹…(x4)5β‹…x5β‹…5(-2)^5 \cdot \left(y^5\right)^5 \cdot \left(x^4\right)^5 \cdot x^{5 \cdot 5}

Evaluating the Expression

To evaluate the expression, we need to calculate the values of each factor.

Evaluating the First Factor

The first factor is (βˆ’2)5(-2)^5. To evaluate this, we need to raise -2 to the power of 5.

(βˆ’2)5=βˆ’2β‹…βˆ’2β‹…βˆ’2β‹…βˆ’2β‹…βˆ’2=βˆ’32(-2)^5 = -2 \cdot -2 \cdot -2 \cdot -2 \cdot -2 = -32

Evaluating the Second Factor

The second factor is (y5)5\left(y^5\right)^5. To evaluate this, we need to raise y5y^5 to the power of 5.

(y5)5=y5β‹…5=y25\left(y^5\right)^5 = y^{5 \cdot 5} = y^{25}

Evaluating the Third Factor

The third factor is (x4)5\left(x^4\right)^5. To evaluate this, we need to raise x4x^4 to the power of 5.

(x4)5=x4β‹…5=x20\left(x^4\right)^5 = x^{4 \cdot 5} = x^{20}

Evaluating the Fourth Factor

The fourth factor is x5β‹…5x^{5 \cdot 5}. To evaluate this, we need to raise xx to the power of 25.

x5β‹…5=x25x^{5 \cdot 5} = x^{25}

Combining the Factors

Now that we have evaluated each factor, we can combine them to get the final result.

(βˆ’2)5β‹…(y5)5β‹…(x4)5β‹…x5β‹…5=βˆ’32β‹…y25β‹…x20β‹…x25(-2)^5 \cdot \left(y^5\right)^5 \cdot \left(x^4\right)^5 \cdot x^{5 \cdot 5} = -32 \cdot y^{25} \cdot x^{20} \cdot x^{25}

Simplifying the Final Result

To simplify the final result, we can combine the like terms.

βˆ’32β‹…y25β‹…x20β‹…x25=βˆ’32β‹…y25β‹…x45-32 \cdot y^{25} \cdot x^{20} \cdot x^{25} = -32 \cdot y^{25} \cdot x^{45}

The final answer is βˆ’32y25x45\boxed{-32 y^{25} x^{45}}.

Understanding the Problem

When dealing with exponents, it's essential to remember the rules of exponentiation. The expression (βˆ’2y5x4β‹…x5)5\left(-2 y^5 x^4 \cdot x^5\right)^5 involves both multiplication and exponentiation. To simplify this expression, we need to apply the rules of exponentiation, specifically the power of a product rule.

Q&A

Q: What is the power of a product rule?

A: The power of a product rule states that when a product of factors is raised to a power, each factor in the product is raised to that power. Mathematically, this can be represented as:

(ab)n=anβ‹…bn(ab)^n = a^n \cdot b^n

Q: How do I apply the power of a product rule to the given expression?

A: To apply the power of a product rule, we need to rewrite the expression as a product of factors. In this case, we can rewrite the expression as:

(βˆ’2y5x4)5β‹…(x5)5\left(-2 y^5 x^4\right)^5 \cdot \left(x^5\right)^5

Q: What is the power of a power rule?

A: The power of a power rule states that when a power is raised to another power, the exponents are multiplied. Mathematically, this can be represented as:

(am)n=amβ‹…n\left(a^m\right)^n = a^{m \cdot n}

Q: How do I apply the power of a power rule to the given expression?

A: To apply the power of a power rule, we need to rewrite each factor raised to the power of 5. In this case, we can rewrite the first factor as:

(βˆ’2)5β‹…(y5)5β‹…(x4)5(-2)^5 \cdot \left(y^5\right)^5 \cdot \left(x^4\right)^5

Q: What is the final result of simplifying the expression?

A: The final result of simplifying the expression is:

βˆ’32β‹…y25β‹…x45-32 \cdot y^{25} \cdot x^{45}

Q: How do I evaluate the expression?

A: To evaluate the expression, we need to calculate the values of each factor. In this case, we need to raise -2 to the power of 5, y5y^5 to the power of 5, x4x^4 to the power of 5, and xx to the power of 25.

Q: What are the values of each factor?

A: The values of each factor are:

  • (βˆ’2)5=βˆ’32(-2)^5 = -32
  • (y5)5=y25\left(y^5\right)^5 = y^{25}
  • (x4)5=x20\left(x^4\right)^5 = x^{20}
  • x5β‹…5=x25x^{5 \cdot 5} = x^{25}

Q: How do I combine the factors to get the final result?

A: To combine the factors, we need to multiply them together. In this case, we can combine the factors as follows:

βˆ’32β‹…y25β‹…x20β‹…x25=βˆ’32β‹…y25β‹…x45-32 \cdot y^{25} \cdot x^{20} \cdot x^{25} = -32 \cdot y^{25} \cdot x^{45}

Conclusion

Simplifying the expression (βˆ’2y5x4β‹…x5)5\left(-2 y^5 x^4 \cdot x^5\right)^5 involves applying the rules of exponentiation, specifically the power of a product rule and the power of a power rule. By following these rules and evaluating each factor, we can simplify the expression to get the final result.

Common Mistakes

  • Failing to apply the power of a product rule
  • Failing to apply the power of a power rule
  • Not evaluating each factor correctly
  • Not combining the factors correctly

Tips and Tricks

  • Make sure to apply the power of a product rule and the power of a power rule correctly
  • Evaluate each factor carefully and correctly
  • Combine the factors correctly to get the final result

Practice Problems

  • Simplify the expression (3x2y3β‹…x4)3\left(3 x^2 y^3 \cdot x^4\right)^3
  • Simplify the expression (2x5y2β‹…y3)2\left(2 x^5 y^2 \cdot y^3\right)^2
  • Simplify the expression (4x3y4β‹…x2)4\left(4 x^3 y^4 \cdot x^2\right)^4

Resources

  • Khan Academy: Exponents and Exponential Functions
  • Mathway: Exponents and Exponential Functions
  • Wolfram Alpha: Exponents and Exponential Functions