Select The Correct Answer.Which Expression Is Equivalent To The Given Expression $\ln \left(\frac{2 E}{x}\right$\]?A. $\ln 2 - \ln X$ B. $1 + \ln 2 - \ln X$ C. $\ln 1 + \ln 2 - \ln X$ D. $\ln 2 + \ln X$

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Introduction

Logarithmic expressions can be complex and challenging to simplify. However, with a clear understanding of the properties of logarithms, we can break down these expressions into more manageable parts. In this article, we will explore how to simplify the expression lnโก(2ex)\ln \left(\frac{2 e}{x}\right) and select the correct equivalent expression from the given options.

Understanding Logarithmic Properties

Before we dive into simplifying the given expression, let's review some essential logarithmic properties:

  • Product Rule: logโกb(xy)=logโกbx+logโกby\log_b (xy) = \log_b x + \log_b y
  • Quotient Rule: logโกb(xy)=logโกbxโˆ’logโกby\log_b \left(\frac{x}{y}\right) = \log_b x - \log_b y
  • Power Rule: logโกb(xn)=nlogโกbx\log_b (x^n) = n \log_b x

These properties will be instrumental in simplifying the given expression.

Simplifying the Expression

Now, let's apply the logarithmic properties to simplify the expression lnโก(2ex)\ln \left(\frac{2 e}{x}\right):

lnโก(2ex)=lnโก2+lnโกeโˆ’lnโกx\ln \left(\frac{2 e}{x}\right) = \ln 2 + \ln e - \ln x

Using the product rule, we can rewrite lnโก2\ln 2 as lnโก2โ‹…1\ln 2 \cdot 1, and lnโกe\ln e as lnโกeโ‹…1\ln e \cdot 1. This gives us:

lnโก(2ex)=lnโก2โ‹…1+lnโกeโ‹…1โˆ’lnโกx\ln \left(\frac{2 e}{x}\right) = \ln 2 \cdot 1 + \ln e \cdot 1 - \ln x

Now, we can apply the power rule to simplify lnโกe\ln e:

lnโก(2ex)=lnโก2+1โˆ’lnโกx\ln \left(\frac{2 e}{x}\right) = \ln 2 + 1 - \ln x

Using the quotient rule, we can rewrite 11 as 11\frac{1}{1}:

lnโก(2ex)=lnโก2+11โˆ’lnโกx\ln \left(\frac{2 e}{x}\right) = \ln 2 + \frac{1}{1} - \ln x

Simplifying further, we get:

lnโก(2ex)=lnโก2+1โˆ’lnโกx\ln \left(\frac{2 e}{x}\right) = \ln 2 + 1 - \ln x

Selecting the Correct Answer

Now that we have simplified the expression, let's compare it with the given options:

A. lnโก2โˆ’lnโกx\ln 2 - \ln x B. 1+lnโก2โˆ’lnโกx1 + \ln 2 - \ln x C. lnโก1+lnโก2โˆ’lnโกx\ln 1 + \ln 2 - \ln x D. lnโก2+lnโกx\ln 2 + \ln x

Based on our simplification, the correct answer is:

B. 1+lnโก2โˆ’lnโกx1 + \ln 2 - \ln x

This option matches our simplified expression, which is lnโก2+1โˆ’lnโกx\ln 2 + 1 - \ln x.

Conclusion

Simplifying logarithmic expressions requires a clear understanding of the properties of logarithms. By applying the product rule, quotient rule, and power rule, we can break down complex expressions into more manageable parts. In this article, we simplified the expression lnโก(2ex)\ln \left(\frac{2 e}{x}\right) and selected the correct equivalent expression from the given options. With practice and patience, you can master the art of simplifying logarithmic expressions and tackle even the most challenging problems.

Additional Tips and Resources

  • Practice, Practice, Practice: The more you practice simplifying logarithmic expressions, the more comfortable you will become with the properties of logarithms.
  • Use Online Resources: Websites like Khan Academy, Mathway, and Wolfram Alpha offer interactive tools and resources to help you practice and learn logarithmic properties.
  • Consult a Math Textbook: If you're struggling with logarithmic properties, consult a math textbook or online resource for a comprehensive review.

Introduction

In our previous article, we explored how to simplify the expression lnโก(2ex)\ln \left(\frac{2 e}{x}\right) using logarithmic properties. However, we know that practice makes perfect, and the best way to learn is by asking questions and seeking answers. In this article, we'll address some common questions and concerns related to logarithmic expression simplification.

Q: What is the difference between the product rule and the quotient rule?

A: The product rule states that logโกb(xy)=logโกbx+logโกby\log_b (xy) = \log_b x + \log_b y, while the quotient rule states that logโกb(xy)=logโกbxโˆ’logโกby\log_b \left(\frac{x}{y}\right) = \log_b x - \log_b y. In other words, when multiplying two numbers, you add their logarithms, and when dividing two numbers, you subtract their logarithms.

Q: How do I apply the power rule to simplify logarithmic expressions?

A: The power rule states that logโกb(xn)=nlogโกbx\log_b (x^n) = n \log_b x. To apply this rule, simply multiply the exponent by the logarithm of the base. For example, logโก2(43)=3logโก24\log_2 (4^3) = 3 \log_2 4.

Q: What is the difference between a logarithmic expression and an exponential expression?

A: A logarithmic expression is an expression that involves a logarithm, such as logโก24\log_2 4. An exponential expression, on the other hand, is an expression that involves an exponent, such as 232^3. While logarithmic expressions and exponential expressions are related, they are not the same thing.

Q: How do I simplify logarithmic expressions with multiple terms?

A: To simplify logarithmic expressions with multiple terms, apply the product rule and quotient rule as needed. For example, logโก2(4โ‹…9)=logโก24+logโก29\log_2 (4 \cdot 9) = \log_2 4 + \log_2 9. If the expression involves a quotient, apply the quotient rule: logโก2(49)=logโก24โˆ’logโก29\log_2 \left(\frac{4}{9}\right) = \log_2 4 - \log_2 9.

Q: What is the relationship between logarithmic expressions and exponential functions?

A: Logarithmic expressions and exponential functions are inverse functions. In other words, if y=2xy = 2^x, then x=logโก2yx = \log_2 y. This means that logarithmic expressions and exponential functions are related, but they are not the same thing.

Q: How do I evaluate logarithmic expressions with negative exponents?

A: To evaluate logarithmic expressions with negative exponents, apply the property that logโกbx=โˆ’logโกb(1x)\log_b x = -\log_b \left(\frac{1}{x}\right). For example, logโก24โˆ’1=โˆ’logโก24\log_2 4^{-1} = -\log_2 4.

Conclusion

Logarithmic expression simplification can be a challenging topic, but with practice and patience, you can master the art of simplifying even the most complex expressions. By understanding the properties of logarithms and applying them correctly, you can tackle a wide range of problems and become a logarithmic expression simplification expert.

Additional Tips and Resources

  • Practice, Practice, Practice: The more you practice simplifying logarithmic expressions, the more comfortable you will become with the properties of logarithms.
  • Use Online Resources: Websites like Khan Academy, Mathway, and Wolfram Alpha offer interactive tools and resources to help you practice and learn logarithmic properties.
  • Consult a Math Textbook: If you're struggling with logarithmic properties, consult a math textbook or online resource for a comprehensive review.

By following these tips and resources, you'll be well on your way to becoming a logarithmic expression simplification master!