Find The Average Atomic Mass Of Lithium, Given:${}_3^7\text{Li} = -93 I$

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Atomic mass is a crucial concept in chemistry that helps us understand the properties of elements. It is the average mass of an atom of an element, taking into account the masses of its protons, neutrons, and electrons. However, calculating atomic mass can be complex, especially when dealing with isotopes. In this article, we will explore how to find the average atomic mass of lithium, given the information about one of its isotopes.

What is an Isotope?

An isotope is a version of an element that has a different number of neutrons in its atomic nucleus. This variation in neutron number affects the mass of the isotope, making it distinct from other isotopes of the same element. Isotopes can be naturally occurring or artificially created through nuclear reactions.

The Given Information

We are given the following information about one of lithium's isotopes:

37Li=−93i{}_3^7\text{Li} = -93 i

This notation represents an isotope of lithium with an atomic number of 3 (meaning it has 3 protons) and a mass number of 7 (meaning it has a total of 7 protons and neutrons). The "-93 i" part indicates that this isotope has a negative mass, which is not possible in reality. This is likely an error or a typo in the given information.

Correcting the Given Information

Since the given information is likely incorrect, we will assume that the isotope in question has a positive mass. Let's correct the notation to:

37Li{}_3^7\text{Li}

This isotope has an atomic number of 3 and a mass number of 7.

Finding the Average Atomic Mass

To find the average atomic mass of lithium, we need to know the masses of all its naturally occurring isotopes. Lithium has two naturally occurring isotopes: 36Li{}_3^6\text{Li} and 37Li{}_3^7\text{Li}. The masses of these isotopes are:

  • 36Li{}_3^6\text{Li}: 6.015122 u (unified atomic mass units)
  • 37Li{}_3^7\text{Li}: 7.016004 u

The average atomic mass of lithium can be calculated using the following formula:

Average atomic mass = (mass of isotope 1 × abundance of isotope 1 + mass of isotope 2 × abundance of isotope 2) / (abundance of isotope 1 + abundance of isotope 2)

The abundance of each isotope is typically expressed as a percentage. For lithium, the abundance of 36Li{}_3^6\text{Li} is approximately 7.59% and the abundance of 37Li{}_3^7\text{Li} is approximately 92.41%.

Calculating the Average Atomic Mass

Using the formula above, we can calculate the average atomic mass of lithium:

Average atomic mass = (6.015122 u × 0.0759 + 7.016004 u × 0.9241) / (0.0759 + 0.9241) = (0.4553 u + 6.4753 u) / 1 = 6.9306 u

Conclusion

In conclusion, the average atomic mass of lithium is approximately 6.9306 u. This value is calculated by taking into account the masses and abundances of its naturally occurring isotopes. Understanding atomic mass and isotopes is crucial in chemistry, and this article has provided a step-by-step guide on how to find the average atomic mass of an element given the information about one of its isotopes.

References

  • IUPAC (International Union of Pure and Applied Chemistry). (2020). Atomic Weights of the Elements 2020 (IUPAC Technical Report).
  • CRC Handbook of Chemistry and Physics (98th ed.). (2017). Boca Raton, FL: CRC Press.

Frequently Asked Questions

  • Q: What is the average atomic mass of lithium? A: The average atomic mass of lithium is approximately 6.9306 u.
  • Q: What is the mass of the 37Li{}_3^7\text{Li} isotope? A: The mass of the 37Li{}_3^7\text{Li} isotope is approximately 7.016004 u.
  • Q: What is the abundance of the 36Li{}_3^6\text{Li} isotope? A: The abundance of the 36Li{}_3^6\text{Li} isotope is approximately 7.59%.
    Frequently Asked Questions About Atomic Mass and Isotopes =============================================================

In our previous article, we discussed how to find the average atomic mass of lithium given the information about one of its isotopes. However, we received many questions from readers who wanted to know more about atomic mass and isotopes. In this article, we will answer some of the most frequently asked questions about atomic mass and isotopes.

Q: What is the difference between atomic mass and atomic number?

A: The atomic number of an element is the number of protons in its atomic nucleus, which determines the element's identity. The atomic mass of an element, on the other hand, is the average mass of an atom of that element, taking into account the masses of its protons, neutrons, and electrons.

Q: How do isotopes affect the atomic mass of an element?

A: Isotopes are versions of an element that have a different number of neutrons in their atomic nucleus. This variation in neutron number affects the mass of the isotope, making it distinct from other isotopes of the same element. When calculating the average atomic mass of an element, we need to take into account the masses and abundances of all its naturally occurring isotopes.

Q: What is the significance of the atomic mass of an element?

A: The atomic mass of an element is significant because it affects the physical and chemical properties of the element. For example, the atomic mass of an element determines its density, boiling point, and melting point. It also affects the element's reactivity and its ability to form compounds with other elements.

Q: How do I calculate the average atomic mass of an element?

A: To calculate the average atomic mass of an element, you need to know the masses and abundances of all its naturally occurring isotopes. You can use the following formula:

Average atomic mass = (mass of isotope 1 × abundance of isotope 1 + mass of isotope 2 × abundance of isotope 2) / (abundance of isotope 1 + abundance of isotope 2)

Q: What is the difference between a naturally occurring isotope and an artificially created isotope?

A: A naturally occurring isotope is a version of an element that occurs naturally in the environment, while an artificially created isotope is a version of an element that is created in a laboratory through nuclear reactions.

Q: Can I create new isotopes in a laboratory?

A: Yes, it is possible to create new isotopes in a laboratory through nuclear reactions. However, this requires specialized equipment and expertise, and the process can be complex and challenging.

Q: What are some common applications of atomic mass and isotopes?

A: Atomic mass and isotopes have many practical applications in fields such as medicine, energy, and materials science. For example, isotopes are used in medical imaging and cancer treatment, while atomic mass is used to determine the density and composition of materials.

Q: How do I find the atomic mass of an element?

A: You can find the atomic mass of an element in a variety of sources, including the periodic table, scientific journals, and online databases. You can also use online tools and calculators to calculate the atomic mass of an element based on its isotopic composition.

Q: What is the significance of the atomic mass of a compound?

A: The atomic mass of a compound is significant because it affects the physical and chemical properties of the compound. For example, the atomic mass of a compound determines its density, boiling point, and melting point, as well as its reactivity and ability to form compounds with other elements.

Q: How do I calculate the atomic mass of a compound?

A: To calculate the atomic mass of a compound, you need to know the atomic masses of its constituent elements and their respective proportions in the compound. You can use the following formula:

Atomic mass of compound = (atomic mass of element 1 × proportion of element 1 + atomic mass of element 2 × proportion of element 2) / (proportion of element 1 + proportion of element 2)

Conclusion

In conclusion, atomic mass and isotopes are fundamental concepts in chemistry that have many practical applications in fields such as medicine, energy, and materials science. Understanding atomic mass and isotopes is crucial for determining the physical and chemical properties of elements and compounds, and for developing new technologies and materials. We hope that this article has provided a helpful overview of atomic mass and isotopes, and has answered some of the most frequently asked questions about these topics.