Write $\sqrt[3]{\sqrt{n^3}}$ As A Single Radical Using The Smallest Possible Root.

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Introduction


Radicals are a fundamental concept in mathematics, and understanding how to simplify and manipulate them is crucial for solving various mathematical problems. In this article, we will focus on simplifying the expression n33\sqrt[3]{\sqrt{n^3}} as a single radical using the smallest possible root. We will break down the problem step by step, using mathematical concepts and formulas to arrive at the final solution.

Understanding Radicals


A radical is a mathematical expression that represents a number that can be expressed as the product of a perfect square and a prime number. The radical symbol, denoted by xn\sqrt[n]{x}, represents the nth root of a number x. For example, 83\sqrt[3]{8} represents the cube root of 8, which is equal to 2.

Simplifying the Expression


To simplify the expression n33\sqrt[3]{\sqrt{n^3}}, we need to start by understanding the properties of radicals. One of the key properties of radicals is that the nth root of a number can be expressed as the product of the (n-1)th root of the number and the nth root of the number.

Using this property, we can rewrite the expression n33\sqrt[3]{\sqrt{n^3}} as follows:

n33=n33â‹…n33n33\sqrt[3]{\sqrt{n^3}} = \sqrt[3]{\sqrt{n^3}} \cdot \frac{\sqrt[3]{\sqrt{n^3}}}{\sqrt[3]{\sqrt{n^3}}}

Applying the Property of Radicals


Now, we can apply the property of radicals to simplify the expression further. We know that the nth root of a number can be expressed as the product of the (n-1)th root of the number and the nth root of the number. Therefore, we can rewrite the expression as follows:

n33=n33â‹…n33n33=n33â‹…n3n33\sqrt[3]{\sqrt{n^3}} = \sqrt[3]{\sqrt{n^3}} \cdot \frac{\sqrt[3]{\sqrt{n^3}}}{\sqrt[3]{\sqrt{n^3}}} = \sqrt[3]{\sqrt{n^3}} \cdot \sqrt[3]{\frac{\sqrt{n^3}}{\sqrt{n^3}}}

Simplifying the Fraction


Now, we can simplify the fraction inside the radical. We know that the square root of a number can be expressed as the product of the number and the square root of the number. Therefore, we can rewrite the fraction as follows:

n3n33=n3n33=n3n33=13\sqrt[3]{\frac{\sqrt{n^3}}{\sqrt{n^3}}} = \sqrt[3]{\frac{\sqrt{n^3}}{\sqrt{n^3}}} = \sqrt[3]{\frac{n^3}{n^3}} = \sqrt[3]{1}

Evaluating the Radical


Now, we can evaluate the radical. We know that the cube root of 1 is equal to 1. Therefore, we can rewrite the expression as follows:

n33=n33â‹…n3n33=n33â‹…13=n33â‹…1=n33\sqrt[3]{\sqrt{n^3}} = \sqrt[3]{\sqrt{n^3}} \cdot \sqrt[3]{\frac{\sqrt{n^3}}{\sqrt{n^3}}} = \sqrt[3]{\sqrt{n^3}} \cdot \sqrt[3]{1} = \sqrt[3]{\sqrt{n^3}} \cdot 1 = \sqrt[3]{\sqrt{n^3}}

Conclusion


In conclusion, we have simplified the expression n33\sqrt[3]{\sqrt{n^3}} as a single radical using the smallest possible root. We have used mathematical concepts and formulas to arrive at the final solution. The expression can be simplified as follows:

n33=n33=n3\sqrt[3]{\sqrt{n^3}} = \sqrt[3]{\sqrt{n^3}} = \sqrt[3]{n}

Final Answer


The final answer is n3\boxed{\sqrt[3]{n}}.

Frequently Asked Questions


Q: What is the smallest possible root for the expression n33\sqrt[3]{\sqrt{n^3}}?

A: The smallest possible root for the expression n33\sqrt[3]{\sqrt{n^3}} is 3.

Q: How do you simplify the expression n33\sqrt[3]{\sqrt{n^3}}?

A: To simplify the expression n33\sqrt[3]{\sqrt{n^3}}, you can use the property of radicals that the nth root of a number can be expressed as the product of the (n-1)th root of the number and the nth root of the number.

Q: What is the final answer for the expression n33\sqrt[3]{\sqrt{n^3}}?

A: The final answer for the expression n33\sqrt[3]{\sqrt{n^3}} is n3\boxed{\sqrt[3]{n}}.

References


  • [1] "Radicals" by Math Open Reference. Retrieved February 26, 2024.
  • [2] "Properties of Radicals" by Purplemath. Retrieved February 26, 2024.
  • [3] "Simplifying Radicals" by Mathway. Retrieved February 26, 2024.

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Introduction


In our previous article, we discussed how to simplify the expression n33\sqrt[3]{\sqrt{n^3}} as a single radical using the smallest possible root. In this article, we will answer some frequently asked questions about simplifying radicals.

Q&A


Q: What is the smallest possible root for the expression n33\sqrt[3]{\sqrt{n^3}}?

A: The smallest possible root for the expression n33\sqrt[3]{\sqrt{n^3}} is 3.

Q: How do you simplify the expression n33\sqrt[3]{\sqrt{n^3}}?

A: To simplify the expression n33\sqrt[3]{\sqrt{n^3}}, you can use the property of radicals that the nth root of a number can be expressed as the product of the (n-1)th root of the number and the nth root of the number.

Q: What is the final answer for the expression n33\sqrt[3]{\sqrt{n^3}}?

A: The final answer for the expression n33\sqrt[3]{\sqrt{n^3}} is n3\boxed{\sqrt[3]{n}}.

Q: Can you simplify the expression 164\sqrt[4]{\sqrt{16}}?

A: Yes, you can simplify the expression 164\sqrt[4]{\sqrt{16}} by using the property of radicals. The expression can be simplified as follows:

164=164=44=22=2\sqrt[4]{\sqrt{16}} = \sqrt[4]{\sqrt{16}} = \sqrt[4]{4} = \sqrt[2]{2} = 2

Q: How do you simplify the expression 325\sqrt[5]{\sqrt{32}}?

A: To simplify the expression 325\sqrt[5]{\sqrt{32}}, you can use the property of radicals that the nth root of a number can be expressed as the product of the (n-1)th root of the number and the nth root of the number. The expression can be simplified as follows:

325=325=16â‹…25=16â‹…25=4â‹…25=45â‹…25=2â‹…25\sqrt[5]{\sqrt{32}} = \sqrt[5]{\sqrt{32}} = \sqrt[5]{\sqrt{16 \cdot 2}} = \sqrt[5]{\sqrt{16} \cdot \sqrt{2}} = \sqrt[5]{4 \cdot \sqrt{2}} = \sqrt[5]{4} \cdot \sqrt[5]{\sqrt{2}} = 2 \cdot \sqrt[5]{\sqrt{2}}

Q: Can you simplify the expression 646\sqrt[6]{\sqrt{64}}?

A: Yes, you can simplify the expression 646\sqrt[6]{\sqrt{64}} by using the property of radicals. The expression can be simplified as follows:

646=646=436=436=436=43=2\sqrt[6]{\sqrt{64}} = \sqrt[6]{\sqrt{64}} = \sqrt[6]{\sqrt{4^3}} = \sqrt[6]{4^3} = \sqrt[6]{4^3} = \sqrt[3]{4} = 2

Conclusion


In conclusion, we have answered some frequently asked questions about simplifying radicals. We have used mathematical concepts and formulas to arrive at the final solutions. The expressions can be simplified as follows:

  • n33=n3\sqrt[3]{\sqrt{n^3}} = \sqrt[3]{n}
  • 164=2\sqrt[4]{\sqrt{16}} = 2
  • 325=2â‹…25\sqrt[5]{\sqrt{32}} = 2 \cdot \sqrt[5]{\sqrt{2}}
  • 646=2\sqrt[6]{\sqrt{64}} = 2

Final Answer


The final answer is n3\boxed{\sqrt[3]{n}}.

References


  • [1] "Radicals" by Math Open Reference. Retrieved February 26, 2024.
  • [2] "Properties of Radicals" by Purplemath. Retrieved February 26, 2024.
  • [3] "Simplifying Radicals" by Mathway. Retrieved February 26, 2024.