Which System Of Equations Below Has No Solution?A. $y = 4x + 5$ And $y = 4x - 5$B. $y = 4x + 5$ And $2y = 8x + 10$C. $y = 4x + 5$ And $y = \frac{1}{4}x + 5$D. $y = 4x + 5$ And $y = 8x +

Introduction

When dealing with systems of equations, it's essential to understand the different types of solutions that can arise. In this article, we will explore the concept of a system of equations with no solution. We will examine four different systems of equations and determine which one has no solution.

What is a System of Equations?

A system of equations is a set of two or more equations that contain multiple variables. Each equation in the system is a statement that two expressions are equal. For example, the system of equations:

$$\begin{cases} y = 4x + 5 \\ y = 2x - 3 \end{cases}$$

is a system of two equations with two variables, x and y.

Types of Solutions to a System of Equations

There are three types of solutions to a system of equations:

1. One solution: A system of equations has one solution if there is a unique point that satisfies both equations.
2. Infinitely many solutions: A system of equations has infinitely many solutions if there are an infinite number of points that satisfy both equations.
3. No solution: A system of equations has no solution if there is no point that satisfies both equations.

System A: $y = 4x + 5$ and $y = 4x - 5$

Let's examine the first system of equations:

$$\begin{cases} y = 4x + 5 \\ y = 4x - 5 \end{cases}$$

To determine if this system has a solution, we can set the two equations equal to each other:

$$4x + 5 = 4x - 5$$

Subtracting 4x from both sides gives us:

$$5 = -5$$

This is a contradiction, as 5 is not equal to -5. Therefore, this system of equations has no solution.

System B: $y = 4x + 5$ and $2y = 8x + 10$

Now, let's examine the second system of equations:

$$\begin{cases} y = 4x + 5 \\ 2y = 8x + 10 \end{cases}$$

We can simplify the second equation by dividing both sides by 2:

$$y = 4x + 5$$

This is the same as the first equation. Therefore, this system of equations has infinitely many solutions.

System C: $y = 4x + 5$ and $y = \frac{1}{4}x + 5$

Next, let's examine the third system of equations:

$$\begin{cases} y = 4x + 5 \\ y = \frac{1}{4}x + 5 \end{cases}$$

We can set the two equations equal to each other:

$$4x + 5 = \frac{1}{4}x + 5$$

Multiplying both sides by 4 gives us:

$$16x + 20 = x + 20$$

Subtracting x from both sides gives us:

$$15x + 20 = 20$$

Subtracting 20 from both sides gives us:

$$15x = 0$$

Dividing both sides by 15 gives us:

$$x = 0$$

Substituting x = 0 into one of the original equations gives us:

$$y = 4(0) + 5$$

$$y = 5$$

Therefore, this system of equations has one solution.

System D: $y = 4x + 5$ and $y = 8x + 10$

Finally, let's examine the fourth system of equations:

$$\begin{cases} y = 4x + 5 \\ y = 8x + 10 \end{cases}$$

We can set the two equations equal to each other:

$$4x + 5 = 8x + 10$$

Subtracting 4x from both sides gives us:

$$5 = 4x + 10$$

Subtracting 10 from both sides gives us:

$$-5 = 4x$$

Dividing both sides by 4 gives us:

$$-\frac{5}{4} = x$$

Substituting x = -5/4 into one of the original equations gives us:

$$y = 4(-\frac{5}{4}) + 5$$

$$y = -5 + 5$$

$$y = 0$$

Therefore, this system of equations has one solution.

Conclusion

In conclusion, the system of equations that has no solution is:

$$\begin{cases} y = 4x + 5 \\ y = 4x - 5 \end{cases}$$

This system has no solution because there is no point that satisfies both equations.

References

• [1] "Systems of Equations" by Math Open Reference
• [2] "Systems of Linear Equations" by Khan Academy
• [3] "Systems of Equations" by Purplemath
  

Introduction

In our previous article, we explored the concept of a system of equations with no solution. We examined four different systems of equations and determined which one had no solution. In this article, we will answer some frequently asked questions about systems of equations with no solution.

Q: What is a system of equations with no solution?

A: A system of equations with no solution is a set of two or more equations that contain multiple variables, where there is no point that satisfies all the equations.

Q: How do I know if a system of equations has no solution?

A: To determine if a system of equations has no solution, you can try to solve the system by setting the equations equal to each other and simplifying. If you get a contradiction, such as 2 = 3, then the system has no solution.

Q: Can a system of equations with no solution have two linear equations?

A: Yes, a system of equations with no solution can have two linear equations. For example:

$$\begin{cases} y = 4x + 5 \\ y = 4x - 5 \end{cases}$$

This system has no solution because there is no point that satisfies both equations.

Q: Can a system of equations with no solution have two quadratic equations?

A: Yes, a system of equations with no solution can have two quadratic equations. For example:

$$\begin{cases} y = x^2 + 4x + 3 \\ y = x^2 + 4x + 2 \end{cases}$$

This system has no solution because there is no point that satisfies both equations.

Q: Can a system of equations with no solution have more than two equations?

A: Yes, a system of equations with no solution can have more than two equations. For example:

$$\begin{cases} y = 4x + 5 \\ y = 4x - 5 \\ y = 2x + 3 \end{cases}$$

This system has no solution because there is no point that satisfies all three equations.

Q: Can a system of equations with no solution have a variable that is not present in all the equations?

A: Yes, a system of equations with no solution can have a variable that is not present in all the equations. For example:

$$\begin{cases} y = 4x + 5 \\ y = 2z + 3 \end{cases}$$

This system has no solution because there is no point that satisfies both equations.

Q: Can a system of equations with no solution have a constant term that is not present in all the equations?

A: Yes, a system of equations with no solution can have a constant term that is not present in all the equations. For example:

$$\begin{cases} y = 4x + 5 \\ y = 4x + 2 \end{cases}$$

This system has no solution because there is no point that satisfies both equations.

Conclusion

In conclusion, a system of equations with no solution can have two or more linear or quadratic equations, and can have a variable or constant term that is not present in all the equations. We hope this article has helped to clarify some of the common questions about systems of equations with no solution.

References

• [1] "Systems of Equations" by Math Open Reference
• [2] "Systems of Linear Equations" by Khan Academy
• [3] "Systems of Equations" by Purplemath