Which Point Would Map Onto Itself After A Reflection Across The Line $y = -x$?A. $(-4, -4$\] B. $(-4, 0$\] C. $(0, -4$\] D. $(4, -4$\]

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Reflection Across the Line y=βˆ’xy = -x: Understanding the Concept

Reflection across a line is a fundamental concept in geometry and mathematics. It involves flipping a point or a shape over a given line, resulting in a new position or shape. In this article, we will explore the concept of reflection across the line y=βˆ’xy = -x and determine which point would map onto itself after such a reflection.

What is Reflection Across a Line?

Reflection across a line is a transformation that flips a point or a shape over a given line. This transformation can be thought of as a mirror image of the original point or shape, with respect to the line of reflection. The line of reflection acts as a mirror, and the point or shape is reflected over it to produce a new position or shape.

Reflection Across the Line y=βˆ’xy = -x

The line y=βˆ’xy = -x is a diagonal line that passes through the origin (0, 0) and has a slope of -1. To reflect a point across this line, we need to find the point that is symmetric to the original point with respect to the line y=βˆ’xy = -x.

How to Reflect a Point Across the Line y=βˆ’xy = -x

To reflect a point (x,y)(x, y) across the line y=βˆ’xy = -x, we need to find the point that is symmetric to the original point with respect to the line. This can be done by using the following formula:

(xβ€²,yβ€²)=(βˆ’y,βˆ’x)(x', y') = (-y, -x)

where (xβ€²,yβ€²)(x', y') is the reflected point.

Applying the Formula to the Given Points

Now, let's apply the formula to the given points to determine which point would map onto itself after a reflection across the line y=βˆ’xy = -x.

A. (βˆ’4,βˆ’4)(-4, -4)

Using the formula, we get:

(βˆ’4β€²,βˆ’4β€²)=(βˆ’(βˆ’4),βˆ’(βˆ’4))=(4,4)(-4', -4') = (-(-4), -(-4)) = (4, 4)

This is not the original point, so option A is incorrect.

B. (βˆ’4,0)(-4, 0)

Using the formula, we get:

(βˆ’4β€²,0β€²)=(βˆ’0,βˆ’(βˆ’4))=(0,4)(-4', 0') = (-0, -(-4)) = (0, 4)

This is not the original point, so option B is incorrect.

C. (0,βˆ’4)(0, -4)

Using the formula, we get:

(0β€²,βˆ’4β€²)=(βˆ’(βˆ’4),βˆ’0)=(4,0)(0', -4') = (-(-4), -0) = (4, 0)

This is not the original point, so option C is incorrect.

D. (4,βˆ’4)(4, -4)

Using the formula, we get:

(4β€²,βˆ’4β€²)=(βˆ’(βˆ’4),βˆ’4)=(4,βˆ’4)(4', -4') = (-(-4), -4) = (4, -4)

This is the original point, so option D is correct.

Conclusion

In conclusion, the point that would map onto itself after a reflection across the line y=βˆ’xy = -x is (4,βˆ’4)(4, -4). This is because when we apply the formula for reflection across the line y=βˆ’xy = -x to this point, we get the original point as the result.

Reflection Across the Line y=βˆ’xy = -x: Key Takeaways

  • Reflection across a line is a transformation that flips a point or a shape over a given line.
  • The line of reflection acts as a mirror, and the point or shape is reflected over it to produce a new position or shape.
  • To reflect a point across the line y=βˆ’xy = -x, we need to find the point that is symmetric to the original point with respect to the line.
  • The formula for reflection across the line y=βˆ’xy = -x is (xβ€²,yβ€²)=(βˆ’y,βˆ’x)(x', y') = (-y, -x).
  • The point that would map onto itself after a reflection across the line y=βˆ’xy = -x is (4,βˆ’4)(4, -4).
    Reflection Across the Line y=βˆ’xy = -x: Q&A

In this article, we will continue to explore the concept of reflection across the line y=βˆ’xy = -x and answer some frequently asked questions related to this topic.

Q: What is the purpose of reflecting a point across the line y=βˆ’xy = -x?

A: The purpose of reflecting a point across the line y=βˆ’xy = -x is to find the point that is symmetric to the original point with respect to the line. This can be useful in various mathematical and real-world applications, such as geometry, trigonometry, and computer graphics.

Q: How do I determine if a point is reflected across the line y=βˆ’xy = -x?

A: To determine if a point is reflected across the line y=βˆ’xy = -x, you can use the formula (xβ€²,yβ€²)=(βˆ’y,βˆ’x)(x', y') = (-y, -x), where (xβ€²,yβ€²)(x', y') is the reflected point. If the reflected point is the same as the original point, then the point is reflected across the line y=βˆ’xy = -x.

Q: What is the relationship between the line y=βˆ’xy = -x and the point (4,βˆ’4)(4, -4)?

A: The point (4,βˆ’4)(4, -4) is reflected across the line y=βˆ’xy = -x. This means that if you reflect the point (4,βˆ’4)(4, -4) across the line y=βˆ’xy = -x, you will get the same point back.

Q: Can I reflect a point across the line y=βˆ’xy = -x using a graphing calculator?

A: Yes, you can reflect a point across the line y=βˆ’xy = -x using a graphing calculator. Most graphing calculators have a built-in function to reflect a point across a line. You can also use the formula (xβ€²,yβ€²)=(βˆ’y,βˆ’x)(x', y') = (-y, -x) to reflect a point manually.

Q: How do I reflect a point across the line y=βˆ’xy = -x in three dimensions?

A: To reflect a point (x,y,z)(x, y, z) across the line y=βˆ’xy = -x in three dimensions, you can use the formula (xβ€²,yβ€²,zβ€²)=(βˆ’y,βˆ’x,z)(x', y', z') = (-y, -x, z). This will give you the reflected point in three dimensions.

Q: Can I reflect a point across the line y=βˆ’xy = -x using a computer program?

A: Yes, you can reflect a point across the line y=βˆ’xy = -x using a computer program. Most programming languages, such as Python and MATLAB, have built-in functions to reflect a point across a line. You can also use the formula (xβ€²,yβ€²)=(βˆ’y,βˆ’x)(x', y') = (-y, -x) to reflect a point manually.

Q: What are some real-world applications of reflecting a point across the line y=βˆ’xy = -x?

A: Some real-world applications of reflecting a point across the line y=βˆ’xy = -x include:

  • Computer graphics: Reflecting a point across the line y=βˆ’xy = -x can be used to create mirror-like effects in computer graphics.
  • Geometry: Reflecting a point across the line y=βˆ’xy = -x can be used to find the midpoint of a line segment.
  • Trigonometry: Reflecting a point across the line y=βˆ’xy = -x can be used to find the sine and cosine of an angle.

Conclusion

In conclusion, reflecting a point across the line y=βˆ’xy = -x is a fundamental concept in geometry and mathematics. It can be used to find the point that is symmetric to the original point with respect to the line, and has various real-world applications. We hope this article has helped you understand the concept of reflection across the line y=βˆ’xy = -x and answer some frequently asked questions related to this topic.

Reflection Across the Line y=βˆ’xy = -x: Key Takeaways

  • Reflection across a line is a transformation that flips a point or a shape over a given line.
  • The line of reflection acts as a mirror, and the point or shape is reflected over it to produce a new position or shape.
  • To reflect a point across the line y=βˆ’xy = -x, you can use the formula (xβ€²,yβ€²)=(βˆ’y,βˆ’x)(x', y') = (-y, -x).
  • The point that would map onto itself after a reflection across the line y=βˆ’xy = -x is (4,βˆ’4)(4, -4).
  • Reflection across the line y=βˆ’xy = -x has various real-world applications, including computer graphics, geometry, and trigonometry.