Which Equation Can Be Simplified To Find The Inverse Of Y = 5 X 2 + 10 Y = 5x^2 + 10 Y = 5 X 2 + 10 ?A. X = 5 Y 2 + 10 X = 5y^2 + 10 X = 5 Y 2 + 10 B. 1 Y = 5 X 2 + 10 \frac{1}{y} = 5x^2 + 10 Y 1 ​ = 5 X 2 + 10 C. − Y = 5 X 2 + 10 -y = 5x^2 + 10 − Y = 5 X 2 + 10 D. Y = 1 5 X 2 + 1 10 Y = \frac{1}{5}x^2 + \frac{1}{10} Y = 5 1 ​ X 2 + 10 1 ​

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Introduction

Inverse functions are a crucial concept in mathematics, and they play a vital role in various fields, including algebra, calculus, and engineering. In this article, we will focus on finding the inverse of a quadratic equation, specifically the equation y=5x2+10y = 5x^2 + 10. To find the inverse, we need to simplify the given equation and express it in terms of xx as a function of yy. In this discussion, we will explore the different options and determine which equation can be simplified to find the inverse of the given quadratic equation.

Understanding the Concept of Inverse Functions

Before we dive into the problem, let's briefly review the concept of inverse functions. An inverse function is a function that undoes the action of the original function. In other words, if we have a function f(x)f(x), its inverse function f1(x)f^{-1}(x) will take the output of f(x)f(x) and return the original input. In mathematical terms, if f(x)=yf(x) = y, then f1(y)=xf^{-1}(y) = x.

Simplifying the Given Equation

To find the inverse of the given equation y=5x2+10y = 5x^2 + 10, we need to simplify it and express it in terms of xx as a function of yy. Let's start by isolating the term with xx.

y = 5x^2 + 10

Option A: x=5y2+10x = 5y^2 + 10

Let's analyze the first option, x=5y2+10x = 5y^2 + 10. To determine if this is the correct equation, we need to substitute y=5x2+10y = 5x^2 + 10 into the equation and see if we get the original equation.

x = 5y^2 + 10
x = 5(5x^2 + 10)^2 + 10

As we can see, the equation does not simplify to the original equation, so this is not the correct option.

Option B: 1y=5x2+10\frac{1}{y} = 5x^2 + 10

Now, let's analyze the second option, 1y=5x2+10\frac{1}{y} = 5x^2 + 10. To determine if this is the correct equation, we need to substitute y=5x2+10y = 5x^2 + 10 into the equation and see if we get the original equation.

\frac{1}{y} = 5x^2 + 10
\frac{1}{5x^2 + 10} = 5x^2 + 10

As we can see, the equation does not simplify to the original equation, so this is not the correct option.

Option C: y=5x2+10-y = 5x^2 + 10

Now, let's analyze the third option, y=5x2+10-y = 5x^2 + 10. To determine if this is the correct equation, we need to substitute y=5x2+10y = 5x^2 + 10 into the equation and see if we get the original equation.

-y = 5x^2 + 10
-(5x^2 + 10) = 5x^2 + 10
-5x^2 - 10 = 5x^2 + 10

As we can see, the equation does not simplify to the original equation, so this is not the correct option.

Option D: y=15x2+110y = \frac{1}{5}x^2 + \frac{1}{10}

Now, let's analyze the fourth option, y=15x2+110y = \frac{1}{5}x^2 + \frac{1}{10}. To determine if this is the correct equation, we need to substitute y=5x2+10y = 5x^2 + 10 into the equation and see if we get the original equation.

y = \frac{1}{5}x^2 + \frac{1}{10}
5x^2 + 10 = \frac{1}{5}x^2 + \frac{1}{10}

As we can see, the equation does not simplify to the original equation, so this is not the correct option.

Conclusion

After analyzing all the options, we can conclude that none of the given equations can be simplified to find the inverse of the given quadratic equation y=5x2+10y = 5x^2 + 10. However, we can try to find the inverse by using a different approach.

Finding the Inverse Using a Different Approach

To find the inverse of the given equation, we can start by isolating the term with xx.

y = 5x^2 + 10
x^2 = \frac{y - 10}{5}
x = \pm \sqrt{\frac{y - 10}{5}}

As we can see, the inverse of the given equation is x=±y105x = \pm \sqrt{\frac{y - 10}{5}}. This is the correct equation, and it can be verified by substituting y=5x2+10y = 5x^2 + 10 into the equation.

Conclusion

In conclusion, we have found the inverse of the given quadratic equation y=5x2+10y = 5x^2 + 10 using a different approach. The inverse is x=±y105x = \pm \sqrt{\frac{y - 10}{5}}, and it can be verified by substituting y=5x2+10y = 5x^2 + 10 into the equation. This demonstrates that the inverse of a quadratic equation can be found using various methods, and it is essential to understand the concept of inverse functions to solve problems in mathematics and other fields.

Final Answer

The final answer is: x=±y105\boxed{x = \pm \sqrt{\frac{y - 10}{5}}}

Introduction

In our previous article, we discussed how to find the inverse of a quadratic equation, specifically the equation y=5x2+10y = 5x^2 + 10. We also explored the different options and determined which equation can be simplified to find the inverse of the given quadratic equation. In this article, we will answer some frequently asked questions related to the inverse of a quadratic equation.

Q: What is the inverse of a quadratic equation?

A: The inverse of a quadratic equation is a function that undoes the action of the original function. In other words, if we have a function f(x)f(x), its inverse function f1(x)f^{-1}(x) will take the output of f(x)f(x) and return the original input.

Q: How do I find the inverse of a quadratic equation?

A: To find the inverse of a quadratic equation, you need to isolate the term with xx and then express it in terms of yy. You can use various methods, such as substitution or elimination, to find the inverse.

Q: What is the formula for the inverse of a quadratic equation?

A: The formula for the inverse of a quadratic equation is x=±ykax = \pm \sqrt{\frac{y - k}{a}}, where aa is the coefficient of the squared term and kk is the constant term.

Q: Can I use a calculator to find the inverse of a quadratic equation?

A: Yes, you can use a calculator to find the inverse of a quadratic equation. Most graphing calculators have a built-in function to find the inverse of a function.

Q: How do I graph the inverse of a quadratic equation?

A: To graph the inverse of a quadratic equation, you need to use a graphing calculator or a computer program. You can also use a graphing tool online to visualize the graph of the inverse function.

Q: What is the difference between the inverse of a quadratic equation and the reciprocal of a quadratic equation?

A: The inverse of a quadratic equation is a function that undoes the action of the original function, while the reciprocal of a quadratic equation is a function that takes the reciprocal of the original function.

Q: Can I use the inverse of a quadratic equation to solve a system of equations?

A: Yes, you can use the inverse of a quadratic equation to solve a system of equations. By using the inverse function, you can isolate one variable and then substitute it into the other equation to solve for the other variable.

Q: How do I use the inverse of a quadratic equation to solve a quadratic equation?

A: To use the inverse of a quadratic equation to solve a quadratic equation, you need to first find the inverse of the quadratic equation and then substitute the given values into the inverse function to solve for the variable.

Conclusion

In conclusion, we have answered some frequently asked questions related to the inverse of a quadratic equation. We hope that this article has provided you with a better understanding of the concept of inverse functions and how to use them to solve problems in mathematics and other fields.

Final Answer

The final answer is: x=±yka\boxed{x = \pm \sqrt{\frac{y - k}{a}}}