What Is The $y$-intercept Of The Function $f(x) = 4 - 5x$?A. $-5$ B. $-4$ C. $4$ D. $5$

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**What is the $y$-intercept of the function $f(x) = 4 - 5x$?**

Understanding the $y$-intercept

The $y$-intercept of a function is the point at which the graph of the function intersects the $y$-axis. In other words, it is the value of $y$ when $x$ is equal to zero. To find the $y$-intercept of a linear function, we can substitute $x = 0$ into the equation of the function.

Finding the $y$-intercept of $f(x) = 4 - 5x$

To find the $y$-intercept of the function $f(x) = 4 - 5x$, we can substitute $x = 0$ into the equation.

f(x)=4βˆ’5xf(x) = 4 - 5x

f(0)=4βˆ’5(0)f(0) = 4 - 5(0)

f(0)=4βˆ’0f(0) = 4 - 0

f(0)=4f(0) = 4

Therefore, the $y$-intercept of the function $f(x) = 4 - 5x$ is $4$.

Q&A

Q: What is the $y$-intercept of the function $f(x) = 2x + 3$?

A: To find the $y$-intercept of the function $f(x) = 2x + 3$, we can substitute $x = 0$ into the equation.

f(x)=2x+3f(x) = 2x + 3

f(0)=2(0)+3f(0) = 2(0) + 3

f(0)=0+3f(0) = 0 + 3

f(0)=3f(0) = 3

Therefore, the $y$-intercept of the function $f(x) = 2x + 3$ is $3$.

Q: What is the $y$-intercept of the function $f(x) = -x + 2$?

A: To find the $y$-intercept of the function $f(x) = -x + 2$, we can substitute $x = 0$ into the equation.

f(x)=βˆ’x+2f(x) = -x + 2

f(0)=βˆ’0+2f(0) = -0 + 2

f(0)=0+2f(0) = 0 + 2

f(0)=2f(0) = 2

Therefore, the $y$-intercept of the function $f(x) = -x + 2$ is $2$.

Q: What is the $y$-intercept of the function $f(x) = x - 4$?

A: To find the $y$-intercept of the function $f(x) = x - 4$, we can substitute $x = 0$ into the equation.

f(x)=xβˆ’4f(x) = x - 4

f(0)=0βˆ’4f(0) = 0 - 4

f(0)=βˆ’4f(0) = -4

Therefore, the $y$-intercept of the function $f(x) = x - 4$ is $-4$.

Q: What is the $y$-intercept of the function $f(x) = 3x - 2$?

A: To find the $y$-intercept of the function $f(x) = 3x - 2$, we can substitute $x = 0$ into the equation.

f(x)=3xβˆ’2f(x) = 3x - 2

f(0)=3(0)βˆ’2f(0) = 3(0) - 2

f(0)=0βˆ’2f(0) = 0 - 2

f(0)=βˆ’2f(0) = -2

Therefore, the $y$-intercept of the function $f(x) = 3x - 2$ is $-2$.

Q: What is the $y$-intercept of the function $f(x) = 2x^2 + 3x - 1$?

A: To find the $y$-intercept of the function $f(x) = 2x^2 + 3x - 1$, we can substitute $x = 0$ into the equation.

f(x)=2x2+3xβˆ’1f(x) = 2x^2 + 3x - 1

f(0)=2(0)2+3(0)βˆ’1f(0) = 2(0)^2 + 3(0) - 1

f(0)=0+0βˆ’1f(0) = 0 + 0 - 1

f(0)=βˆ’1f(0) = -1

Therefore, the $y$-intercept of the function $f(x) = 2x^2 + 3x - 1$ is $-1$.

Q: What is the $y$-intercept of the function $f(x) = x^2 - 4x + 3$?

A: To find the $y$-intercept of the function $f(x) = x^2 - 4x + 3$, we can substitute $x = 0$ into the equation.

f(x)=x2βˆ’4x+3f(x) = x^2 - 4x + 3

f(0)=(0)2βˆ’4(0)+3f(0) = (0)^2 - 4(0) + 3

f(0)=0βˆ’0+3f(0) = 0 - 0 + 3

f(0)=3f(0) = 3

Therefore, the $y$-intercept of the function $f(x) = x^2 - 4x + 3$ is $3$.

Q: What is the $y$-intercept of the function $f(x) = x^2 + 2x - 3$?

A: To find the $y$-intercept of the function $f(x) = x^2 + 2x - 3$, we can substitute $x = 0$ into the equation.

f(x)=x2+2xβˆ’3f(x) = x^2 + 2x - 3

f(0)=(0)2+2(0)βˆ’3f(0) = (0)^2 + 2(0) - 3

f(0)=0+0βˆ’3f(0) = 0 + 0 - 3

f(0)=βˆ’3f(0) = -3

Therefore, the $y$-intercept of the function $f(x) = x^2 + 2x - 3$ is $-3$.

Q: What is the $y$-intercept of the function $f(x) = x^2 - 2x - 3$?

A: To find the $y$-intercept of the function $f(x) = x^2 - 2x - 3$, we can substitute $x = 0$ into the equation.

f(x)=x2βˆ’2xβˆ’3f(x) = x^2 - 2x - 3

f(0)=(0)2βˆ’2(0)βˆ’3f(0) = (0)^2 - 2(0) - 3

f(0)=0βˆ’0βˆ’3f(0) = 0 - 0 - 3

f(0)=βˆ’3f(0) = -3

Therefore, the $y$-intercept of the function $f(x) = x^2 - 2x - 3$ is $-3$.

Q: What is the $y$-intercept of the function $f(x) = x^2 + 4x + 4$?

A: To find the $y$-intercept of the function $f(x) = x^2 + 4x + 4$, we can substitute $x = 0$ into the equation.

f(x)=x2+4x+4f(x) = x^2 + 4x + 4

f(0)=(0)2+4(0)+4f(0) = (0)^2 + 4(0) + 4

f(0)=0+0+4f(0) = 0 + 0 + 4

f(0)=4f(0) = 4

Therefore, the $y$-intercept of the function $f(x) = x^2 + 4x + 4$ is $4$.

Q: What is the $y$-intercept of the function $f(x) = x^2 - 4x + 4$?

A: To find the $y$-intercept of the function $f(x) = x^2 - 4x + 4$, we can substitute $x = 0$ into the equation.

f(x)=x2βˆ’4x+4f(x) = x^2 - 4x + 4

f(0)=(0)2βˆ’4(0)+4f(0) = (0)^2 - 4(0) + 4

f(0)=0βˆ’0+4f(0) = 0 - 0 + 4

f(0)=4f(0) = 4

Therefore, the $y$-intercept of the function $f(x) = x^2 - 4x + 4$ is $4$.

Q: What is the $y$-intercept of the function $f(x) = x^2 + 2x + 1$?

A: To find the $y$-intercept of the function $f(x) = x^2 + 2x + 1$, we can substitute $x = 0$ into the equation.

f(x)=x2+2x+1f(x) = x^2 + 2x + 1

f(0)=(0)2+2(0)+1f(0) = (0)^2 + 2(0) + 1

f(0)=0+0+1f(0) = 0 + 0 + 1

f(0)=1f(0) = 1

Therefore, the $y$-intercept of the function $f(x) = x^2 + 2x + 1$