What Is The Velocity Of A Quarter Dropped From A Tower After 10 Seconds?$\[ a = V_i - V_0 \\]

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Introduction

In physics, the study of motion is a fundamental concept that helps us understand how objects move and respond to forces. One of the most basic types of motion is free fall, where an object falls under the sole influence of gravity. In this article, we will explore the velocity of a quarter dropped from a tower after 10 seconds. We will use the equations of motion to calculate the velocity of the quarter and provide a step-by-step guide on how to solve this problem.

Equations of Motion

The equations of motion are a set of mathematical equations that describe the motion of an object. The most commonly used equations are:

  • Equation of Motion 1: s=s0+v0t+12at2s = s_0 + v_0t + \frac{1}{2}at^2
  • Equation of Motion 2: v=v0+atv = v_0 + at
  • Equation of Motion 3: a=Fma = \frac{F}{m}

where:

  • ss is the final position of the object
  • s0s_0 is the initial position of the object
  • v0v_0 is the initial velocity of the object
  • vv is the final velocity of the object
  • aa is the acceleration of the object
  • FF is the net force acting on the object
  • mm is the mass of the object

Free Fall

In the case of free fall, the only force acting on the object is gravity. The acceleration due to gravity is denoted by gg and is approximately equal to 9.8 m/s29.8 \, \text{m/s}^2. Since the quarter is dropped from rest, the initial velocity v0v_0 is equal to zero.

Calculating the Velocity of the Quarter

To calculate the velocity of the quarter after 10 seconds, we can use Equation of Motion 2: v=v0+atv = v_0 + at. Since the quarter is under the sole influence of gravity, the acceleration aa is equal to gg. Plugging in the values, we get:

v=0+(9.8 m/s2)(10 s)v = 0 + (9.8 \, \text{m/s}^2)(10 \, \text{s})

v=98 m/sv = 98 \, \text{m/s}

Therefore, the velocity of the quarter after 10 seconds is 98 m/s98 \, \text{m/s}.

Calculating the Position of the Quarter

To calculate the position of the quarter after 10 seconds, we can use Equation of Motion 1: s=s0+v0t+12at2s = s_0 + v_0t + \frac{1}{2}at^2. Since the quarter is dropped from rest, the initial velocity v0v_0 is equal to zero. Plugging in the values, we get:

s=0+0(10 s)+12(9.8 m/s2)(10 s)2s = 0 + 0(10 \, \text{s}) + \frac{1}{2}(9.8 \, \text{m/s}^2)(10 \, \text{s})^2

s=490 ms = 490 \, \text{m}

Therefore, the position of the quarter after 10 seconds is 490 m490 \, \text{m}.

Conclusion

In this article, we calculated the velocity and position of a quarter dropped from a tower after 10 seconds. We used the equations of motion to solve this problem and provided a step-by-step guide on how to calculate the velocity and position of an object under the sole influence of gravity. The velocity of the quarter after 10 seconds is 98 m/s98 \, \text{m/s}, and the position of the quarter after 10 seconds is 490 m490 \, \text{m}.

References

  • Halliday, D., Resnick, R., & Walker, J. (2013). Fundamentals of Physics (10th ed.). John Wiley & Sons.
  • Serway, R. A., & Jewett, J. W. (2018). Physics for Scientists and Engineers (10th ed.). Cengage Learning.

Additional Resources

  • Khan Academy: Free Fall - A video tutorial on free fall and the equations of motion.
  • Physics Classroom: Free Fall - A tutorial on free fall and the equations of motion.
  • Wolfram Alpha: Free Fall - A calculator that can be used to calculate the velocity and position of an object under the sole influence of gravity.
    What is the Velocity of a Quarter Dropped from a Tower After 10 Seconds? - Q&A ====================================================================

Introduction

In our previous article, we calculated the velocity and position of a quarter dropped from a tower after 10 seconds. In this article, we will answer some frequently asked questions related to this topic.

Q: What is the acceleration due to gravity?

A: The acceleration due to gravity is denoted by gg and is approximately equal to 9.8 m/s29.8 \, \text{m/s}^2.

Q: What is the initial velocity of the quarter?

A: Since the quarter is dropped from rest, the initial velocity v0v_0 is equal to zero.

Q: How do I calculate the velocity of the quarter after 10 seconds?

A: To calculate the velocity of the quarter after 10 seconds, you can use Equation of Motion 2: v=v0+atv = v_0 + at. Plugging in the values, you get:

v=0+(9.8 m/s2)(10 s)v = 0 + (9.8 \, \text{m/s}^2)(10 \, \text{s})

v=98 m/sv = 98 \, \text{m/s}

Q: How do I calculate the position of the quarter after 10 seconds?

A: To calculate the position of the quarter after 10 seconds, you can use Equation of Motion 1: s=s0+v0t+12at2s = s_0 + v_0t + \frac{1}{2}at^2. Plugging in the values, you get:

s=0+0(10 s)+12(9.8 m/s2)(10 s)2s = 0 + 0(10 \, \text{s}) + \frac{1}{2}(9.8 \, \text{m/s}^2)(10 \, \text{s})^2

s=490 ms = 490 \, \text{m}

Q: What is the difference between velocity and position?

A: Velocity is a measure of an object's speed in a specific direction, while position is a measure of an object's location in space.

Q: Can I use the equations of motion to calculate the velocity and position of an object under the influence of other forces?

A: Yes, you can use the equations of motion to calculate the velocity and position of an object under the influence of other forces. However, you will need to take into account the net force acting on the object and the mass of the object.

Q: What are some real-world applications of the equations of motion?

A: The equations of motion have many real-world applications, including:

  • Projectile motion: The equations of motion can be used to calculate the trajectory of a projectile, such as a thrown ball or a launched rocket.
  • Free fall: The equations of motion can be used to calculate the velocity and position of an object under the sole influence of gravity.
  • Motion under constant acceleration: The equations of motion can be used to calculate the velocity and position of an object under the influence of a constant acceleration, such as an object moving on a straight line.

Conclusion

In this article, we answered some frequently asked questions related to the velocity and position of a quarter dropped from a tower after 10 seconds. We also discussed the equations of motion and their real-world applications. We hope that this article has been helpful in understanding the concepts of velocity and position.

References

  • Halliday, D., Resnick, R., & Walker, J. (2013). Fundamentals of Physics (10th ed.). John Wiley & Sons.
  • Serway, R. A., & Jewett, J. W. (2018). Physics for Scientists and Engineers (10th ed.). Cengage Learning.

Additional Resources

  • Khan Academy: Free Fall - A video tutorial on free fall and the equations of motion.
  • Physics Classroom: Free Fall - A tutorial on free fall and the equations of motion.
  • Wolfram Alpha: Free Fall - A calculator that can be used to calculate the velocity and position of an object under the sole influence of gravity.