What Is The Value Of $\log_a\left(\frac{x Z^2}{y^{-2}}\right$\] When Given The Following Values?$\[ \begin{align*} \log_a(x) &= 2 \\ \log_a(y) &= 3 \\ \log_a(z) &= 4 \end{align*} \\]

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Introduction

In this article, we will explore the concept of logarithms and how to evaluate expressions involving logarithms. We will use the given values of loga(x)\log_a(x), loga(y)\log_a(y), and loga(z)\log_a(z) to find the value of loga(xz2y2)\log_a\left(\frac{x z^2}{y^{-2}}\right). This problem requires a deep understanding of logarithmic properties and how to apply them to evaluate complex expressions.

Understanding Logarithmic Properties

Before we dive into the problem, let's review some essential logarithmic properties:

  • Product Rule: loga(MN)=loga(M)+loga(N)\log_a(MN) = \log_a(M) + \log_a(N)
  • Quotient Rule: loga(MN)=loga(M)loga(N)\log_a\left(\frac{M}{N}\right) = \log_a(M) - \log_a(N)
  • Power Rule: loga(Mp)=ploga(M)\log_a(M^p) = p \log_a(M)

These properties will be crucial in evaluating the given expression.

Evaluating the Expression

Now, let's evaluate the expression loga(xz2y2)\log_a\left(\frac{x z^2}{y^{-2}}\right) using the given values of loga(x)\log_a(x), loga(y)\log_a(y), and loga(z)\log_a(z).

We can start by applying the Quotient Rule:

loga(xz2y2)=loga(xz2)loga(y2)\log_a\left(\frac{x z^2}{y^{-2}}\right) = \log_a(x z^2) - \log_a(y^{-2})

Next, we can apply the Product Rule to the first term:

loga(xz2)=loga(x)+loga(z2)\log_a(x z^2) = \log_a(x) + \log_a(z^2)

Now, we can apply the Power Rule to the second term:

loga(z2)=2loga(z)\log_a(z^2) = 2 \log_a(z)

Substituting the given values, we get:

loga(xz2)=2+2(4)=10\log_a(x z^2) = 2 + 2(4) = 10

Now, let's evaluate the second term:

loga(y2)=2loga(y)\log_a(y^{-2}) = -2 \log_a(y)

Substituting the given value, we get:

loga(y2)=2(3)=6\log_a(y^{-2}) = -2(3) = -6

Now, we can substitute these values back into the original expression:

loga(xz2y2)=10(6)=16\log_a\left(\frac{x z^2}{y^{-2}}\right) = 10 - (-6) = 16

Conclusion

In this article, we evaluated the expression loga(xz2y2)\log_a\left(\frac{x z^2}{y^{-2}}\right) using the given values of loga(x)\log_a(x), loga(y)\log_a(y), and loga(z)\log_a(z). We applied the Quotient Rule, Product Rule, and Power Rule to simplify the expression and find its value. The final answer is 16\boxed{16}.

Frequently Asked Questions

  • What is the value of loga(x)\log_a(x), loga(y)\log_a(y), and loga(z)\log_a(z)?
    • loga(x)=2\log_a(x) = 2
    • loga(y)=3\log_a(y) = 3
    • loga(z)=4\log_a(z) = 4
  • How do you evaluate the expression loga(xz2y2)\log_a\left(\frac{x z^2}{y^{-2}}\right)?
    • Apply the Quotient Rule, Product Rule, and Power Rule to simplify the expression.
  • What is the final answer?
    • 16\boxed{16}

Related Topics

  • Logarithmic properties
  • Evaluating expressions involving logarithms
  • Logarithmic functions

References

  • [1] "Logarithmic Properties" by Math Open Reference
  • [2] "Evaluating Expressions Involving Logarithms" by Khan Academy
  • [3] "Logarithmic Functions" by Wolfram MathWorld

Introduction

In our previous article, we explored the concept of logarithmic expressions and how to evaluate them using the given values of loga(x)\log_a(x), loga(y)\log_a(y), and loga(z)\log_a(z). In this article, we will address some of the most frequently asked questions related to logarithmic expressions.

Q&A

Q1: What is the value of loga(x)\log_a(x), loga(y)\log_a(y), and loga(z)\log_a(z)?

A1: The values of loga(x)\log_a(x), loga(y)\log_a(y), and loga(z)\log_a(z) are given as:

  • loga(x)=2\log_a(x) = 2
  • loga(y)=3\log_a(y) = 3
  • loga(z)=4\log_a(z) = 4

Q2: How do you evaluate the expression loga(xz2y2)\log_a\left(\frac{x z^2}{y^{-2}}\right)?

A2: To evaluate the expression loga(xz2y2)\log_a\left(\frac{x z^2}{y^{-2}}\right), you need to apply the following logarithmic properties:

  • Quotient Rule: loga(MN)=loga(M)loga(N)\log_a\left(\frac{M}{N}\right) = \log_a(M) - \log_a(N)
  • Product Rule: loga(MN)=loga(M)+loga(N)\log_a(MN) = \log_a(M) + \log_a(N)
  • Power Rule: loga(Mp)=ploga(M)\log_a(M^p) = p \log_a(M)

Q3: What is the final answer to the expression loga(xz2y2)\log_a\left(\frac{x z^2}{y^{-2}}\right)?

A3: The final answer to the expression loga(xz2y2)\log_a\left(\frac{x z^2}{y^{-2}}\right) is 16\boxed{16}.

Q4: How do you apply the Quotient Rule to the expression loga(xz2y2)\log_a\left(\frac{x z^2}{y^{-2}}\right)?

A4: To apply the Quotient Rule, you need to subtract the logarithm of the denominator from the logarithm of the numerator:

loga(xz2y2)=loga(xz2)loga(y2)\log_a\left(\frac{x z^2}{y^{-2}}\right) = \log_a(x z^2) - \log_a(y^{-2})

Q5: How do you apply the Product Rule to the expression loga(xz2)\log_a(x z^2)?

A5: To apply the Product Rule, you need to add the logarithms of the two factors:

loga(xz2)=loga(x)+loga(z2)\log_a(x z^2) = \log_a(x) + \log_a(z^2)

Q6: How do you apply the Power Rule to the expression loga(z2)\log_a(z^2)?

A6: To apply the Power Rule, you need to multiply the logarithm of the base by the exponent:

loga(z2)=2loga(z)\log_a(z^2) = 2 \log_a(z)

Q7: What is the value of loga(y2)\log_a(y^{-2})?

A7: The value of loga(y2)\log_a(y^{-2}) is 2loga(y)-2 \log_a(y).

Q8: How do you substitute the values of loga(x)\log_a(x), loga(y)\log_a(y), and loga(z)\log_a(z) into the expression?

A8: To substitute the values, you need to replace the variables with their corresponding values:

loga(xz2)=2+2(4)=10\log_a(x z^2) = 2 + 2(4) = 10

loga(y2)=2(3)=6\log_a(y^{-2}) = -2(3) = -6

Q9: What is the final answer after substituting the values?

A9: The final answer after substituting the values is 16\boxed{16}.

Conclusion

In this article, we addressed some of the most frequently asked questions related to logarithmic expressions. We provided step-by-step explanations and examples to help you understand the concepts and apply them to evaluate logarithmic expressions.

Related Topics

  • Logarithmic properties
  • Evaluating expressions involving logarithms
  • Logarithmic functions

References

  • [1] "Logarithmic Properties" by Math Open Reference
  • [2] "Evaluating Expressions Involving Logarithms" by Khan Academy
  • [3] "Logarithmic Functions" by Wolfram MathWorld