What Is The Sum Of The Polynomials?$\[ \begin{array}{r} 17m - 12n - 1 \\ + \quad 4 - 13m - 12n \\ \hline \end{array} \\]A. \[$4m + 3\$\]B. \[$4m - 24n + 3\$\]C. \[$30m - 5\$\]D. \[$30m - 24n - 5\$\]

by ADMIN 199 views

Understanding Polynomials and Their Operations

Polynomials are algebraic expressions consisting of variables and coefficients combined using only addition, subtraction, and multiplication. In this article, we will explore the concept of summing polynomials, which involves combining two or more polynomials using addition and subtraction operations.

The Basics of Polynomial Addition and Subtraction

When adding or subtracting polynomials, we combine like terms, which are terms that have the same variable(s) raised to the same power. For example, in the polynomial 3x2+2xβˆ’13x^2 + 2x - 1, the terms 3x23x^2 and 2x2x are like terms because they both have the variable xx raised to the power of 2.

The Problem: Summing Two Polynomials

Let's consider the problem of summing the two polynomials:

17mβˆ’12nβˆ’1+4βˆ’13mβˆ’12n\begin{array}{r} 17m - 12n - 1 \\ + \quad 4 - 13m - 12n \\ \hline \end{array}

To find the sum of these polynomials, we need to combine like terms. We can start by adding the coefficients of the like terms.

Step 1: Combine Like Terms

The first polynomial has the term 17m17m, and the second polynomial has the term βˆ’13m-13m. We can combine these two terms by adding their coefficients:

17m+(βˆ’13m)=4m17m + (-13m) = 4m

The first polynomial also has the term βˆ’12n-12n, and the second polynomial has the term βˆ’12n-12n. We can combine these two terms by adding their coefficients:

βˆ’12n+(βˆ’12n)=βˆ’24n-12n + (-12n) = -24n

The first polynomial has a constant term of βˆ’1-1, and the second polynomial has a constant term of 44. We can combine these two terms by adding them:

βˆ’1+4=3-1 + 4 = 3

Step 2: Write the Sum of the Polynomials

Now that we have combined the like terms, we can write the sum of the polynomials:

4mβˆ’24n+34m - 24n + 3

Conclusion

In this article, we explored the concept of summing polynomials and applied it to a specific problem. We learned how to combine like terms and write the sum of two polynomials. The correct answer to the problem is:

4mβˆ’24n+34m - 24n + 3

This is option B in the given choices.

Key Takeaways

  • Polynomials are algebraic expressions consisting of variables and coefficients combined using only addition, subtraction, and multiplication.
  • When adding or subtracting polynomials, we combine like terms, which are terms that have the same variable(s) raised to the same power.
  • To find the sum of two polynomials, we need to combine like terms by adding their coefficients.
  • The sum of two polynomials can be written by combining the like terms and writing the resulting expression.

Frequently Asked Questions

  • What is the sum of the polynomials 17mβˆ’12nβˆ’117m - 12n - 1 and 4βˆ’13mβˆ’12n4 - 13m - 12n?
    • The sum of the polynomials is 4mβˆ’24n+34m - 24n + 3.
  • How do we combine like terms in polynomials?
    • We combine like terms by adding their coefficients.
  • What is the result of combining the terms 17m17m and βˆ’13m-13m?
    • The result is 4m4m.
  • What is the result of combining the terms βˆ’12n-12n and βˆ’12n-12n?
    • The result is βˆ’24n-24n.

References

Frequently Asked Questions

Q: What is the sum of the polynomials 17mβˆ’12nβˆ’117m - 12n - 1 and 4βˆ’13mβˆ’12n4 - 13m - 12n?

A: The sum of the polynomials is 4mβˆ’24n+34m - 24n + 3.

Q: How do we combine like terms in polynomials?

A: We combine like terms by adding their coefficients.

Q: What is the result of combining the terms 17m17m and βˆ’13m-13m?

A: The result is 4m4m.

Q: What is the result of combining the terms βˆ’12n-12n and βˆ’12n-12n?

A: The result is βˆ’24n-24n.

Q: Can we add polynomials with different variables?

A: No, we can only add polynomials with the same variables raised to the same power.

Q: How do we subtract polynomials?

A: To subtract a polynomial, we change the sign of each term in the polynomial and then add the resulting polynomials.

Q: What is the sum of the polynomials 2x2+3xβˆ’12x^2 + 3x - 1 and x2βˆ’2x+3x^2 - 2x + 3?

A: To find the sum, we combine like terms:

  • 2x2+x2=3x22x^2 + x^2 = 3x^2
  • 3xβˆ’2x=x3x - 2x = x
  • βˆ’1+3=2-1 + 3 = 2

The sum of the polynomials is 3x2+x+23x^2 + x + 2.

Q: What is the difference between the polynomials 2x2+3xβˆ’12x^2 + 3x - 1 and x2βˆ’2x+3x^2 - 2x + 3?

A: To find the difference, we change the sign of each term in the second polynomial and then add the resulting polynomials:

  • 2x2+x2=3x22x^2 + x^2 = 3x^2
  • 3x+2x=5x3x + 2x = 5x
  • βˆ’1βˆ’3=βˆ’4-1 - 3 = -4

The difference between the polynomials is 3x2+5xβˆ’43x^2 + 5x - 4.

Q: Can we multiply polynomials?

A: Yes, we can multiply polynomials using the distributive property.

Q: What is the product of the polynomials 2x2+3xβˆ’12x^2 + 3x - 1 and x2βˆ’2x+3x^2 - 2x + 3?

A: To find the product, we multiply each term in the first polynomial by each term in the second polynomial and then combine like terms:

  • (2x2)(x2)=2x4(2x^2)(x^2) = 2x^4
  • (2x2)(βˆ’2x)=βˆ’4x3(2x^2)(-2x) = -4x^3
  • (2x2)(3)=6x2(2x^2)(3) = 6x^2
  • (3x)(x2)=3x3(3x)(x^2) = 3x^3
  • (3x)(βˆ’2x)=βˆ’6x2(3x)(-2x) = -6x^2
  • (3x)(3)=9x(3x)(3) = 9x
  • (βˆ’1)(x2)=βˆ’x2(-1)(x^2) = -x^2
  • (βˆ’1)(βˆ’2x)=2x(-1)(-2x) = 2x
  • (βˆ’1)(3)=βˆ’3(-1)(3) = -3

Combining like terms, we get:

  • 2x4βˆ’4x3+6x2+3x3βˆ’6x2+9xβˆ’x2+2xβˆ’32x^4 - 4x^3 + 6x^2 + 3x^3 - 6x^2 + 9x - x^2 + 2x - 3
  • 2x4βˆ’x3+9xβˆ’32x^4 - x^3 + 9x - 3

The product of the polynomials is 2x4βˆ’x3+9xβˆ’32x^4 - x^3 + 9x - 3.

Q: Can we divide polynomials?

A: Yes, we can divide polynomials using long division or synthetic division.

Q: What is the quotient of the polynomials 2x3+3x2βˆ’12x^3 + 3x^2 - 1 and x+2x + 2?

A: To find the quotient, we use long division:

  • Divide 2x32x^3 by xx to get 2x22x^2
  • Multiply x+2x + 2 by 2x22x^2 to get 2x3+4x22x^3 + 4x^2
  • Subtract 2x3+4x22x^3 + 4x^2 from 2x3+3x2βˆ’12x^3 + 3x^2 - 1 to get βˆ’x2βˆ’1-x^2 - 1
  • Divide βˆ’x2-x^2 by xx to get βˆ’x-x
  • Multiply x+2x + 2 by βˆ’x-x to get βˆ’x2βˆ’2x-x^2 - 2x
  • Subtract βˆ’x2βˆ’2x-x^2 - 2x from βˆ’x2βˆ’1-x^2 - 1 to get 2xβˆ’12x - 1
  • Divide 2x2x by xx to get 22
  • Multiply x+2x + 2 by 22 to get 2x+42x + 4
  • Subtract 2x+42x + 4 from 2xβˆ’12x - 1 to get βˆ’5-5

The quotient of the polynomials is 2x2βˆ’x+22x^2 - x + 2 with a remainder of βˆ’5-5.

Q: What is the remainder of the polynomials 2x3+3x2βˆ’12x^3 + 3x^2 - 1 and x+2x + 2?

A: The remainder is βˆ’5-5.

Q: Can we simplify polynomials?

A: Yes, we can simplify polynomials by combining like terms and factoring out common factors.

Q: What is the simplified form of the polynomial 2x3+3x2βˆ’12x^3 + 3x^2 - 1?

A: We can simplify the polynomial by combining like terms:

  • 2x3+3x2βˆ’1=2x3+3x2βˆ’12x^3 + 3x^2 - 1 = 2x^3 + 3x^2 - 1

However, we can factor out a common factor of x2x^2:

  • 2x3+3x2βˆ’1=x2(2x+3)βˆ’12x^3 + 3x^2 - 1 = x^2(2x + 3) - 1

The simplified form of the polynomial is x2(2x+3)βˆ’1x^2(2x + 3) - 1.