What Is The Percent By Mass Of Potassium In K 3 F E ( C N ) 6 K _3 Fe ( CN )_6 K 3 ​ F E ( CN ) 6 ​ ? Use % Element = Total mass of element in compound Molar mass of compound × 100 \% \text{ Element } = \frac{\text{total Mass Of Element In Compound}}{\text{molar Mass Of Compound}} \times 100 % Element = Molar mass of compound Total mass of element in compound ​ × 100 .A. 16.96%B. 21.88%C. 25.53%D. 35.62%

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What is the Percent by Mass of Potassium in K3Fe(CN)6K _3 Fe ( CN )_6?

The percent by mass of an element in a compound is a measure of the mass of that element in the compound relative to the total mass of the compound. It is an important concept in chemistry, as it allows us to understand the composition of a compound and how it relates to its properties.

To calculate the percent by mass of an element in a compound, we can use the following formula:

% Element =total mass of element in compoundmolar mass of compound×100\% \text{ Element } = \frac{\text{total mass of element in compound}}{\text{molar mass of compound}} \times 100

In this formula, the total mass of the element in the compound is the sum of the masses of all the atoms of that element in the compound, and the molar mass of the compound is the sum of the masses of all the atoms in the compound.

Calculating the Molar Mass of K3Fe(CN)6K _3 Fe ( CN )_6

To calculate the percent by mass of potassium in K3Fe(CN)6K _3 Fe ( CN )_6, we first need to calculate the molar mass of the compound. The molar mass of a compound is the sum of the masses of all the atoms in the compound.

The molar mass of K3Fe(CN)6K _3 Fe ( CN )_6 can be calculated as follows:

  • The molar mass of potassium (K) is 39.09 g/mol.
  • The molar mass of iron (Fe) is 55.85 g/mol.
  • The molar mass of carbon (C) is 12.01 g/mol.
  • The molar mass of nitrogen (N) is 14.01 g/mol.

The formula for K3Fe(CN)6K _3 Fe ( CN )_6 indicates that there are 3 potassium atoms, 1 iron atom, 6 carbon atoms, and 6 nitrogen atoms in the compound.

Therefore, the molar mass of K3Fe(CN)6K _3 Fe ( CN )_6 is:

3(39.09)+55.85+6(12.01)+6(14.01)=116.27+55.85+72.06+84.06=328.243(39.09) + 55.85 + 6(12.01) + 6(14.01) = 116.27 + 55.85 + 72.06 + 84.06 = 328.24 g/mol

Calculating the Percent by Mass of Potassium in K3Fe(CN)6K _3 Fe ( CN )_6

Now that we have calculated the molar mass of K3Fe(CN)6K _3 Fe ( CN )_6, we can calculate the percent by mass of potassium in the compound.

The total mass of potassium in the compound is 3 times the molar mass of potassium, which is:

3(39.09)=117.273(39.09) = 117.27 g

The percent by mass of potassium in the compound is then:

% Potassium =117.27328.24×100=35.62%\% \text{ Potassium } = \frac{117.27}{328.24} \times 100 = 35.62\%

Therefore, the percent by mass of potassium in K3Fe(CN)6K _3 Fe ( CN )_6 is 35.62%.

Conclusion

In this article, we have calculated the percent by mass of potassium in K3Fe(CN)6K _3 Fe ( CN )_6 using the formula:

% Element =total mass of element in compoundmolar mass of compound×100\% \text{ Element } = \frac{\text{total mass of element in compound}}{\text{molar mass of compound}} \times 100

We first calculated the molar mass of the compound, and then used this value to calculate the percent by mass of potassium in the compound. The result is 35.62%.

Answer

The correct answer is D. 35.62%.

Discussion

This problem requires the student to understand the concept of percent by mass and how to calculate it using the formula. The student must also be able to calculate the molar mass of the compound and use this value to calculate the percent by mass of the element.

The student should be able to explain why the percent by mass of potassium in K3Fe(CN)6K _3 Fe ( CN )_6 is 35.62%, and how this value relates to the composition of the compound.

Key Concepts

  • Percent by mass
  • Molar mass
  • Composition of a compound

Key Equations

  • % Element =total mass of element in compoundmolar mass of compound×100\% \text{ Element } = \frac{\text{total mass of element in compound}}{\text{molar mass of compound}} \times 100

Key Calculations

  • Molar mass of K3Fe(CN)6K _3 Fe ( CN )_6 = 328.24 g/mol
  • Total mass of potassium in the compound = 117.27 g
  • Percent by mass of potassium in the compound = 35.62%
    Q&A: Percent by Mass of Potassium in K3Fe(CN)6K _3 Fe ( CN )_6

In the previous article, we calculated the percent by mass of potassium in K3Fe(CN)6K _3 Fe ( CN )_6 using the formula:

% Element =total mass of element in compoundmolar mass of compound×100\% \text{ Element } = \frac{\text{total mass of element in compound}}{\text{molar mass of compound}} \times 100

In this article, we will answer some common questions related to this topic.

Q: What is the percent by mass of potassium in K3Fe(CN)6K _3 Fe ( CN )_6?

A: The percent by mass of potassium in K3Fe(CN)6K _3 Fe ( CN )_6 is 35.62%.

Q: How do I calculate the percent by mass of an element in a compound?

A: To calculate the percent by mass of an element in a compound, you can use the formula:

% Element =total mass of element in compoundmolar mass of compound×100\% \text{ Element } = \frac{\text{total mass of element in compound}}{\text{molar mass of compound}} \times 100

Q: What is the molar mass of K3Fe(CN)6K _3 Fe ( CN )_6?

A: The molar mass of K3Fe(CN)6K _3 Fe ( CN )_6 is 328.24 g/mol.

Q: How do I calculate the total mass of an element in a compound?

A: To calculate the total mass of an element in a compound, you need to multiply the molar mass of the element by the number of atoms of that element in the compound.

Q: What is the percent by mass of iron in K3Fe(CN)6K _3 Fe ( CN )_6?

A: To calculate the percent by mass of iron in K3Fe(CN)6K _3 Fe ( CN )_6, you need to calculate the total mass of iron in the compound and divide it by the molar mass of the compound.

The total mass of iron in the compound is:

1(55.85)=55.851(55.85) = 55.85 g

The percent by mass of iron in the compound is then:

% Iron =55.85328.24×100=17.04%\% \text{ Iron } = \frac{55.85}{328.24} \times 100 = 17.04\%

Q: What is the percent by mass of carbon in K3Fe(CN)6K _3 Fe ( CN )_6?

A: To calculate the percent by mass of carbon in K3Fe(CN)6K _3 Fe ( CN )_6, you need to calculate the total mass of carbon in the compound and divide it by the molar mass of the compound.

The total mass of carbon in the compound is:

6(12.01)=72.066(12.01) = 72.06 g

The percent by mass of carbon in the compound is then:

% Carbon =72.06328.24×100=21.94%\% \text{ Carbon } = \frac{72.06}{328.24} \times 100 = 21.94\%

Q: What is the percent by mass of nitrogen in K3Fe(CN)6K _3 Fe ( CN )_6?

A: To calculate the percent by mass of nitrogen in K3Fe(CN)6K _3 Fe ( CN )_6, you need to calculate the total mass of nitrogen in the compound and divide it by the molar mass of the compound.

The total mass of nitrogen in the compound is:

6(14.01)=84.066(14.01) = 84.06 g

The percent by mass of nitrogen in the compound is then:

% Nitrogen =84.06328.24×100=25.53%\% \text{ Nitrogen } = \frac{84.06}{328.24} \times 100 = 25.53\%

Conclusion

In this article, we have answered some common questions related to the percent by mass of potassium in K3Fe(CN)6K _3 Fe ( CN )_6. We have also calculated the percent by mass of iron, carbon, and nitrogen in the compound.

Key Concepts

  • Percent by mass
  • Molar mass
  • Composition of a compound

Key Equations

  • % Element =total mass of element in compoundmolar mass of compound×100\% \text{ Element } = \frac{\text{total mass of element in compound}}{\text{molar mass of compound}} \times 100

Key Calculations

  • Molar mass of K3Fe(CN)6K _3 Fe ( CN )_6 = 328.24 g/mol
  • Total mass of potassium in the compound = 117.27 g
  • Percent by mass of potassium in the compound = 35.62%
  • Total mass of iron in the compound = 55.85 g
  • Percent by mass of iron in the compound = 17.04%
  • Total mass of carbon in the compound = 72.06 g
  • Percent by mass of carbon in the compound = 21.94%
  • Total mass of nitrogen in the compound = 84.06 g
  • Percent by mass of nitrogen in the compound = 25.53%