What Is The Length Of The Major Axis Of The Ellipse Given By The Equation $\frac{x^2}{10} + \frac{y^2}{20} = 1$?

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Introduction

In mathematics, an ellipse is a fundamental concept in geometry and algebra. It is a closed curve on a plane surrounding two focal points such that the sum of the distances to the two focal points is constant. The equation of an ellipse in standard form is given by x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1, where aa and bb are the lengths of the semi-major and semi-minor axes, respectively. In this article, we will discuss how to find the length of the major axis of an ellipse given by the equation x210+y220=1\frac{x^2}{10} + \frac{y^2}{20} = 1.

Understanding the Equation of the Ellipse

The given equation of the ellipse is x210+y220=1\frac{x^2}{10} + \frac{y^2}{20} = 1. To find the length of the major axis, we need to identify the values of aa and bb in the equation. Comparing the given equation with the standard form of the equation of an ellipse, we can see that a2=10a^2 = 10 and b2=20b^2 = 20. Taking the square root of both sides, we get a=10a = \sqrt{10} and b=20b = \sqrt{20}.

Finding the Length of the Major Axis

The length of the major axis of an ellipse is given by 2a2a, where aa is the length of the semi-major axis. Since we have found the value of aa to be 10\sqrt{10}, we can now find the length of the major axis by multiplying aa by 2. Therefore, the length of the major axis of the ellipse given by the equation x210+y220=1\frac{x^2}{10} + \frac{y^2}{20} = 1 is 2102\sqrt{10}.

Simplifying the Answer

To simplify the answer, we can rationalize the denominator by multiplying the numerator and denominator by 10\sqrt{10}. This gives us 2101010=2010\frac{2\sqrt{10}\sqrt{10}}{\sqrt{10}} = \frac{20}{\sqrt{10}}. To further simplify the answer, we can multiply the numerator and denominator by 10\sqrt{10} again. This gives us 20101010=201010=210\frac{20\sqrt{10}}{\sqrt{10}\sqrt{10}} = \frac{20\sqrt{10}}{10} = 2\sqrt{10}.

Conclusion

In conclusion, the length of the major axis of the ellipse given by the equation x210+y220=1\frac{x^2}{10} + \frac{y^2}{20} = 1 is 2102\sqrt{10}. This can be simplified to 2102\sqrt{10}.

Final Answer

The final answer is: 210\boxed{2\sqrt{10}}

Additional Information

  • The length of the semi-major axis is 10\sqrt{10}.
  • The length of the semi-minor axis is 20\sqrt{20}.
  • The equation of the ellipse can be written as x2(10)2+y2(20)2=1\frac{x^2}{(\sqrt{10})^2} + \frac{y^2}{(\sqrt{20})^2} = 1.

References

Related Topics

Tags

  • Ellipse
  • Equation of an Ellipse
  • Length of the Major Axis
  • Length of the Semi-Major Axis
  • Length of the Semi-Minor Axis

Q: What is the equation of an ellipse in standard form?

A: The equation of an ellipse in standard form is given by x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1, where aa and bb are the lengths of the semi-major and semi-minor axes, respectively.

Q: How do I find the length of the major axis of an ellipse?

A: To find the length of the major axis of an ellipse, you need to identify the values of aa and bb in the equation of the ellipse. The length of the major axis is given by 2a2a, where aa is the length of the semi-major axis.

Q: What is the length of the semi-major axis of the ellipse given by the equation x210+y220=1\frac{x^2}{10} + \frac{y^2}{20} = 1?

A: The length of the semi-major axis of the ellipse given by the equation x210+y220=1\frac{x^2}{10} + \frac{y^2}{20} = 1 is 10\sqrt{10}.

Q: What is the length of the semi-minor axis of the ellipse given by the equation x210+y220=1\frac{x^2}{10} + \frac{y^2}{20} = 1?

A: The length of the semi-minor axis of the ellipse given by the equation x210+y220=1\frac{x^2}{10} + \frac{y^2}{20} = 1 is 20\sqrt{20}.

Q: How do I simplify the answer to find the length of the major axis?

A: To simplify the answer, you can rationalize the denominator by multiplying the numerator and denominator by 10\sqrt{10}. This gives you 2101010=2010\frac{2\sqrt{10}\sqrt{10}}{\sqrt{10}} = \frac{20}{\sqrt{10}}. To further simplify the answer, you can multiply the numerator and denominator by 10\sqrt{10} again. This gives you 20101010=201010=210\frac{20\sqrt{10}}{\sqrt{10}\sqrt{10}} = \frac{20\sqrt{10}}{10} = 2\sqrt{10}.

Q: What is the final answer to the problem?

A: The final answer to the problem is 2102\sqrt{10}.

Q: What are some additional information related to the problem?

A: Some additional information related to the problem includes:

  • The length of the semi-major axis is 10\sqrt{10}.
  • The length of the semi-minor axis is 20\sqrt{20}.
  • The equation of the ellipse can be written as x2(10)2+y2(20)2=1\frac{x^2}{(\sqrt{10})^2} + \frac{y^2}{(\sqrt{20})^2} = 1.

Q: What are some related topics to the problem?

A: Some related topics to the problem include:

Q: What are some references related to the problem?

A: Some references related to the problem include:

Q: What are some tags related to the problem?

A: Some tags related to the problem include:

  • Ellipse
  • Equation of an Ellipse
  • Length of the Major Axis
  • Length of the Semi-Major Axis
  • Length of the Semi-Minor Axis