What Is Produced During The Replacement Reaction Of $Ba \left( NO_3 \right)_2$ And $Na_2 SO_4$?A. 2 B A N A + 2 N O 3 S O 4 2 BaNa + 2 NO_3 SO_4 2 B A N A + 2 N O 3 S O 4 B. 2 N A N O 3 + B A S O 4 2 NaNO_3 + BaSO_4 2 N A N O 3 + B A S O 4 C. N A N O 3 + B A S O 4 NaNO_3 + BaSO_4 N A N O 3 + B A S O 4 D. $BaNa_2 + \left( NO_3 \right)_2
What is Produced During the Replacement Reaction of $Ba \left( NO_3 \right)_2$ and $Na_2 SO_4$?
Understanding the Replacement Reaction
A replacement reaction, also known as a double displacement reaction, is a type of chemical reaction where two compounds react to form two new compounds. In this reaction, one element is displaced from one compound by another element from a different compound. The replacement reaction between $Ba \left( NO_3 \right)_2$ and $Na_2 SO_4$ is a classic example of this type of reaction.
The Chemical Equation
The chemical equation for the replacement reaction between $Ba \left( NO_3 \right)_2$ and $Na_2 SO_4$ is:
Breaking Down the Reaction
In this reaction, barium nitrate ($Ba \left( NO_3 \right)_2$) reacts with sodium sulfate ($Na_2 SO_4$) to form barium sulfate ($BaSO_4$) and sodium nitrate ($NaNO_3$). The barium ion (Ba) is displaced from the nitrate ion (NO_3) by the sodium ion (Na) from the sulfate ion (SO_4).
The Products of the Reaction
The two products of this reaction are:
- Barium Sulfate (BaSO_4): This is a white, insoluble solid that is commonly used in medical imaging procedures, such as X-rays and CT scans.
- Sodium Nitrate (NaNO_3): This is a white, crystalline solid that is commonly used in the production of fertilizers, explosives, and other chemicals.
Why is the Correct Answer B?
The correct answer is B, $2 NaNO_3 + BaSO_4$. This is because the reaction produces two moles of sodium nitrate ($NaNO_3$) for every one mole of barium sulfate ($BaSO_4$) produced.
Why are the Other Options Incorrect?
The other options are incorrect because they do not accurately represent the products of the reaction. Option A, $2 BaNa + 2 NO_3 SO_4$, is incorrect because it suggests that the reaction produces barium sodium (BaNa) and nitrate sulfate (NO_3 SO_4), which are not the actual products of the reaction. Option C, $NaNO_3 + BaSO_4$, is incorrect because it suggests that the reaction produces only one mole of sodium nitrate ($NaNO_3$) for every one mole of barium sulfate ($BaSO_4$) produced, which is not the case. Option D, $BaNa_2 + \left( NO_3 \right)_2$, is incorrect because it suggests that the reaction produces barium sodium ($BaNa_2$) and nitrate ($\left( NO_3 \right)_2$), which are not the actual products of the reaction.
Conclusion
In conclusion, the replacement reaction between $Ba \left( NO_3 \right)_2$ and $Na_2 SO_4$ produces barium sulfate ($BaSO_4$) and sodium nitrate ($NaNO_3$). The correct answer is B, $2 NaNO_3 + BaSO_4$, because it accurately represents the products of the reaction.
Q&A: Replacement Reaction of $Ba \left( NO_3 \right)_2$ and $Na_2 SO_4$
Frequently Asked Questions
Q: What is the replacement reaction between $Ba \left( NO_3 \right)_2$ and $Na_2 SO_4$?
A: The replacement reaction between $Ba \left( NO_3 \right)_2$ and $Na_2 SO_4$ is a type of double displacement reaction where barium nitrate reacts with sodium sulfate to form barium sulfate and sodium nitrate.
Q: What are the products of the reaction?
A: The two products of the reaction are barium sulfate ($BaSO_4$) and sodium nitrate ($NaNO_3$).
Q: Why is the correct answer B, $2 NaNO_3 + BaSO_4$?
A: The correct answer is B, $2 NaNO_3 + BaSO_4$, because the reaction produces two moles of sodium nitrate ($NaNO_3$) for every one mole of barium sulfate ($BaSO_4$) produced.
Q: Why are the other options incorrect?
A: The other options are incorrect because they do not accurately represent the products of the reaction. Option A, $2 BaNa + 2 NO_3 SO_4$, is incorrect because it suggests that the reaction produces barium sodium (BaNa) and nitrate sulfate (NO_3 SO_4), which are not the actual products of the reaction. Option C, $NaNO_3 + BaSO_4$, is incorrect because it suggests that the reaction produces only one mole of sodium nitrate ($NaNO_3$) for every one mole of barium sulfate ($BaSO_4$) produced, which is not the case. Option D, $BaNa_2 + \left( NO_3 \right)_2$, is incorrect because it suggests that the reaction produces barium sodium ($BaNa_2$) and nitrate ($\left( NO_3 \right)_2$), which are not the actual products of the reaction.
Q: What is the significance of the replacement reaction between $Ba \left( NO_3 \right)_2$ and $Na_2 SO_4$?
A: The replacement reaction between $Ba \left( NO_3 \right)_2$ and $Na_2 SO_4$ is significant because it produces barium sulfate, which is commonly used in medical imaging procedures, and sodium nitrate, which is used in the production of fertilizers, explosives, and other chemicals.
Q: How can I determine the products of a replacement reaction?
A: To determine the products of a replacement reaction, you can use the following steps:
- Write the chemical equation for the reaction.
- Identify the reactants and products.
- Use the solubility rules to determine the products.
- Check the products to see if they are correct.
Q: What are the solubility rules?
A: The solubility rules are a set of rules that determine the solubility of compounds in water. The solubility rules are:
- Most sodium (Na) compounds are soluble.
- Most potassium (K) compounds are soluble.
- Most ammonium (NH_4) compounds are soluble.
- Most nitrates (NO_3) are soluble.
- Most acetates (CH_3COO) are soluble.
- Most chlorides (Cl) are soluble, except for silver chloride (AgCl), lead chloride (PbCl_2), and mercury chloride (Hg_2Cl_2).
- Most bromides (Br) are soluble, except for silver bromide (AgBr), lead bromide (PbBr_2), and mercury bromide (Hg_2Br_2).
- Most iodides (I) are soluble, except for silver iodide (AgI), lead iodide (PbI_2), and mercury iodide (Hg_2I_2).
- Most sulfates (SO_4) are soluble, except for barium sulfate (BaSO_4), strontium sulfate (SrSO_4), and lead sulfate (PbSO_4).
- Most carbonates (CO_3) are insoluble, except for sodium carbonate (Na_2CO_3), potassium carbonate (K_2CO_3), and ammonium carbonate ((NH_4)_2CO_3).
- Most phosphates (PO_4) are insoluble, except for sodium phosphate (Na_3PO_4), potassium phosphate (K_3PO_4), and ammonium phosphate ((NH_4)_3PO_4).
Conclusion
In conclusion, the replacement reaction between $Ba \left( NO_3 \right)_2$ and $Na_2 SO_4$ produces barium sulfate and sodium nitrate. The correct answer is B, $2 NaNO_3 + BaSO_4$, because it accurately represents the products of the reaction.