Using The Slope And The $y$-intercept, Graph The Line Represented By The Following Equation:$2x - Y + 4 = 0$Complete Your Work In The Space Provided Or Upload A File That Can Display Math Symbols If Your Work Requires It. Include The

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Understanding the Equation

The given equation is 2xβˆ’y+4=02x - y + 4 = 0. To graph this line, we need to first rewrite the equation in the slope-intercept form, which is y=mx+by = mx + b, where mm is the slope and bb is the yy-intercept.

Rewriting the Equation

To rewrite the equation in slope-intercept form, we need to isolate yy on one side of the equation. We can do this by subtracting 2x2x from both sides and adding yy to both sides:

2xβˆ’y+4=02x - y + 4 = 0

βˆ’y=βˆ’2xβˆ’4-y = -2x - 4

y=2x+4y = 2x + 4

Identifying the Slope and yy-Intercept

Now that we have the equation in slope-intercept form, we can identify the slope and yy-intercept. The slope is the coefficient of xx, which is 22. The yy-intercept is the constant term, which is 44.

Graphing the Line

To graph the line, we can use the slope and yy-intercept to find two points on the line. We can then draw a line through these two points to graph the line.

Finding the yy-Intercept

The yy-intercept is the point where the line intersects the yy-axis. Since the yy-intercept is 44, we can plot the point (0,4)(0, 4) on the coordinate plane.

Finding a Second Point

To find a second point on the line, we can use the slope to find the xx-coordinate of the point. Since the slope is 22, we can use the point-slope form of a linear equation, which is yβˆ’y1=m(xβˆ’x1)y - y_1 = m(x - x_1), where (x1,y1)(x_1, y_1) is a point on the line.

Let's choose the point (0,4)(0, 4) as the point (x1,y1)(x_1, y_1). We can then plug in the values of mm, x1x_1, and y1y_1 into the point-slope form:

yβˆ’4=2(xβˆ’0)y - 4 = 2(x - 0)

yβˆ’4=2xy - 4 = 2x

y=2x+4y = 2x + 4

Now that we have the equation in point-slope form, we can find the xx-coordinate of the second point. Let's choose x=1x = 1. We can then plug in the value of xx into the equation:

y=2(1)+4y = 2(1) + 4

y=2+4y = 2 + 4

y=6y = 6

So, the second point is (1,6)(1, 6).

Graphing the Line

Now that we have two points on the line, we can graph the line by drawing a line through these two points. The line will have a slope of 22 and a yy-intercept of 44.

Conclusion

In this article, we learned how to graph a line using the slope and yy-intercept. We started by rewriting the equation in slope-intercept form, which allowed us to identify the slope and yy-intercept. We then used the slope and yy-intercept to find two points on the line, which we used to graph the line. The line has a slope of 22 and a yy-intercept of 44.

Example Problems

Problem 1

Graph the line represented by the equation 3xβˆ’2y+5=03x - 2y + 5 = 0.

Solution

To graph the line, we need to rewrite the equation in slope-intercept form. We can do this by subtracting 3x3x from both sides and adding 2y2y to both sides:

3xβˆ’2y+5=03x - 2y + 5 = 0

βˆ’2y=βˆ’3xβˆ’5-2y = -3x - 5

y=32x+52y = \frac{3}{2}x + \frac{5}{2}

The slope is 32\frac{3}{2} and the yy-intercept is 52\frac{5}{2}. We can use these values to find two points on the line. Let's choose the point (0,52)(0, \frac{5}{2}) as the yy-intercept. We can then use the slope to find the xx-coordinate of the second point. Let's choose x=1x = 1. We can then plug in the value of xx into the equation:

y=32(1)+52y = \frac{3}{2}(1) + \frac{5}{2}

y=32+52y = \frac{3}{2} + \frac{5}{2}

y=82y = \frac{8}{2}

y=4y = 4

So, the second point is (1,4)(1, 4). We can then graph the line by drawing a line through these two points.

Problem 2

Graph the line represented by the equation x+2yβˆ’3=0x + 2y - 3 = 0.

Solution

To graph the line, we need to rewrite the equation in slope-intercept form. We can do this by subtracting xx from both sides and adding 2y2y to both sides:

x+2yβˆ’3=0x + 2y - 3 = 0

2y=βˆ’x+32y = -x + 3

y=βˆ’12x+32y = -\frac{1}{2}x + \frac{3}{2}

The slope is βˆ’12-\frac{1}{2} and the yy-intercept is 32\frac{3}{2}. We can use these values to find two points on the line. Let's choose the point (0,32)(0, \frac{3}{2}) as the yy-intercept. We can then use the slope to find the xx-coordinate of the second point. Let's choose x=1x = 1. We can then plug in the value of xx into the equation:

y=βˆ’12(1)+32y = -\frac{1}{2}(1) + \frac{3}{2}

y=βˆ’12+32y = -\frac{1}{2} + \frac{3}{2}

y=22y = \frac{2}{2}

y=1y = 1

So, the second point is (1,1)(1, 1). We can then graph the line by drawing a line through these two points.

Final Thoughts

Graphing a line using the slope and yy-intercept is a useful skill to have in mathematics. It allows us to visualize the line and understand its properties. In this article, we learned how to graph a line using the slope and yy-intercept, and we saw how to apply this skill to example problems. With practice and patience, you can become proficient in graphing lines using the slope and yy-intercept.

Understanding the Basics

Graphing a line using the slope and yy-intercept is a fundamental concept in mathematics. It allows us to visualize the line and understand its properties. In this article, we will answer some common questions about graphing a line using the slope and yy-intercept.

Q: What is the slope-intercept form of a linear equation?

A: The slope-intercept form of a linear equation is y=mx+by = mx + b, where mm is the slope and bb is the yy-intercept.

Q: How do I find the slope and yy-intercept of a linear equation?

A: To find the slope and yy-intercept of a linear equation, you need to rewrite the equation in slope-intercept form. This can be done by subtracting xx from both sides and adding yy to both sides.

Q: What is the yy-intercept?

A: The yy-intercept is the point where the line intersects the yy-axis. It is the value of yy when x=0x = 0.

Q: How do I graph a line using the slope and yy-intercept?

A: To graph a line using the slope and yy-intercept, you need to find two points on the line. You can do this by using the slope to find the xx-coordinate of the second point, and then plugging in the value of xx into the equation to find the yy-coordinate.

Q: What is the significance of the slope in graphing a line?

A: The slope is the rate of change of the line. It tells us how steep the line is and in which direction it is sloping.

Q: How do I find the xx-coordinate of a point on a line?

A: To find the xx-coordinate of a point on a line, you need to use the slope to find the xx-coordinate of the point. This can be done by plugging in the value of yy into the equation and solving for xx.

Q: What is the difference between the slope and the yy-intercept?

A: The slope is the rate of change of the line, while the yy-intercept is the point where the line intersects the yy-axis.

Q: How do I graph a line with a negative slope?

A: To graph a line with a negative slope, you need to find two points on the line. You can do this by using the slope to find the xx-coordinate of the second point, and then plugging in the value of xx into the equation to find the yy-coordinate.

Q: What is the significance of the yy-intercept in graphing a line?

A: The yy-intercept is the point where the line intersects the yy-axis. It is the value of yy when x=0x = 0.

Q: How do I graph a line with a zero slope?

A: To graph a line with a zero slope, you need to find the yy-intercept of the line. This can be done by plugging in the value of xx into the equation and solving for yy.

Q: What is the difference between a linear equation and a quadratic equation?

A: A linear equation is an equation in which the highest power of the variable is 1, while a quadratic equation is an equation in which the highest power of the variable is 2.

Q: How do I graph a quadratic equation?

A: To graph a quadratic equation, you need to find the xx-intercepts and the yy-intercept of the equation. You can do this by plugging in the value of xx into the equation and solving for yy.

Conclusion

Graphing a line using the slope and yy-intercept is a fundamental concept in mathematics. It allows us to visualize the line and understand its properties. In this article, we answered some common questions about graphing a line using the slope and yy-intercept. We hope that this article has been helpful in understanding the basics of graphing a line using the slope and yy-intercept.

Final Thoughts

Graphing a line using the slope and yy-intercept is a useful skill to have in mathematics. It allows us to visualize the line and understand its properties. With practice and patience, you can become proficient in graphing lines using the slope and yy-intercept.