Use The Given Function To Find The Information. F ( X ) = − ( X − 2 ) 2 + 9 F(x) = -(x - 2)^2 + 9 F ( X ) = − ( X − 2 ) 2 + 9 A. Intercepts

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Understanding the Function

The given function is f(x)=(x2)2+9f(x) = -(x - 2)^2 + 9. This is a quadratic function in the form of f(x)=a(xh)2+kf(x) = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola. In this case, the vertex is (2,9)(2, 9).

Finding Intercepts

To find the x-intercepts, we need to set f(x)=0f(x) = 0 and solve for xx. This means that the function will intersect the x-axis at the points where the graph touches the x-axis.

Finding the x-Intercepts

To find the x-intercepts, we set f(x)=0f(x) = 0 and solve for xx:

(x2)2+9=0-(x - 2)^2 + 9 = 0

We can start by isolating the squared term:

(x2)2=9(x - 2)^2 = 9

Taking the square root of both sides, we get:

x2=±3x - 2 = \pm 3

Solving for xx, we get:

x=2±3x = 2 \pm 3

So, the x-intercepts are x=5x = 5 and x=1x = -1.

Finding the y-Intercept

To find the y-intercept, we need to find the value of f(x)f(x) when x=0x = 0. This is the point where the graph touches the y-axis.

We can plug in x=0x = 0 into the function:

f(0)=(02)2+9f(0) = -(0 - 2)^2 + 9

Simplifying, we get:

f(0)=(2)2+9f(0) = -(-2)^2 + 9

f(0)=4+9f(0) = -4 + 9

f(0)=5f(0) = 5

So, the y-intercept is (0,5)(0, 5).

Finding the Vertex

The vertex of the parabola is the point where the function changes from decreasing to increasing or vice versa. In this case, the vertex is (2,9)(2, 9).

Finding the Axis of Symmetry

The axis of symmetry is the vertical line that passes through the vertex. In this case, the axis of symmetry is x=2x = 2.

Finding the Maximum or Minimum Value

The maximum or minimum value of the function is the value of the function at the vertex. In this case, the maximum value is 99.

Graphing the Function

To graph the function, we can use the information we have found. We can plot the x-intercepts, y-intercept, vertex, and axis of symmetry on a coordinate plane.

Conclusion

In this article, we used the given function to find the x-intercepts, y-intercept, vertex, axis of symmetry, and maximum or minimum value. We also graphed the function using the information we found. This demonstrates how to use a quadratic function to find important information about the graph of the function.

Final Answer

The final answer is:

  • x-intercepts: x=5x = 5 and x=1x = -1
  • y-intercept: (0,5)(0, 5)
  • vertex: (2,9)(2, 9)
  • axis of symmetry: x=2x = 2
  • maximum or minimum value: 99

Understanding the Function

The given function is f(x)=(x2)2+9f(x) = -(x - 2)^2 + 9. This is a quadratic function in the form of f(x)=a(xh)2+kf(x) = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola. In this case, the vertex is (2,9)(2, 9).

Q&A

Q: What is the x-intercept of the function?

A: To find the x-intercept, we need to set f(x)=0f(x) = 0 and solve for xx. This means that the function will intersect the x-axis at the points where the graph touches the x-axis.

Q: How do I find the x-intercepts of the function?

A: To find the x-intercepts, we set f(x)=0f(x) = 0 and solve for xx. We can start by isolating the squared term:

(x2)2=9(x - 2)^2 = 9

Taking the square root of both sides, we get:

x2=±3x - 2 = \pm 3

Solving for xx, we get:

x=2±3x = 2 \pm 3

So, the x-intercepts are x=5x = 5 and x=1x = -1.

Q: What is the y-intercept of the function?

A: To find the y-intercept, we need to find the value of f(x)f(x) when x=0x = 0. This is the point where the graph touches the y-axis.

We can plug in x=0x = 0 into the function:

f(0)=(02)2+9f(0) = -(0 - 2)^2 + 9

Simplifying, we get:

f(0)=(2)2+9f(0) = -(-2)^2 + 9

f(0)=4+9f(0) = -4 + 9

f(0)=5f(0) = 5

So, the y-intercept is (0,5)(0, 5).

Q: What is the vertex of the function?

A: The vertex of the parabola is the point where the function changes from decreasing to increasing or vice versa. In this case, the vertex is (2,9)(2, 9).

Q: What is the axis of symmetry of the function?

A: The axis of symmetry is the vertical line that passes through the vertex. In this case, the axis of symmetry is x=2x = 2.

Q: What is the maximum or minimum value of the function?

A: The maximum or minimum value of the function is the value of the function at the vertex. In this case, the maximum value is 99.

Q: How do I graph the function?

A: To graph the function, we can use the information we have found. We can plot the x-intercepts, y-intercept, vertex, and axis of symmetry on a coordinate plane.

Q: What is the significance of the given function?

A: The given function is a quadratic function, which is a polynomial function of degree two. It has a parabolic shape and can be used to model a wide range of real-world phenomena, such as the trajectory of a projectile or the growth of a population.

Conclusion

In this article, we answered some common questions about the given quadratic function. We discussed how to find the x-intercepts, y-intercept, vertex, axis of symmetry, and maximum or minimum value of the function. We also graphed the function using the information we found. This demonstrates how to use a quadratic function to find important information about the graph of the function.

Final Answer

The final answer is:

  • x-intercepts: x=5x = 5 and x=1x = -1
  • y-intercept: (0,5)(0, 5)
  • vertex: (2,9)(2, 9)
  • axis of symmetry: x=2x = 2
  • maximum or minimum value: 99