Use The Given Conditions To Write An Equation For The Line In Point-slope Form And General Form.Passing Through { (2,-9)$}$ And Perpendicular To The Line Whose Equation Is { X - 4y - 7 = 0$}$.The Equation Of The Line In Point-slope

Introduction

In mathematics, the equation of a line can be expressed in various forms, including point-slope form and general form. The point-slope form is a convenient way to write the equation of a line when we know a point on the line and the slope of the line. On the other hand, the general form is a more compact way to write the equation of a line, which can be useful for solving systems of linear equations. In this article, we will use the given conditions to write an equation for the line in point-slope form and general form.

Understanding the Given Conditions

We are given that the line passes through the point ${(2,-9)}$ and is perpendicular to the line whose equation is ${x - 4y - 7 = 0}$. To start, we need to find the slope of the given line. The equation of the line is in general form, so we can rewrite it in slope-intercept form by solving for ${y}$.

Slope-Intercept Form

The equation of the line is:

${x - 4y - 7 = 0}$

To solve for ${y}$, we can add ${4y}$ to both sides of the equation and then divide by 4:

${4y = x - 7}$

${y = \frac{x}{4} - \frac{7}{4}}$

Now that we have the equation in slope-intercept form, we can see that the slope of the line is ${\frac{1}{4}}$.

Perpendicular Line

Since the line we are looking for is perpendicular to the given line, its slope will be the negative reciprocal of ${\frac{1}{4}}$, which is ${-4}$.

Writing the Equation in Point-Slope Form

Now that we have the slope of the line, we can use the point-slope form to write the equation of the line. The point-slope form is given by:

${y - y_1 = m(x - x_1)}$

where ${(x_1, y_1)}$ is a point on the line and ${m}$ is the slope of the line.

In this case, we know that the line passes through the point ${(2,-9)}$ and has a slope of ${-4}$. Plugging these values into the point-slope form, we get:

${y - (-9) = -4(x - 2)}$

Simplifying the equation, we get:

${y + 9 = -4x + 8}$

Subtracting 9 from both sides, we get:

${y = -4x - 1}$

Writing the Equation in General Form

To write the equation in general form, we can multiply both sides of the equation by ${-1}$ and then rearrange the terms:

${4x + y + 1 = 0}$

This is the equation of the line in general form.

Conclusion

In this article, we used the given conditions to write an equation for the line in point-slope form and general form. We found the slope of the line by rewriting the equation of the given line in slope-intercept form and then used the point-slope form to write the equation of the line. Finally, we converted the equation to general form by multiplying both sides by ${-1}$ and rearranging the terms.

Key Takeaways

• The point-slope form is a convenient way to write the equation of a line when we know a point on the line and the slope of the line.
• The general form is a more compact way to write the equation of a line, which can be useful for solving systems of linear equations.
• To find the slope of a line, we can rewrite the equation in slope-intercept form and then identify the slope.
• To write the equation of a line in point-slope form, we can use the point-slope form and plug in the values of the point and the slope.
• To write the equation of a line in general form, we can multiply both sides of the equation by ${-1}$ and then rearrange the terms.

Practice Problems

1. Find the equation of the line that passes through the point ${(3,4)}$ and has a slope of ${-2}$.
2. Find the equation of the line that is perpendicular to the line whose equation is ${2x + 3y - 5 = 0}$.
3. Find the equation of the line that passes through the point ${(1,2)}$ and has a slope of ${\frac{3}{4}}$.

Solutions

1. Using the point-slope form, we get:

${y - 4 = -2(x - 3)}$

Simplifying the equation, we get:

${y - 4 = -2x + 6}$

Adding 4 to both sides, we get:

${y = -2x + 10}$

2. The slope of the given line is ${-\frac{2}{3}}$, so the slope of the perpendicular line is ${\frac{3}{2}}$. Using the point-slope form, we get:

${y - 0 = \frac{3}{2}(x - 0)}$

Simplifying the equation, we get:

${y = \frac{3}{2}x}$

3. Using the point-slope form, we get:

${y - 2 = \frac{3}{4}(x - 1)}$

Simplifying the equation, we get:

${y - 2 = \frac{3}{4}x - \frac{3}{4}}$

Adding 2 to both sides, we get:

$$

Q: What is the point-slope form of a line?

A: The point-slope form of a line is a way to write the equation of a line when we know a point on the line and the slope of the line. It is given by:

${y - y_1 = m(x - x_1)}$

where ${(x_1, y_1)}$ is a point on the line and ${m}$ is the slope of the line.

Q: How do I find the slope of a line?

A: To find the slope of a line, we can rewrite the equation of the line in slope-intercept form and then identify the slope. The slope-intercept form is given by:

${y = mx + b}$

where ${m}$ is the slope and ${b}$ is the y-intercept.

Q: What is the general form of a line?

A: The general form of a line is a more compact way to write the equation of a line. It is given by:

${Ax + By + C = 0}$

where ${A}$, ${B}$, and ${C}$ are constants.

Q: How do I convert the point-slope form to general form?

A: To convert the point-slope form to general form, we can multiply both sides of the equation by ${-1}$ and then rearrange the terms.

Q: What is the difference between the point-slope form and the general form?

A: The point-slope form is a convenient way to write the equation of a line when we know a point on the line and the slope of the line. The general form is a more compact way to write the equation of a line, which can be useful for solving systems of linear equations.

Q: How do I find the equation of a line that is perpendicular to another line?

A: To find the equation of a line that is perpendicular to another line, we can find the slope of the given line and then take the negative reciprocal of the slope. This will give us the slope of the perpendicular line.

Q: What is the negative reciprocal of a slope?

A: The negative reciprocal of a slope is the slope that is perpendicular to the given slope. If the slope of a line is ${m}$, then the negative reciprocal of the slope is ${-\frac{1}{m}}$.

Q: How do I use the point-slope form to write the equation of a line?

A: To use the point-slope form to write the equation of a line, we can plug in the values of the point and the slope into the point-slope form:

${y - y_1 = m(x - x_1)}$

where ${(x_1, y_1)}$ is a point on the line and ${m}$ is the slope of the line.

Q: What are some common mistakes to avoid when working with the point-slope form?

A: Some common mistakes to avoid when working with the point-slope form include:

• Not using the correct values for the point and the slope
• Not simplifying the equation correctly
• Not rearranging the terms correctly

Q: How do I check if two lines are parallel or perpendicular?

A: To check if two lines are parallel or perpendicular, we can compare their slopes. If the slopes are equal, then the lines are parallel. If the slopes are negative reciprocals of each other, then the lines are perpendicular.

Q: What are some real-world applications of the point-slope form?

A: Some real-world applications of the point-slope form include:

• Writing the equation of a line that passes through a given point and has a given slope
• Finding the equation of a line that is perpendicular to another line
• Solving systems of linear equations

Q: How do I use the point-slope form to solve a system of linear equations?

A: To use the point-slope form to solve a system of linear equations, we can write the equations of the lines in point-slope form and then solve for the intersection point. The intersection point will be the solution to the system of equations.