Translate The Word Problem:You Must Be At Least 13 To Ride A Roller Coaster.Convert The Linear Inequality − 4 Z + 6 \textgreater 10 -4z + 6 \ \textgreater \ 10 − 4 Z + 6 \textgreater 10 Into A Word Problem.
Understanding Linear Inequalities
Linear inequalities are mathematical expressions that compare two values using the greater than or less than symbols. They are often used to represent real-world situations where a certain condition must be met. In this article, we will explore how to convert linear inequalities into word problems, using the example of a roller coaster ride.
Converting the Word Problem into a Linear Inequality
Let's start with the word problem: "You must be at least 13 to ride a roller coaster." This can be translated into a linear inequality as follows:
- Let z be the age of the person.
- The condition is that the person must be at least 13 years old.
- This can be represented as z ≥ 13.
Converting the Linear Inequality into a Word Problem
Now, let's convert the linear inequality into a word problem. To do this, we need to understand the meaning of the inequality.
- The inequality is in the form of , where a, b, and c are constants.
- The coefficient of z is -4, which means that the value of z is being multiplied by -4.
- The constant term is 6, which is being added to the product of -4z.
- The inequality is greater than 10, which means that the value of the expression is greater than 10.
Breaking Down the Linear Inequality
To convert the linear inequality into a word problem, we need to break it down into its components.
- The coefficient of z is -4, which means that the value of z is being multiplied by -4. This can be represented as "4 times the value of z".
- The constant term is 6, which is being added to the product of -4z. This can be represented as "6 more than 4 times the value of z".
- The inequality is greater than 10, which means that the value of the expression is greater than 10. This can be represented as "greater than 10".
Creating a Word Problem
Now that we have broken down the linear inequality into its components, we can create a word problem.
Example 1: Tom has 4 times as many pencils as his friend Alex. If Alex has 6 more pencils than Tom, and Tom has more than 10 pencils, how many pencils does Tom have?
Solution: Let z be the number of pencils that Tom has. Then, the inequality can be written as:
-4z + 6 > 10
This can be rewritten as:
4z < 4
z < 1
Since z represents the number of pencils that Tom has, the solution is that Tom has less than 1 pencil. However, this is not a realistic solution, as Tom cannot have a fraction of a pencil.
Example 2: A bookshelf has 4 times as many books as a nearby bookcase. If the bookcase has 6 more books than the bookshelf, and the bookshelf has more than 10 books, how many books does the bookshelf have?
Solution: Let z be the number of books that the bookshelf has. Then, the inequality can be written as:
-4z + 6 > 10
This can be rewritten as:
4z < 4
z < 1
Since z represents the number of books that the bookshelf has, the solution is that the bookshelf has less than 1 book. However, this is not a realistic solution, as a bookshelf cannot have a fraction of a book.
Example 3: A company has 4 times as many employees as a nearby company. If the nearby company has 6 more employees than the company, and the company has more than 10 employees, how many employees does the company have?
Solution: Let z be the number of employees that the company has. Then, the inequality can be written as:
-4z + 6 > 10
This can be rewritten as:
4z < 4
z < 1
Since z represents the number of employees that the company has, the solution is that the company has less than 1 employee. However, this is not a realistic solution, as a company cannot have a fraction of an employee.
Conclusion
Converting linear inequalities into word problems can be a challenging task, but it requires a deep understanding of the meaning of the inequality. By breaking down the inequality into its components and creating a word problem, we can make the inequality more accessible and easier to understand. In this article, we have explored how to convert the linear inequality into a word problem, using the example of a roller coaster ride. We have also created three word problems to illustrate the concept.
References
- [1] Khan Academy. (n.d.). Linear Inequalities. Retrieved from https://www.khanacademy.org/math/algebra/x2f-linear-inequalities/x2f-linear-inequalities/x2f-linear-inequalities
- [2] Math Open Reference. (n.d.). Linear Inequalities. Retrieved from https://www.mathopenref.com/linearinequalities.html
- [3] Wolfram MathWorld. (n.d.). Linear Inequalities. Retrieved from https://mathworld.wolfram.com/LinearInequalities.html
Word Problem Examples
- A person has 4 times as many dollars as their friend. If their friend has 6 more dollars than they do, and they have more than 10 dollars, how many dollars do they have?
- A company has 4 times as many employees as a nearby company. If the nearby company has 6 more employees than the company, and the company has more than 10 employees, how many employees does the company have?
- A bookshelf has 4 times as many books as a nearby bookcase. If the bookcase has 6 more books than the bookshelf, and the bookshelf has more than 10 books, how many books does the bookshelf have?
Solutions
- Let z be the number of dollars that the person has. Then, the inequality can be written as: -4z + 6 > 10 This can be rewritten as: 4z < 4 z < 1 Since z represents the number of dollars that the person has, the solution is that the person has less than 1 dollar. However, this is not a realistic solution, as a person cannot have a fraction of a dollar.
- Let z be the number of employees that the company has. Then, the inequality can be written as: -4z + 6 > 10 This can be rewritten as: 4z < 4 z < 1 Since z represents the number of employees that the company has, the solution is that the company has less than 1 employee. However, this is not a realistic solution, as a company cannot have a fraction of an employee.
- Let z be the number of books that the bookshelf has. Then, the inequality can be written as:
-4z + 6 > 10
This can be rewritten as:
4z < 4
z < 1
Since z represents the number of books that the bookshelf has, the solution is that the bookshelf has less than 1 book. However, this is not a realistic solution, as a bookshelf cannot have a fraction of a book.
Q&A: Converting Linear Inequalities into Word Problems =====================================================
Frequently Asked Questions
Q: What is a linear inequality? A: A linear inequality is a mathematical expression that compares two values using the greater than or less than symbols. It is often used to represent real-world situations where a certain condition must be met.
Q: How do I convert a linear inequality into a word problem? A: To convert a linear inequality into a word problem, you need to break down the inequality into its components and create a scenario that illustrates the inequality. This can be done by identifying the variables, constants, and operations involved in the inequality.
Q: What are some common mistakes to avoid when converting linear inequalities into word problems? A: Some common mistakes to avoid when converting linear inequalities into word problems include:
- Not identifying the variables and constants in the inequality
- Not creating a realistic scenario that illustrates the inequality
- Not using clear and concise language in the word problem
- Not providing enough information to solve the problem
Q: How do I create a word problem that illustrates a linear inequality? A: To create a word problem that illustrates a linear inequality, you need to identify the variables, constants, and operations involved in the inequality and create a scenario that illustrates the inequality. This can be done by:
- Identifying the variables and constants in the inequality
- Creating a scenario that illustrates the inequality
- Using clear and concise language in the word problem
- Providing enough information to solve the problem
Q: What are some examples of word problems that illustrate linear inequalities? A: Some examples of word problems that illustrate linear inequalities include:
- A person has 4 times as many dollars as their friend. If their friend has 6 more dollars than they do, and they have more than 10 dollars, how many dollars do they have?
- A company has 4 times as many employees as a nearby company. If the nearby company has 6 more employees than the company, and the company has more than 10 employees, how many employees does the company have?
- A bookshelf has 4 times as many books as a nearby bookcase. If the bookcase has 6 more books than the bookshelf, and the bookshelf has more than 10 books, how many books does the bookshelf have?
Q: How do I solve a word problem that illustrates a linear inequality? A: To solve a word problem that illustrates a linear inequality, you need to:
- Read the word problem carefully and identify the variables, constants, and operations involved in the inequality
- Create an equation or inequality that represents the situation
- Solve the equation or inequality to find the solution
- Check the solution to make sure it is reasonable and makes sense in the context of the problem
Q: What are some tips for creating effective word problems that illustrate linear inequalities? A: Some tips for creating effective word problems that illustrate linear inequalities include:
- Using clear and concise language
- Providing enough information to solve the problem
- Creating a realistic scenario that illustrates the inequality
- Using variables and constants that are relevant to the problem
- Making sure the solution is reasonable and makes sense in the context of the problem
Q: How do I know if a word problem is a good example of a linear inequality? A: A word problem is a good example of a linear inequality if it:
- Involves a comparison between two values using the greater than or less than symbols
- Can be represented by an equation or inequality
- Has a solution that is reasonable and makes sense in the context of the problem
Q: What are some common applications of linear inequalities in real-world situations? A: Some common applications of linear inequalities in real-world situations include:
- Budgeting and financial planning
- Resource allocation and management
- Optimization and decision-making
- Science and engineering applications
- Business and economics applications
Q: How do I use linear inequalities to solve real-world problems? A: To use linear inequalities to solve real-world problems, you need to:
- Identify the variables, constants, and operations involved in the problem
- Create an equation or inequality that represents the situation
- Solve the equation or inequality to find the solution
- Check the solution to make sure it is reasonable and makes sense in the context of the problem
Q: What are some common mistakes to avoid when using linear inequalities to solve real-world problems? A: Some common mistakes to avoid when using linear inequalities to solve real-world problems include:
- Not identifying the variables and constants in the problem
- Not creating a realistic scenario that illustrates the inequality
- Not using clear and concise language in the problem
- Not providing enough information to solve the problem
- Not checking the solution to make sure it is reasonable and makes sense in the context of the problem