The $y$-intercept Is 6.Practice Exercise 61. Determine The $x$-intercept And $y$-intercept Of The Lines Represented By Each Of The Following Equations.$[ \begin{array}{|c|c|c|c|} \hline \text{Equation} &

by ADMIN 210 views

Determining the $x$-intercept and $y$-intercept of Linear Equations

In mathematics, the intercepts of a linear equation are crucial points that help us understand the behavior of the line. The $x$-intercept is the point where the line crosses the $x$-axis, and the $y$-intercept is the point where the line crosses the $y$-axis. In this article, we will explore how to determine the $x$-intercept and $y$-intercept of the lines represented by given equations.

Understanding the Basics of Linear Equations

A linear equation is a mathematical statement that represents a straight line on the coordinate plane. It is typically written in the form of $y = mx + b$, where $m$ is the slope of the line and $b$ is the $y$-intercept. The slope-intercept form of a linear equation is essential in determining the intercepts of the line.

The Role of the $y$-Intercept

The $y$-intercept is the point where the line crosses the $y$-axis. It is the value of $y$ when $x = 0$. In the equation $y = mx + b$, the $y$-intercept is represented by the value of $b$. For example, if the equation is $y = 2x + 6$, the $y$-intercept is 6.

Determining the $x$-Intercept

The $x$-intercept is the point where the line crosses the $x$-axis. It is the value of $x$ when $y = 0$. To determine the $x$-intercept, we need to set $y = 0$ in the equation and solve for $x$.

Example 1: Finding the $x$-Intercept

Consider the equation $y = 2x + 6$. To find the $x$-intercept, we set $y = 0$ and solve for $x$.

0=2x+60 = 2x + 6

Subtracting 6 from both sides:

βˆ’6=2x-6 = 2x

Dividing both sides by 2:

x=βˆ’3x = -3

Therefore, the $x$-intercept of the line represented by the equation $y = 2x + 6$ is -3.

Determining the $y$-Intercept

As mentioned earlier, the $y$-intercept is the value of $y$ when $x = 0$. In the equation $y = mx + b$, the $y$-intercept is represented by the value of $b$. Therefore, to determine the $y$-intercept, we simply need to identify the value of $b$ in the equation.

Example 2: Finding the $y$-Intercept

Consider the equation $y = 3x - 2$. To find the $y$-intercept, we need to identify the value of $b$, which is -2.

Therefore, the $y$-intercept of the line represented by the equation $y = 3x - 2$ is -2.

Practice Exercise 61

Determine the $x$-intercept and $y$-intercept of the lines represented by each of the following equations:

  1. y=4x+2y = 4x + 2

  2. y=2xβˆ’5y = 2x - 5

  3. y=x+3y = x + 3

  4. y=3xβˆ’4y = 3x - 4

Solution to Practice Exercise 61

Equation 1: $y = 4x + 2$

To find the $x$-intercept, we set $y = 0$ and solve for $x$.

0=4x+20 = 4x + 2

Subtracting 2 from both sides:

βˆ’2=4x-2 = 4x

Dividing both sides by 4:

x=βˆ’12x = -\frac{1}{2}

Therefore, the $x$-intercept of the line represented by the equation $y = 4x + 2$ is $-\frac{1}{2}$.

To find the $y$-intercept, we identify the value of $b$, which is 2.

Therefore, the $y$-intercept of the line represented by the equation $y = 4x + 2$ is 2.

Equation 2: $y = 2x - 5$

To find the $x$-intercept, we set $y = 0$ and solve for $x$.

0=2xβˆ’50 = 2x - 5

Adding 5 to both sides:

5=2x5 = 2x

Dividing both sides by 2:

x=52x = \frac{5}{2}

Therefore, the $x$-intercept of the line represented by the equation $y = 2x - 5$ is $\frac{5}{2}$.

To find the $y$-intercept, we identify the value of $b$, which is -5.

Therefore, the $y$-intercept of the line represented by the equation $y = 2x - 5$ is -5.

Equation 3: $y = x + 3$

To find the $x$-intercept, we set $y = 0$ and solve for $x$.

0=x+30 = x + 3

Subtracting 3 from both sides:

βˆ’3=x-3 = x

Therefore, the $x$-intercept of the line represented by the equation $y = x + 3$ is -3.

To find the $y$-intercept, we identify the value of $b$, which is 3.

Therefore, the $y$-intercept of the line represented by the equation $y = x + 3$ is 3.

Equation 4: $y = 3x - 4$

To find the $x$-intercept, we set $y = 0$ and solve for $x$.

0=3xβˆ’40 = 3x - 4

Adding 4 to both sides:

4=3x4 = 3x

Dividing both sides by 3:

x=43x = \frac{4}{3}

Therefore, the $x$-intercept of the line represented by the equation $y = 3x - 4$ is $\frac{4}{3}$.

To find the $y$-intercept, we identify the value of $b$, which is -4.

Therefore, the $y$-intercept of the line represented by the equation $y = 3x - 4$ is -4.

In conclusion, determining the $x$-intercept and $y$-intercept of a linear equation is crucial in understanding the behavior of the line. By setting $y = 0$ and solving for $x$, we can find the $x$-intercept, and by identifying the value of $b$, we can find the $y$-intercept.

Frequently Asked Questions and Answers

In the previous article, we explored how to determine the $x$-intercept and $y$-intercept of the lines represented by given equations. In this article, we will address some frequently asked questions and provide answers to help you better understand the concept.

Q: What is the difference between the $x$-intercept and the $y$-intercept?

A: The $x$-intercept is the point where the line crosses the $x$-axis, and the $y$-intercept is the point where the line crosses the $y$-axis. In other words, the $x$-intercept is the value of $x$ when $y = 0$, and the $y$-intercept is the value of $y$ when $x = 0$.

Q: How do I determine the $x$-intercept of a line?

A: To determine the $x$-intercept, you need to set $y = 0$ in the equation and solve for $x$. This will give you the value of $x$ when the line crosses the $x$-axis.

Q: How do I determine the $y$-intercept of a line?

A: To determine the $y$-intercept, you need to identify the value of $b$ in the equation $y = mx + b$. This will give you the value of $y$ when the line crosses the $y$-axis.

Q: What if the equation is not in the form $y = mx + b$?

A: If the equation is not in the form $y = mx + b$, you can still determine the $x$-intercept and $y$-intercept by rearranging the equation to isolate $y$ and then following the steps outlined above.

Q: Can I use a graphing calculator to determine the intercepts of a line?

A: Yes, you can use a graphing calculator to determine the intercepts of a line. By graphing the line and using the calculator's built-in functions, you can find the $x$-intercept and $y$-intercept of the line.

Q: What if the line has no $x$-intercept or $y$-intercept?

A: If the line has no $x$-intercept or $y$-intercept, it means that the line does not cross the $x$-axis or $y$-axis. This can occur when the line is a vertical line (i.e., a line with a slope of infinity) or a horizontal line (i.e., a line with a slope of zero).

Q: Can I use the intercepts to determine the equation of a line?

A: Yes, you can use the intercepts to determine the equation of a line. By using the $x$-intercept and $y$-intercept, you can write the equation of the line in the form $y = mx + b$.

Q: What if I have a system of linear equations?

A: If you have a system of linear equations, you can use the intercepts to determine the solution to the system. By finding the $x$-intercept and $y$-intercept of each line, you can identify the point of intersection between the two lines.

Q: Can I use the intercepts to determine the slope of a line?

A: Yes, you can use the intercepts to determine the slope of a line. By using the $x$-intercept and $y$-intercept, you can write the equation of the line in the form $y = mx + b$ and then identify the slope $m$.

Q: What if I have a non-linear equation?

A: If you have a non-linear equation, you cannot use the intercepts to determine the equation of the line. Non-linear equations have a more complex form and require different methods to solve.

Q: Can I use the intercepts to determine the equation of a non-linear equation?

A: No, you cannot use the intercepts to determine the equation of a non-linear equation. Non-linear equations have a more complex form and require different methods to solve.

Q: What if I have a quadratic equation?

A: If you have a quadratic equation, you can use the intercepts to determine the equation of the line. By finding the $x$-intercept and $y$-intercept, you can write the equation of the line in the form $y = ax^2 + bx + c$.

Q: Can I use the intercepts to determine the equation of a quadratic equation?

A: Yes, you can use the intercepts to determine the equation of a quadratic equation. By finding the $x$-intercept and $y$-intercept, you can write the equation of the line in the form $y = ax^2 + bx + c$.

Q: What if I have a cubic equation?

A: If you have a cubic equation, you can use the intercepts to determine the equation of the line. By finding the $x$-intercept and $y$-intercept, you can write the equation of the line in the form $y = ax^3 + bx^2 + cx + d$.

Q: Can I use the intercepts to determine the equation of a cubic equation?

A: Yes, you can use the intercepts to determine the equation of a cubic equation. By finding the $x$-intercept and $y$-intercept, you can write the equation of the line in the form $y = ax^3 + bx^2 + cx + d$.

In conclusion, the intercepts of a line are crucial points that help us understand the behavior of the line. By determining the $x$-intercept and $y$-intercept, we can write the equation of the line in the form $y = mx + b$ and use it to solve various problems.