The Total Resistance In A Circuit With Two Parallel Resistors Is 2 Ohms, And $R_1$ Is 6 Ohms. Using The Equation For $R_2$, In Terms Of $R_T$ And $R_1$, What Is $R_2$?$R_2$ Is _____ Ohms.

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Understanding the Basics of Parallel Resistors

When two resistors are connected in parallel, the total resistance of the circuit is less than the individual resistances of the two resistors. This is because the current can flow through both resistors simultaneously, reducing the overall resistance. In this article, we will explore the equation for calculating the total resistance in a circuit with two parallel resistors and use it to find the value of R2R_2.

The Equation for Total Resistance in a Parallel Circuit

The equation for total resistance in a parallel circuit is given by:

1RT=1R1+1R2\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2}

where RTR_T is the total resistance, R1R_1 is the resistance of the first resistor, and R2R_2 is the resistance of the second resistor.

Given Values and the Equation for R2R_2

We are given that the total resistance in the circuit is 2 ohms, and R1R_1 is 6 ohms. We need to find the value of R2R_2 using the equation for R2R_2 in terms of RTR_T and R1R_1.

Deriving the Equation for R2R_2

To derive the equation for R2R_2, we can start with the equation for total resistance in a parallel circuit:

1RT=1R1+1R2\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2}

We can rearrange this equation to isolate R2R_2:

1R2=1RTβˆ’1R1\frac{1}{R_2} = \frac{1}{R_T} - \frac{1}{R_1}

Taking the reciprocal of both sides, we get:

R2=11RTβˆ’1R1R_2 = \frac{1}{\frac{1}{R_T} - \frac{1}{R_1}}

Simplifying the expression, we get:

R2=R1RTRTβˆ’R1R_2 = \frac{R_1 R_T}{R_T - R_1}

Substituting the Given Values

We are given that RTR_T is 2 ohms and R1R_1 is 6 ohms. Substituting these values into the equation for R2R_2, we get:

R2=6Γ—22βˆ’6R_2 = \frac{6 \times 2}{2 - 6}

Simplifying the expression, we get:

R2=12βˆ’4R_2 = \frac{12}{-4}

R2=βˆ’3R_2 = -3

However, since resistance cannot be negative, we need to take the absolute value of the result:

R2=βˆ£βˆ’3∣R_2 = |-3|

R2=3R_2 = 3

Therefore, the value of R2R_2 is 3 ohms.

Conclusion

In this article, we derived the equation for R2R_2 in terms of RTR_T and R1R_1 and used it to find the value of R2R_2 in a circuit with two parallel resistors. We found that the value of R2R_2 is 3 ohms.

Key Takeaways

  • The equation for total resistance in a parallel circuit is given by 1RT=1R1+1R2\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2}.
  • The equation for R2R_2 in terms of RTR_T and R1R_1 is given by R2=R1RTRTβˆ’R1R_2 = \frac{R_1 R_T}{R_T - R_1}.
  • The value of R2R_2 is 3 ohms when RTR_T is 2 ohms and R1R_1 is 6 ohms.
    Frequently Asked Questions (FAQs) about Parallel Resistors =============================================================

Q: What is the total resistance in a circuit with two parallel resistors?

A: The total resistance in a circuit with two parallel resistors is given by the equation 1RT=1R1+1R2\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2}, where RTR_T is the total resistance, R1R_1 is the resistance of the first resistor, and R2R_2 is the resistance of the second resistor.

Q: How do I calculate the total resistance in a circuit with two parallel resistors?

A: To calculate the total resistance in a circuit with two parallel resistors, you can use the equation 1RT=1R1+1R2\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2}. Rearranging this equation, you can solve for RTR_T:

RT=R1R2R1+R2R_T = \frac{R_1 R_2}{R_1 + R_2}

Q: What is the relationship between the total resistance and the individual resistances in a parallel circuit?

A: In a parallel circuit, the total resistance is less than the individual resistances. This is because the current can flow through both resistors simultaneously, reducing the overall resistance.

Q: Can I use the equation for total resistance in a series circuit to calculate the total resistance in a parallel circuit?

A: No, you cannot use the equation for total resistance in a series circuit to calculate the total resistance in a parallel circuit. The equation for total resistance in a series circuit is RT=R1+R2R_T = R_1 + R_2, while the equation for total resistance in a parallel circuit is 1RT=1R1+1R2\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2}.

Q: How do I find the value of R2R_2 in a circuit with two parallel resistors?

A: To find the value of R2R_2 in a circuit with two parallel resistors, you can use the equation R2=R1RTRTβˆ’R1R_2 = \frac{R_1 R_T}{R_T - R_1}. Rearranging this equation, you can solve for R2R_2:

R2=R1RTRTβˆ’R1R_2 = \frac{R_1 R_T}{R_T - R_1}

Q: What is the value of R2R_2 when RTR_T is 2 ohms and R1R_1 is 6 ohms?

A: To find the value of R2R_2 when RTR_T is 2 ohms and R1R_1 is 6 ohms, you can substitute these values into the equation R2=R1RTRTβˆ’R1R_2 = \frac{R_1 R_T}{R_T - R_1}:

R2=6Γ—22βˆ’6R_2 = \frac{6 \times 2}{2 - 6}

Simplifying the expression, you get:

R2=12βˆ’4R_2 = \frac{12}{-4}

R2=βˆ’3R_2 = -3

However, since resistance cannot be negative, you need to take the absolute value of the result:

R2=βˆ£βˆ’3∣R_2 = |-3|

R2=3R_2 = 3

Therefore, the value of R2R_2 is 3 ohms.

Q: What is the significance of the equation for R2R_2 in a parallel circuit?

A: The equation for R2R_2 in a parallel circuit is significant because it allows you to calculate the value of R2R_2 when the total resistance and the resistance of the first resistor are known. This equation is useful in a variety of applications, including electronics and electrical engineering.

Q: Can I use the equation for R2R_2 in a parallel circuit to calculate the total resistance in a series circuit?

A: No, you cannot use the equation for R2R_2 in a parallel circuit to calculate the total resistance in a series circuit. The equation for total resistance in a series circuit is RT=R1+R2R_T = R_1 + R_2, while the equation for R2R_2 in a parallel circuit is R2=R1RTRTβˆ’R1R_2 = \frac{R_1 R_T}{R_T - R_1}. These equations are not equivalent and cannot be used interchangeably.