
Introduction
A linear function is a type of function that can be represented in the form y=mx+b, where m is the slope and b is the y-intercept. The table of values represents a linear function, and in this article, we will learn how to enter an equation in the form y=mx+b that represents the given table of values.
Understanding the Table of Values
The table of values is a collection of points that represent the input and output values of a function. In this case, the table of values is given as:
The table of values shows that when x is -3, the corresponding value of y is 9. Similarly, when x is 3, the corresponding value of y is -1, and when x is 9, the corresponding value of y is -11.
Finding the Slope
The slope of a linear function is a measure of how much the function changes as the input value changes. In this case, we can find the slope by using the formula:
m=x2ββx1βy2ββy1ββ
where (x1β,y1β) and (x2β,y2β) are two points on the table of values.
Let's use the points (-3, 9) and (3, -1) to find the slope:
m=3β(β3)β1β9β=6β10β=β35β
So, the slope of the linear function is β35β.
Finding the Y-Intercept
The y-intercept of a linear function is the value of y when x is 0. In this case, we can find the y-intercept by using the point (0, b) and the slope m.
We know that the point (0, b) lies on the line, so we can substitute x=0 and y=b into the equation y=mx+b:
b=m(0)+b
Simplifying the equation, we get:
b=b
This equation is true for any value of b, so we can use any point on the table of values to find the y-intercept.
Let's use the point (-3, 9) to find the y-intercept:
9=β35β(β3)+b
Simplifying the equation, we get:
9=5+b
Subtracting 5 from both sides, we get:
b=4
So, the y-intercept of the linear function is 4.
Writing the Equation
Now that we have found the slope and y-intercept, we can write the equation of the linear function in the form y=mx+b:
y=β35βx+4
This equation represents the table of values and is a linear function.
Conclusion
In this article, we learned how to enter an equation in the form y=mx+b that represents a given table of values. We found the slope and y-intercept of the linear function using the points on the table of values and wrote the equation of the linear function in the form y=mx+b. The equation of the linear function is y=β35βx+4.
Example Problems
- Find the equation of the linear function represented by the table of values:
- Find the equation of the linear function represented by the table of values:
Solutions
- To find the equation of the linear function, we need to find the slope and y-intercept. Let's use the points (2, 5) and (4, 9) to find the slope:
m=4β29β5β=24β=2
So, the slope of the linear function is 2.
Now, let's use the point (2, 5) to find the y-intercept:
5=2(2)+b
Simplifying the equation, we get:
5=4+b
Subtracting 4 from both sides, we get:
b=1
So, the y-intercept of the linear function is 1.
The equation of the linear function is:
y=2x+1
- To find the equation of the linear function, we need to find the slope and y-intercept. Let's use the points (-2, 3) and (0, 5) to find the slope:
m=0β(β2)5β3β=22β=1
So, the slope of the linear function is 1.
Now, let's use the point (-2, 3) to find the y-intercept:
3=1(β2)+b
Simplifying the equation, we get:
3=β2+b
Adding 2 to both sides, we get:
b=5
So, the y-intercept of the linear function is 5.
The equation of the linear function is:
y = x + 5$<br/>
**Q&A: The Table of Values Represents a Linear Function**
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Frequently Asked Questions

Q: What is a linear function?
A: A linear function is a type of function that can be represented in the form y=mx+b, where m is the slope and b is the y-intercept.
Q: How do I find the slope of a linear function?
A: To find the slope of a linear function, you can use the formula:
m=x2ββx1βy2ββy1ββ</span></p><p>where<spanclass="katex"><spanclass="katexβmathml"><mathxmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mostretchy="false">(</mo><msub><mi>x</mi><mn>1</mn></msub><moseparator="true">,</mo><msub><mi>y</mi><mn>1</mn></msub><mostretchy="false">)</mo></mrow><annotationencoding="application/xβtex">(x1β,y1β)</annotation></semantics></math></span><spanclass="katexβhtml"ariaβhidden="true"><spanclass="base"><spanclass="strut"style="height:1em;verticalβalign:β0.25em;"></span><spanclass="mopen">(</span><spanclass="mord"><spanclass="mordmathnormal">x</span><spanclass="msupsub"><spanclass="vlistβtvlistβt2"><spanclass="vlistβr"><spanclass="vlist"style="height:0.3011em;"><spanstyle="top:β2.55em;marginβleft:0em;marginβright:0.05em;"><spanclass="pstrut"style="height:2.7em;"></span><spanclass="sizingresetβsize6size3mtight"><spanclass="mordmtight">1</span></span></span></span><spanclass="vlistβs">β</span></span><spanclass="vlistβr"><spanclass="vlist"style="height:0.15em;"><span></span></span></span></span></span></span><spanclass="mpunct">,</span><spanclass="mspace"style="marginβright:0.1667em;"></span><spanclass="mord"><spanclass="mordmathnormal"style="marginβright:0.03588em;">y</span><spanclass="msupsub"><spanclass="vlistβtvlistβt2"><spanclass="vlistβr"><spanclass="vlist"style="height:0.3011em;"><spanstyle="top:β2.55em;marginβleft:β0.0359em;marginβright:0.05em;"><spanclass="pstrut"style="height:2.7em;"></span><spanclass="sizingresetβsize6size3mtight"><spanclass="mordmtight">1</span></span></span></span><spanclass="vlistβs">β</span></span><spanclass="vlistβr"><spanclass="vlist"style="height:0.15em;"><span></span></span></span></span></span></span><spanclass="mclose">)</span></span></span></span>and<spanclass="katex"><spanclass="katexβmathml"><mathxmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mostretchy="false">(</mo><msub><mi>x</mi><mn>2</mn></msub><moseparator="true">,</mo><msub><mi>y</mi><mn>2</mn></msub><mostretchy="false">)</mo></mrow><annotationencoding="application/xβtex">(x2β,y2β)</annotation></semantics></math></span><spanclass="katexβhtml"ariaβhidden="true"><spanclass="base"><spanclass="strut"style="height:1em;verticalβalign:β0.25em;"></span><spanclass="mopen">(</span><spanclass="mord"><spanclass="mordmathnormal">x</span><spanclass="msupsub"><spanclass="vlistβtvlistβt2"><spanclass="vlistβr"><spanclass="vlist"style="height:0.3011em;"><spanstyle="top:β2.55em;marginβleft:0em;marginβright:0.05em;"><spanclass="pstrut"style="height:2.7em;"></span><spanclass="sizingresetβsize6size3mtight"><spanclass="mordmtight">2</span></span></span></span><spanclass="vlistβs">β</span></span><spanclass="vlistβr"><spanclass="vlist"style="height:0.15em;"><span></span></span></span></span></span></span><spanclass="mpunct">,</span><spanclass="mspace"style="marginβright:0.1667em;"></span><spanclass="mord"><spanclass="mordmathnormal"style="marginβright:0.03588em;">y</span><spanclass="msupsub"><spanclass="vlistβtvlistβt2"><spanclass="vlistβr"><spanclass="vlist"style="height:0.3011em;"><spanstyle="top:β2.55em;marginβleft:β0.0359em;marginβright:0.05em;"><spanclass="pstrut"style="height:2.7em;"></span><spanclass="sizingresetβsize6size3mtight"><spanclass="mordmtight">2</span></span></span></span><spanclass="vlistβs">β</span></span><spanclass="vlistβr"><spanclass="vlist"style="height:0.15em;"><span></span></span></span></span></span></span><spanclass="mclose">)</span></span></span></span>aretwopointsonthetableofvalues.</p><h2><strong>Q:HowdoIfindtheyβinterceptofalinearfunction?</strong></h2><p>A:Tofindtheyβinterceptofalinearfunction,youcanusethepoint(0,b)andtheslope<spanclass="katex"><spanclass="katexβmathml"><mathxmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mi>m</mi></mrow><annotationencoding="application/xβtex">m</annotation></semantics></math></span><spanclass="katexβhtml"ariaβhidden="true"><spanclass="base"><spanclass="strut"style="height:0.4306em;"></span><spanclass="mordmathnormal">m</span></span></span></span>.Youcansubstitute<spanclass="katex"><spanclass="katexβmathml"><mathxmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mi>x</mi><mo>=</mo><mn>0</mn></mrow><annotationencoding="application/xβtex">x=0</annotation></semantics></math></span><spanclass="katexβhtml"ariaβhidden="true"><spanclass="base"><spanclass="strut"style="height:0.4306em;"></span><spanclass="mordmathnormal">x</span><spanclass="mspace"style="marginβright:0.2778em;"></span><spanclass="mrel">=</span><spanclass="mspace"style="marginβright:0.2778em;"></span></span><spanclass="base"><spanclass="strut"style="height:0.6444em;"></span><spanclass="mord">0</span></span></span></span>and<spanclass="katex"><spanclass="katexβmathml"><mathxmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mi>y</mi><mo>=</mo><mi>b</mi></mrow><annotationencoding="application/xβtex">y=b</annotation></semantics></math></span><spanclass="katexβhtml"ariaβhidden="true"><spanclass="base"><spanclass="strut"style="height:0.625em;verticalβalign:β0.1944em;"></span><spanclass="mordmathnormal"style="marginβright:0.03588em;">y</span><spanclass="mspace"style="marginβright:0.2778em;"></span><spanclass="mrel">=</span><spanclass="mspace"style="marginβright:0.2778em;"></span></span><spanclass="base"><spanclass="strut"style="height:0.6944em;"></span><spanclass="mordmathnormal">b</span></span></span></span>intotheequation<spanclass="katex"><spanclass="katexβmathml"><mathxmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mi>y</mi><mo>=</mo><mi>m</mi><mi>x</mi><mo>+</mo><mi>b</mi></mrow><annotationencoding="application/xβtex">y=mx+b</annotation></semantics></math></span><spanclass="katexβhtml"ariaβhidden="true"><spanclass="base"><spanclass="strut"style="height:0.625em;verticalβalign:β0.1944em;"></span><spanclass="mordmathnormal"style="marginβright:0.03588em;">y</span><spanclass="mspace"style="marginβright:0.2778em;"></span><spanclass="mrel">=</span><spanclass="mspace"style="marginβright:0.2778em;"></span></span><spanclass="base"><spanclass="strut"style="height:0.6667em;verticalβalign:β0.0833em;"></span><spanclass="mordmathnormal">m</span><spanclass="mordmathnormal">x</span><spanclass="mspace"style="marginβright:0.2222em;"></span><spanclass="mbin">+</span><spanclass="mspace"style="marginβright:0.2222em;"></span></span><spanclass="base"><spanclass="strut"style="height:0.6944em;"></span><spanclass="mordmathnormal">b</span></span></span></span>andsolvefor<spanclass="katex"><spanclass="katexβmathml"><mathxmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mi>b</mi></mrow><annotationencoding="application/xβtex">b</annotation></semantics></math></span><spanclass="katexβhtml"ariaβhidden="true"><spanclass="base"><spanclass="strut"style="height:0.6944em;"></span><spanclass="mordmathnormal">b</span></span></span></span>.</p><h2><strong>Q:Whatistheequationofalinearfunction?</strong></h2><p>A:Theequationofalinearfunctionisintheform<spanclass="katex"><spanclass="katexβmathml"><mathxmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mi>y</mi><mo>=</mo><mi>m</mi><mi>x</mi><mo>+</mo><mi>b</mi></mrow><annotationencoding="application/xβtex">y=mx+b</annotation></semantics></math></span><spanclass="katexβhtml"ariaβhidden="true"><spanclass="base"><spanclass="strut"style="height:0.625em;verticalβalign:β0.1944em;"></span><spanclass="mordmathnormal"style="marginβright:0.03588em;">y</span><spanclass="mspace"style="marginβright:0.2778em;"></span><spanclass="mrel">=</span><spanclass="mspace"style="marginβright:0.2778em;"></span></span><spanclass="base"><spanclass="strut"style="height:0.6667em;verticalβalign:β0.0833em;"></span><spanclass="mordmathnormal">m</span><spanclass="mordmathnormal">x</span><spanclass="mspace"style="marginβright:0.2222em;"></span><spanclass="mbin">+</span><spanclass="mspace"style="marginβright:0.2222em;"></span></span><spanclass="base"><spanclass="strut"style="height:0.6944em;"></span><spanclass="mordmathnormal">b</span></span></span></span>,where<spanclass="katex"><spanclass="katexβmathml"><mathxmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mi>m</mi></mrow><annotationencoding="application/xβtex">m</annotation></semantics></math></span><spanclass="katexβhtml"ariaβhidden="true"><spanclass="base"><spanclass="strut"style="height:0.4306em;"></span><spanclass="mordmathnormal">m</span></span></span></span>istheslopeand<spanclass="katex"><spanclass="katexβmathml"><mathxmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mi>b</mi></mrow><annotationencoding="application/xβtex">b</annotation></semantics></math></span><spanclass="katexβhtml"ariaβhidden="true"><spanclass="base"><spanclass="strut"style="height:0.6944em;"></span><spanclass="mordmathnormal">b</span></span></span></span>istheyβintercept.</p><h2><strong>Q:HowdoIwritetheequationofalinearfunction?</strong></h2><p>A:Towritetheequationofalinearfunction,youneedtofindtheslopeandyβintercept.Onceyouhavefoundtheslopeandyβintercept,youcanwritetheequationofthelinearfunctionintheform<spanclass="katex"><spanclass="katexβmathml"><mathxmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mi>y</mi><mo>=</mo><mi>m</mi><mi>x</mi><mo>+</mo><mi>b</mi></mrow><annotationencoding="application/xβtex">y=mx+b</annotation></semantics></math></span><spanclass="katexβhtml"ariaβhidden="true"><spanclass="base"><spanclass="strut"style="height:0.625em;verticalβalign:β0.1944em;"></span><spanclass="mordmathnormal"style="marginβright:0.03588em;">y</span><spanclass="mspace"style="marginβright:0.2778em;"></span><spanclass="mrel">=</span><spanclass="mspace"style="marginβright:0.2778em;"></span></span><spanclass="base"><spanclass="strut"style="height:0.6667em;verticalβalign:β0.0833em;"></span><spanclass="mordmathnormal">m</span><spanclass="mordmathnormal">x</span><spanclass="mspace"style="marginβright:0.2222em;"></span><spanclass="mbin">+</span><spanclass="mspace"style="marginβright:0.2222em;"></span></span><spanclass="base"><spanclass="strut"style="height:0.6944em;"></span><spanclass="mordmathnormal">b</span></span></span></span>.</p><h2><strong>Q:Whatisthesignificanceoftheslopeandyβinterceptinalinearfunction?</strong></h2><p>A:Theslopeandyβinterceptareimportantcomponentsofalinearfunction.Thesloperepresentstherateofchangeofthefunction,whiletheyβinterceptrepresentsthepointwherethefunctionintersectstheyβaxis.</p><h2><strong>Q:Canalinearfunctionhaveanegativeslope?</strong></h2><p>A:Yes,alinearfunctioncanhaveanegativeslope.Anegativeslopeindicatesthatthefunctionisdecreasingastheinputvalueincreases.</p><h2><strong>Q:Canalinearfunctionhaveazeroslope?</strong></h2><p>A:Yes,alinearfunctioncanhaveazeroslope.Azeroslopeindicatesthatthefunctionisahorizontalline.</p><h2><strong>Q:Canalinearfunctionhaveafractionalslope?</strong></h2><p>A:Yes,alinearfunctioncanhaveafractionalslope.Afractionalslopeindicatesthatthefunctionisalinewithaslopethatisafraction.</p><h2><strong>Q:Canalinearfunctionhaveanegativeyβintercept?</strong></h2><p>A:Yes,alinearfunctioncanhaveanegativeyβintercept.Anegativeyβinterceptindicatesthatthefunctionintersectstheyβaxisbelowtheorigin.</p><h2><strong>Q:Canalinearfunctionhaveazeroyβintercept?</strong></h2><p>A:Yes,alinearfunctioncanhaveazeroyβintercept.Azeroyβinterceptindicatesthatthefunctionintersectstheyβaxisattheorigin.</p><h2><strong>Q:Canalinearfunctionhaveafractionalyβintercept?</strong></h2><p>A:Yes,alinearfunctioncanhaveafractionalyβintercept.Afractionalyβinterceptindicatesthatthefunctionintersectstheyβaxisatapointthatisafractionoftheunit.</p><h2><strong>Conclusion</strong></h2><p>Inthisarticle,wehaveansweredsomeofthefrequentlyaskedquestionsaboutthetableofvaluesrepresentsalinearfunction.Wehavediscussedthedefinitionofalinearfunction,howtofindtheslopeandyβintercept,andhowtowritetheequationofalinearfunction.Wehavealsodiscussedthesignificanceoftheslopeandyβinterceptinalinearfunctionandansweredsomecommonquestionsaboutlinearfunctions.</p>