The Molar Mass Of Sucrose \left( C_{12}H_{22}O_{11} \right ] Is 342.3 G/mol 342.3 \, \text{g/mol} 342.3 G/mol . A Chemist Has A 0.500 Mol 0.500 \, \text{mol} 0.500 Mol Sample Of Sucrose. What Is The Mass, In Grams, Of This Sample?A. 171 Grams B. 342 Grams C. 500

Understanding the Molar Mass of Sucrose

The molar mass of a substance is a crucial concept in chemistry that represents the mass of one mole of that substance. In the case of sucrose, denoted by the chemical formula $\left( C_{12}H_{22}O_{11} \right)$, its molar mass is $342.3 \, \text{g/mol}$. This value signifies that one mole of sucrose weighs $342.3 \, \text{grams}$.

Calculating the Mass of a Sucrose Sample

To determine the mass of a sample of sucrose, we need to know the number of moles present in that sample. Given that a chemist has a $0.500 \, \text{mol}$ sample of sucrose, we can use the molar mass of sucrose to calculate the mass of this sample.

The Formula for Calculating Mass from Moles

The formula to calculate the mass of a substance from its moles is given by:

$$\text{Mass} = \text{Number of Moles} \times \text{Molar Mass}$$

Applying the Formula to the Sucrose Sample

Substituting the given values into the formula, we get:

$$\text{Mass} = 0.500 \, \text{mol} \times 342.3 \, \text{g/mol}$$

Performing the Calculation

To find the mass of the sucrose sample, we multiply the number of moles by the molar mass:

$$\text{Mass} = 0.500 \times 342.3 = 171.15 \, \text{grams}$$

Rounding the Answer

Rounding the calculated mass to the nearest whole number, we get:

$$\text{Mass} \approx 171 \, \text{grams}$$

Conclusion

In conclusion, the mass of a $0.500 \, \text{mol}$ sample of sucrose is approximately $171 \, \text{grams}$. This calculation demonstrates the importance of understanding the molar mass of a substance and its applications in chemistry.

The Significance of Molar Mass in Chemistry

Molar mass is a fundamental concept in chemistry that has numerous applications in various fields, including:

• Chemical Reactions: Molar mass is essential in determining the amount of reactants and products in chemical reactions.
• Chemical Equilibrium: Molar mass is used to calculate the equilibrium constant in chemical reactions.
• Chemical Kinetics: Molar mass is used to determine the rate of chemical reactions.
• Chemical Thermodynamics: Molar mass is used to calculate the thermodynamic properties of substances.

The Importance of Accurate Molar Mass Calculations

Accurate molar mass calculations are crucial in chemistry as they have significant implications in various fields, including:

• Chemical Synthesis: Accurate molar mass calculations are essential in determining the amount of reactants and products in chemical synthesis.
• Chemical Analysis: Accurate molar mass calculations are used to identify and quantify substances in chemical analysis.
• Chemical Engineering: Accurate molar mass calculations are used to design and optimize chemical processes.

Conclusion

In conclusion, the molar mass of sucrose is a fundamental concept in chemistry that has numerous applications in various fields. Accurate molar mass calculations are essential in determining the mass of a substance and its applications in chemistry.

Q: What is the molar mass of sucrose?

A: The molar mass of sucrose is $342.3 \, \text{g/mol}$.

Q: How is the molar mass of sucrose calculated?

A: The molar mass of sucrose is calculated by summing the atomic masses of its constituent atoms, which are carbon (C), hydrogen (H), and oxygen (O).

Q: What is the formula for calculating the mass of a substance from its moles?

A: The formula for calculating the mass of a substance from its moles is given by:

$$\text{Mass} = \text{Number of Moles} \times \text{Molar Mass}$$

Q: How do I calculate the mass of a sucrose sample if I know its number of moles?

A: To calculate the mass of a sucrose sample, you can use the formula:

$$\text{Mass} = \text{Number of Moles} \times 342.3 \, \text{g/mol}$$

Q: What is the mass of a $0.500 \, \text{mol}$ sample of sucrose?

A: The mass of a $0.500 \, \text{mol}$ sample of sucrose is approximately $171 \, \text{grams}$.

Q: Why is the molar mass of sucrose important in chemistry?

A: The molar mass of sucrose is important in chemistry because it is used to determine the amount of reactants and products in chemical reactions, calculate the equilibrium constant in chemical reactions, determine the rate of chemical reactions, and calculate the thermodynamic properties of substances.

Q: What are some of the applications of the molar mass of sucrose in chemistry?

A: Some of the applications of the molar mass of sucrose in chemistry include:

• Chemical Synthesis: Accurate molar mass calculations are essential in determining the amount of reactants and products in chemical synthesis.
• Chemical Analysis: Accurate molar mass calculations are used to identify and quantify substances in chemical analysis.
• Chemical Engineering: Accurate molar mass calculations are used to design and optimize chemical processes.

Q: Can I use the molar mass of sucrose to calculate the mass of other substances?

A: Yes, you can use the molar mass of sucrose to calculate the mass of other substances if you know their number of moles and their molar masses.

Q: How do I determine the molar mass of a substance?

A: To determine the molar mass of a substance, you can sum the atomic masses of its constituent atoms.

Q: What is the significance of accurate molar mass calculations in chemistry?

A: Accurate molar mass calculations are crucial in chemistry because they have significant implications in various fields, including chemical synthesis, chemical analysis, and chemical engineering.

Q: Can I use the molar mass of sucrose to calculate the number of moles of a substance?

A: No, you cannot use the molar mass of sucrose to calculate the number of moles of a substance. However, you can use the formula:

$$\text{Number of Moles} = \frac{\text{Mass}}{\text{Molar Mass}}$$

to calculate the number of moles of a substance if you know its mass and molar mass.