The Ions Formed When $MgI_2$ Dissociates In Water Are:A. $Mg^{2+}$ And $ I − I^{-} I − [/tex]B. $Mg^{2+}$ And $I^{-}$C. $ M G + Mg^{+} M G + [/tex] And $I^{-}$D. $Mg^{+}$ And
Understanding the Dissociation of $MgI_2$ in Water
When $MgI_2$ dissociates in water, it breaks down into its constituent ions. This process is known as dissociation, and it is an essential concept in chemistry. In this article, we will explore the ions formed when $MgI_2$ dissociates in water and discuss the relevant chemistry behind this process.
The Chemical Formula of $MgI_2$
The chemical formula of $MgI_2$ represents magnesium iodide, a compound composed of magnesium (Mg) and iodine (I). The subscript 2 indicates that there are two iodine atoms bonded to one magnesium atom.
The Dissociation of $MgI_2$ in Water
When $MgI_2$ is added to water, it dissociates into its constituent ions. This process can be represented by the following equation:
In this equation, $Mg^{2+}$ represents the magnesium ion, and $I^{-}$ represents the iodide ion.
The Ions Formed When $MgI_2$ Dissociates in Water
Based on the dissociation equation, the ions formed when $MgI_2$ dissociates in water are:
-
Mg^{2+}$: The magnesium ion, which has a +2 charge.
-
I^{-}$: The iodide ion, which has a -1 charge.
Why is the Correct Answer $Mg^{2+}$ and $I^{-}$?
The correct answer is $Mg^{2+}$ and $I^{-}$ because the dissociation equation shows that $MgI_2$ breaks down into one magnesium ion ($Mg^{2+}$) and two iodide ions ($I^{-}$). This is consistent with the chemical formula of $MgI_2$, which indicates that there are two iodine atoms bonded to one magnesium atom.
Why is Option C Incorrect?
Option C is incorrect because it suggests that the magnesium ion has a +1 charge ($Mg^{+}$). However, the dissociation equation shows that the magnesium ion has a +2 charge ($Mg^{2+}$).
Why is Option D Incorrect?
Option D is incorrect because it suggests that the magnesium ion has a +1 charge ($Mg^{+}$) and the iodide ion has a -1 charge ($I^{-}$). However, the dissociation equation shows that the magnesium ion has a +2 charge ($Mg^{2+}$) and the iodide ion has a -1 charge ($I^{-}$).
Conclusion
In conclusion, the ions formed when $MgI_2$ dissociates in water are $Mg^{2+}$ and $I^{-}$. This is consistent with the chemical formula of $MgI_2$ and the dissociation equation. The correct answer is $Mg^{2+}$ and $I^{-}$, and options C and D are incorrect because they suggest that the magnesium ion has a +1 charge or that the iodide ion has a -1 charge.
Frequently Asked Questions
- What are the ions formed when $MgI_2$ dissociates in water?
- The ions formed when $MgI_2$ dissociates in water are $Mg^{2+}$ and $I^{-}$.
- Why is the correct answer $Mg^{2+}$ and $I^{-}$?
- The correct answer is $Mg^{2+}$ and $I^{-}$ because the dissociation equation shows that $MgI_2$ breaks down into one magnesium ion ($Mg^{2+}$) and two iodide ions ($I^{-}$).
- Why is option C incorrect?
- Option C is incorrect because it suggests that the magnesium ion has a +1 charge ($Mg^{+}$). However, the dissociation equation shows that the magnesium ion has a +2 charge ($Mg^{2+}$).
- Why is option D incorrect?
- Option D is incorrect because it suggests that the magnesium ion has a +1 charge ($Mg^{+}$) and the iodide ion has a -1 charge ($I^{-}$). However, the dissociation equation shows that the magnesium ion has a +2 charge ($Mg^{2+}$) and the iodide ion has a -1 charge ($I^{-}$).
Key Takeaways
- The ions formed when $MgI_2$ dissociates in water are $Mg^{2+}$ and $I^{-}$.
- The correct answer is $Mg^{2+}$ and $I^{-}$ because the dissociation equation shows that $MgI_2$ breaks down into one magnesium ion ($Mg^{2+}$) and two iodide ions ($I^{-}$).
- Options C and D are incorrect because they suggest that the magnesium ion has a +1 charge or that the iodide ion has a -1 charge.
References
- Chemistry textbook by [Author's Name]
- Online resources on chemistry and dissociation
Further Reading
- [Article on the dissociation of $MgI_2$ in water](link to article)
- [Article on the chemistry of $MgI_2$](link to article)
Glossary
- Dissociation: The process by which a compound breaks down into its constituent ions.
- Magnesium ion: The ion formed when magnesium (Mg) loses two electrons.
- Iodide ion: The ion formed when iodine (I) gains one electron.
- $MgI_2$: The chemical formula for magnesium iodide, a compound composed of magnesium (Mg) and iodine (I).
Q: What are the ions formed when $MgI_2$ dissociates in water?
A: The ions formed when $MgI_2$ dissociates in water are $Mg^{2+}$ and $I^{-}$. This is consistent with the chemical formula of $MgI_2$ and the dissociation equation.
Q: Why is the correct answer $Mg^{2+}$ and $I^{-}$?
A: The correct answer is $Mg^{2+}$ and $I^{-}$ because the dissociation equation shows that $MgI_2$ breaks down into one magnesium ion ($Mg^{2+}$) and two iodide ions ($I^{-}$). This is consistent with the chemical formula of $MgI_2$, which indicates that there are two iodine atoms bonded to one magnesium atom.
Q: Why is option C incorrect?
A: Option C is incorrect because it suggests that the magnesium ion has a +1 charge ($Mg^{+}$). However, the dissociation equation shows that the magnesium ion has a +2 charge ($Mg^{2+}$).
Q: Why is option D incorrect?
A: Option D is incorrect because it suggests that the magnesium ion has a +1 charge ($Mg^{+}$) and the iodide ion has a -1 charge ($I^{-}$). However, the dissociation equation shows that the magnesium ion has a +2 charge ($Mg^{2+}$) and the iodide ion has a -1 charge ($I^{-}$).
Q: What is the chemical formula of $MgI_2$?
A: The chemical formula of $MgI_2$ is MgI2, which represents magnesium iodide, a compound composed of magnesium (Mg) and iodine (I).
Q: What is the dissociation equation for $MgI_2$?
A: The dissociation equation for $MgI_2$ is:
Q: What is the magnesium ion?
A: The magnesium ion is the ion formed when magnesium (Mg) loses two electrons. It has a +2 charge and is represented by the symbol $Mg^{2+}$.
Q: What is the iodide ion?
A: The iodide ion is the ion formed when iodine (I) gains one electron. It has a -1 charge and is represented by the symbol $I^{-}$.
Q: What is dissociation?
A: Dissociation is the process by which a compound breaks down into its constituent ions.
Q: Why is it important to understand the ions formed when $MgI_2$ dissociates in water?
A: Understanding the ions formed when $MgI_2$ dissociates in water is important because it helps us understand the chemistry of $MgI_2$ and its behavior in different environments.
Q: What are some real-world applications of understanding the ions formed when $MgI_2$ dissociates in water?
A: Understanding the ions formed when $MgI_2$ dissociates in water has several real-world applications, including:
- In the production of magnesium-based materials
- In the development of new medications
- In the study of environmental chemistry
Q: How can I learn more about the ions formed when $MgI_2$ dissociates in water?
A: You can learn more about the ions formed when $MgI_2$ dissociates in water by:
- Reading chemistry textbooks and online resources
- Conducting experiments and research
- Consulting with experts in the field of chemistry
Q: What are some common mistakes to avoid when learning about the ions formed when $MgI_2$ dissociates in water?
A: Some common mistakes to avoid when learning about the ions formed when $MgI_2$ dissociates in water include:
- Confusing the magnesium ion with the iodide ion
- Misunderstanding the dissociation equation
- Failing to consider the chemical formula of $MgI_2$
Q: How can I apply my knowledge of the ions formed when $MgI_2$ dissociates in water to real-world problems?
A: You can apply your knowledge of the ions formed when $MgI_2$ dissociates in water to real-world problems by:
- Using your understanding of the dissociation equation to develop new medications
- Applying your knowledge of the magnesium ion and iodide ion to the production of magnesium-based materials
- Using your understanding of the chemistry of $MgI_2$ to study environmental chemistry.