The Image Of A Point Is Given By The Rule $r_{y=-x}(x, Y) \rightarrow (-4, 9$\]. What Are The Coordinates Of Its Pre-image?A. $(-9, 4$\] B. $(-4, -9$\] C. $(4, 9$\] D. $(9, -4$\]

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Introduction

In mathematics, particularly in geometry and coordinate geometry, the concept of reflection is a fundamental idea that deals with the transformation of points from one position to another. When a point is reflected over a line, its image is formed, and the original point is known as the pre-image. In this article, we will explore the concept of the image of a point and its pre-image, focusing on the given rule ry=βˆ’x(x,y)β†’(βˆ’4,9)r_{y=-x}(x, y) \rightarrow (-4, 9) and determining the coordinates of its pre-image.

Understanding the Reflection Rule

The given rule ry=βˆ’x(x,y)β†’(βˆ’4,9)r_{y=-x}(x, y) \rightarrow (-4, 9) represents a reflection over the line y=βˆ’xy = -x. This line is a diagonal line that passes through the origin and has a slope of -1. When a point is reflected over this line, its xx-coordinate becomes the negative of its yy-coordinate, and its yy-coordinate becomes the negative of its xx-coordinate.

The Image of a Point

To find the image of a point (x,y)(x, y) under the reflection rule ry=βˆ’xr_{y=-x}, we need to apply the transformation. The new coordinates of the image point are given by:

(βˆ’y,βˆ’x)(-y, -x)

Using this transformation, we can find the image of any point (x,y)(x, y).

The Pre-Image of a Point

The pre-image of a point is the original point that is reflected to form the image. To find the pre-image of a point (xβ€²,yβ€²)(x', y'), we need to apply the inverse transformation of the reflection rule. The original coordinates of the pre-image point are given by:

(yβ€²,βˆ’xβ€²)(y', -x')

Using this transformation, we can find the pre-image of any point (xβ€²,yβ€²)(x', y').

Finding the Pre-Image of the Given Image

Now, let's apply the inverse transformation to find the pre-image of the given image point (βˆ’4,9)(-4, 9). We need to find the original coordinates (x,y)(x, y) that are reflected to form the image point (βˆ’4,9)(-4, 9).

Using the inverse transformation, we get:

(yβ€²,βˆ’xβ€²)=(9,βˆ’(βˆ’4))(y', -x') = (9, -(-4))

(yβ€²,βˆ’xβ€²)=(9,4)(y', -x') = (9, 4)

Therefore, the pre-image of the given image point (βˆ’4,9)(-4, 9) is the point (4,βˆ’9)(4, -9).

Conclusion

In this article, we explored the concept of the image of a point and its pre-image, focusing on the given rule ry=βˆ’x(x,y)β†’(βˆ’4,9)r_{y=-x}(x, y) \rightarrow (-4, 9). We applied the reflection rule and its inverse transformation to find the pre-image of the given image point. The pre-image of the given image point (βˆ’4,9)(-4, 9) is the point (4,βˆ’9)(4, -9). This concept is essential in mathematics, particularly in geometry and coordinate geometry, and has numerous applications in various fields.

Frequently Asked Questions

  • What is the reflection rule ry=βˆ’xr_{y=-x}?
    • The reflection rule ry=βˆ’xr_{y=-x} represents a reflection over the line y=βˆ’xy = -x.
  • How do you find the image of a point under the reflection rule ry=βˆ’xr_{y=-x}?
    • To find the image of a point (x,y)(x, y) under the reflection rule ry=βˆ’xr_{y=-x}, we need to apply the transformation: (βˆ’y,βˆ’x)(-y, -x).
  • How do you find the pre-image of a point under the reflection rule ry=βˆ’xr_{y=-x}?
    • To find the pre-image of a point (xβ€²,yβ€²)(x', y') under the reflection rule ry=βˆ’xr_{y=-x}, we need to apply the inverse transformation: (yβ€²,βˆ’xβ€²)(y', -x').

Final Answer

The pre-image of the given image point (βˆ’4,9)(-4, 9) is the point (4,βˆ’9)(4, -9).

Introduction

In our previous article, we explored the concept of the image of a point and its pre-image, focusing on the given rule ry=βˆ’x(x,y)β†’(βˆ’4,9)r_{y=-x}(x, y) \rightarrow (-4, 9). We applied the reflection rule and its inverse transformation to find the pre-image of the given image point. In this article, we will provide a Q&A section to further clarify the concept and answer any questions that readers may have.

Q&A

Q1: What is the reflection rule ry=βˆ’xr_{y=-x}?

A1: The reflection rule ry=βˆ’xr_{y=-x} represents a reflection over the line y=βˆ’xy = -x. This line is a diagonal line that passes through the origin and has a slope of -1.

Q2: How do you find the image of a point under the reflection rule ry=βˆ’xr_{y=-x}?

A2: To find the image of a point (x,y)(x, y) under the reflection rule ry=βˆ’xr_{y=-x}, we need to apply the transformation: (βˆ’y,βˆ’x)(-y, -x).

Q3: How do you find the pre-image of a point under the reflection rule ry=βˆ’xr_{y=-x}?

A3: To find the pre-image of a point (xβ€²,yβ€²)(x', y') under the reflection rule ry=βˆ’xr_{y=-x}, we need to apply the inverse transformation: (yβ€²,βˆ’xβ€²)(y', -x').

Q4: What is the difference between the image and the pre-image of a point?

A4: The image of a point is the point that is formed after applying the reflection rule, while the pre-image of a point is the original point that is reflected to form the image.

Q5: Can you provide an example of finding the pre-image of a point?

A5: Let's consider the point (βˆ’3,4)(-3, 4). To find its pre-image, we need to apply the inverse transformation: (yβ€²,βˆ’xβ€²)=(4,βˆ’(βˆ’3))=(4,3)(y', -x') = (4, -(-3)) = (4, 3). Therefore, the pre-image of the point (βˆ’3,4)(-3, 4) is the point (3,βˆ’4)(3, -4).

Q6: How do you determine the coordinates of the pre-image of a point?

A6: To determine the coordinates of the pre-image of a point, we need to apply the inverse transformation: (yβ€²,βˆ’xβ€²)(y', -x'). This will give us the original coordinates of the pre-image point.

Q7: Can you provide an example of finding the image of a point?

A7: Let's consider the point (2,βˆ’5)(2, -5). To find its image, we need to apply the transformation: (βˆ’y,βˆ’x)=(βˆ’(βˆ’5),βˆ’2)=(5,βˆ’2)(-y, -x) = (-(-5), -2) = (5, -2). Therefore, the image of the point (2,βˆ’5)(2, -5) is the point (5,βˆ’2)(5, -2).

Q8: How do you determine the coordinates of the image of a point?

A8: To determine the coordinates of the image of a point, we need to apply the transformation: (βˆ’y,βˆ’x)(-y, -x). This will give us the new coordinates of the image point.

Conclusion

In this Q&A article, we provided answers to common questions about the image of a point and its pre-image. We clarified the concept of the reflection rule ry=βˆ’xr_{y=-x} and its inverse transformation. We also provided examples of finding the pre-image and image of a point. We hope that this article has been helpful in further clarifying the concept and answering any questions that readers may have.

Frequently Asked Questions

  • What is the reflection rule ry=βˆ’xr_{y=-x}?
    • The reflection rule ry=βˆ’xr_{y=-x} represents a reflection over the line y=βˆ’xy = -x.
  • How do you find the image of a point under the reflection rule ry=βˆ’xr_{y=-x}?
    • To find the image of a point (x,y)(x, y) under the reflection rule ry=βˆ’xr_{y=-x}, we need to apply the transformation: (βˆ’y,βˆ’x)(-y, -x).
  • How do you find the pre-image of a point under the reflection rule ry=βˆ’xr_{y=-x}?
    • To find the pre-image of a point (xβ€²,yβ€²)(x', y') under the reflection rule ry=βˆ’xr_{y=-x}, we need to apply the inverse transformation: (yβ€²,βˆ’xβ€²)(y', -x').

Final Answer

The pre-image of the given image point (βˆ’4,9)(-4, 9) is the point (4,βˆ’9)(4, -9).