The Following Equation Of A Quadratic Function Is Given In Standard Form: F ( X ) = − 2 X 2 + 12 X − 13 F(x) = -2x^2 + 12x - 13 F ( X ) = − 2 X 2 + 12 X − 13 Find The Same Equation In Vertex Form, Then Enter It Below. Round Your Answers To The Nearest Tenth If Necessary.$f(x) = \square(x -

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Introduction

In mathematics, a quadratic function is a polynomial function of degree two, which means the highest power of the variable is two. The standard form of a quadratic function is given by f(x)=ax2+bx+cf(x) = ax^2 + bx + c, where aa, bb, and cc are constants. In this article, we will discuss how to convert a quadratic function from standard form to vertex form.

Standard Form to Vertex Form

The vertex form of a quadratic function is given by f(x)=a(xh)2+kf(x) = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola. To convert a quadratic function from standard form to vertex form, we need to complete the square.

Completing the Square

Completing the square is a technique used to rewrite a quadratic expression in the form of a perfect square trinomial. This can be done by adding and subtracting a constant term to the expression.

Step 1: Factor out the coefficient of x2x^2

The first step in completing the square is to factor out the coefficient of x2x^2 from the quadratic expression. In this case, the coefficient of x2x^2 is 2-2, so we can factor it out as follows:

f(x)=2(x26x)13f(x) = -2(x^2 - 6x) - 13

Step 2: Add and subtract the square of half the coefficient of xx

The next step is to add and subtract the square of half the coefficient of xx inside the parentheses. The coefficient of xx is 66, so half of it is 33. The square of 33 is 99, so we can add and subtract 99 inside the parentheses as follows:

f(x)=2(x26x+99)13f(x) = -2(x^2 - 6x + 9 - 9) - 13

Step 3: Simplify the expression

Now we can simplify the expression by combining like terms:

f(x)=2(x26x+9)+1813f(x) = -2(x^2 - 6x + 9) + 18 - 13

f(x)=2(x26x+9)+5f(x) = -2(x^2 - 6x + 9) + 5

Step 4: Write the expression in vertex form

Finally, we can write the expression in vertex form by factoring the perfect square trinomial:

f(x)=2(x3)2+5f(x) = -2(x - 3)^2 + 5

Conclusion

In this article, we discussed how to convert a quadratic function from standard form to vertex form. We used the technique of completing the square to rewrite the quadratic expression in the form of a perfect square trinomial. The vertex form of a quadratic function is given by f(x)=a(xh)2+kf(x) = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola. We can use this form to find the vertex of a parabola and to graph the parabola.

Vertex Form of the Given Quadratic Function

The vertex form of the given quadratic function is:

f(x)=2(x3)2+5f(x) = -2(x - 3)^2 + 5

Vertex of the Parabola

The vertex of the parabola is given by the point (h,k)(h, k), where hh is the value of xx that makes the expression inside the parentheses equal to zero, and kk is the value of the expression outside the parentheses. In this case, the vertex is (3,5)(3, 5).

Graph of the Parabola

The graph of the parabola is a downward-facing parabola with a vertex at (3,5)(3, 5). The parabola opens downward because the coefficient of the squared term is negative.

Example Problems

Problem 1

Find the vertex form of the quadratic function f(x)=3x212x+7f(x) = 3x^2 - 12x + 7.

Solution

To find the vertex form of the quadratic function, we need to complete the square. We can do this by factoring out the coefficient of x2x^2 and then adding and subtracting the square of half the coefficient of xx inside the parentheses.

f(x)=3(x24x)+7f(x) = 3(x^2 - 4x) + 7

f(x)=3(x24x+44)+7f(x) = 3(x^2 - 4x + 4 - 4) + 7

f(x)=3(x24x+4)12+7f(x) = 3(x^2 - 4x + 4) - 12 + 7

f(x)=3(x2)25f(x) = 3(x - 2)^2 - 5

Problem 2

Find the vertex of the parabola given by the quadratic function f(x)=2x28x+3f(x) = 2x^2 - 8x + 3.

Solution

To find the vertex of the parabola, we need to find the values of hh and kk in the vertex form of the quadratic function. We can do this by factoring out the coefficient of x2x^2 and then adding and subtracting the square of half the coefficient of xx inside the parentheses.

f(x)=2(x24x)+3f(x) = 2(x^2 - 4x) + 3

f(x)=2(x24x+44)+3f(x) = 2(x^2 - 4x + 4 - 4) + 3

f(x)=2(x24x+4)8+3f(x) = 2(x^2 - 4x + 4) - 8 + 3

f(x)=2(x2)25f(x) = 2(x - 2)^2 - 5

The vertex of the parabola is given by the point (h,k)(h, k), where hh is the value of xx that makes the expression inside the parentheses equal to zero, and kk is the value of the expression outside the parentheses. In this case, the vertex is (2,5)(2, -5).

Conclusion

Q: What is the vertex form of a quadratic function?

A: The vertex form of a quadratic function is given by f(x)=a(xh)2+kf(x) = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.

Q: How do I convert a quadratic function from standard form to vertex form?

A: To convert a quadratic function from standard form to vertex form, you need to complete the square. This involves factoring out the coefficient of x2x^2 and then adding and subtracting the square of half the coefficient of xx inside the parentheses.

Q: What is completing the square?

A: Completing the square is a technique used to rewrite a quadratic expression in the form of a perfect square trinomial. This can be done by adding and subtracting a constant term to the expression.

Q: How do I find the vertex of a parabola?

A: To find the vertex of a parabola, you need to find the values of hh and kk in the vertex form of the quadratic function. The vertex is given by the point (h,k)(h, k), where hh is the value of xx that makes the expression inside the parentheses equal to zero, and kk is the value of the expression outside the parentheses.

Q: What is the significance of the vertex of a parabola?

A: The vertex of a parabola is the highest or lowest point on the graph of the parabola. It is also the point where the parabola changes direction.

Q: How do I graph a parabola?

A: To graph a parabola, you need to find the vertex of the parabola and then use the vertex form of the quadratic function to determine the direction and shape of the parabola.

Q: What are some common mistakes to avoid when converting a quadratic function from standard form to vertex form?

A: Some common mistakes to avoid when converting a quadratic function from standard form to vertex form include:

  • Not factoring out the coefficient of x2x^2
  • Not adding and subtracting the square of half the coefficient of xx inside the parentheses
  • Not simplifying the expression after completing the square
  • Not writing the expression in vertex form

Q: How do I check my work when converting a quadratic function from standard form to vertex form?

A: To check your work when converting a quadratic function from standard form to vertex form, you can:

  • Plug in the values of xx and yy into the original and vertex forms of the quadratic function to see if they are equal
  • Graph the original and vertex forms of the quadratic function to see if they are the same
  • Use a calculator to graph the quadratic function and check if the vertex is correct

Q: What are some real-world applications of quadratic functions?

A: Quadratic functions have many real-world applications, including:

  • Modeling the trajectory of a projectile
  • Finding the maximum or minimum value of a function
  • Determining the shape and direction of a parabola
  • Solving problems in physics, engineering, and economics

Q: How do I use quadratic functions in real-world applications?

A: To use quadratic functions in real-world applications, you need to:

  • Understand the concept of quadratic functions and how to convert them from standard form to vertex form
  • Be able to graph quadratic functions and find their vertices
  • Be able to use quadratic functions to model real-world problems and solve them

Q: What are some common types of quadratic functions?

A: Some common types of quadratic functions include:

  • Linear quadratic functions: f(x)=ax+bf(x) = ax + b
  • Quadratic functions with a positive leading coefficient: f(x)=ax2+bx+cf(x) = ax^2 + bx + c
  • Quadratic functions with a negative leading coefficient: f(x)=ax2+bx+cf(x) = -ax^2 + bx + c
  • Quadratic functions with a zero leading coefficient: f(x)=bx+cf(x) = bx + c

Q: How do I determine the type of quadratic function I am working with?

A: To determine the type of quadratic function you are working with, you need to:

  • Look at the leading coefficient of the quadratic function
  • Determine if the leading coefficient is positive, negative, or zero
  • Use this information to determine the type of quadratic function you are working with.