The Expression $4x^2 + Bx - 45$, Where $b$ Is A Constant, Can Be Rewritten As $(hx + K)(x + J)$, Where $ H , K , H, K, H , K , [/tex] And $j$ Are Integer Constants. Which Of The Following Must Be An Integer?A)

by ADMIN 218 views

Introduction

In algebra, factorization is a crucial concept that helps us simplify complex expressions and solve equations. The expression 4x2+bx−454x^2 + bx - 45 is a quadratic expression that can be rewritten in the form (hx+k)(x+j)(hx + k)(x + j), where h,k,h, k, and jj are integer constants. In this article, we will explore the factorization of the given expression and determine which of the following must be an integer.

Understanding the Factorization

To factorize the expression 4x2+bx−454x^2 + bx - 45, we need to find two binomials whose product is equal to the given expression. The general form of the factorization is (hx+k)(x+j)(hx + k)(x + j). When we multiply these two binomials, we get:

(hx+k)(x+j)=hx2+hjx+kx+kj(hx + k)(x + j) = hx^2 + hjx + kx + kj

Expanding the right-hand side, we get:

hx2+(hj+k)x+kjhx^2 + (hj + k)x + kj

Comparing the coefficients of the terms on both sides, we can see that:

  • The coefficient of x2x^2 is hh.
  • The coefficient of xx is hj+khj + k.
  • The constant term is kjkj.

Equating Coefficients

Now, let's equate the coefficients of the terms in the given expression 4x2+bx−454x^2 + bx - 45 with the coefficients of the terms in the factorized form (hx+k)(x+j)(hx + k)(x + j).

  • The coefficient of x2x^2 in the given expression is 44, so we have h=4h = 4.
  • The coefficient of xx in the given expression is bb, so we have hj+k=bhj + k = b.
  • The constant term in the given expression is −45-45, so we have kj=−45kj = -45.

Solving for jj and kk

Since h=4h = 4, we can substitute this value into the equation kj=−45kj = -45 to get:

4j=−454j = -45

Dividing both sides by 44, we get:

j=−454j = -\frac{45}{4}

However, we are told that jj is an integer. Therefore, we must have j=−9j = -9 or j=5j = 5, since these are the only integer factors of −45-45 that divide 44.

Determining the Value of kk

Now that we have found the possible values of jj, we can determine the corresponding values of kk. Since kj=−45kj = -45, we have:

  • If j=−9j = -9, then k=5k = 5.
  • If j=5j = 5, then k=−9k = -9.

Conclusion

In conclusion, the expression 4x2+bx−454x^2 + bx - 45 can be rewritten as (hx+k)(x+j)(hx + k)(x + j), where h,k,h, k, and jj are integer constants. We have found that h=4h = 4 and j=−9j = -9 or j=5j = 5. Therefore, the value of kk must be 55 or −9-9, respectively.

Answer

The correct answer is that kk must be an integer.

Final Thoughts

Introduction

In our previous article, we explored the factorization of the expression 4x2+bx−454x^2 + bx - 45 and determined which of the following must be an integer. In this article, we will answer some frequently asked questions related to the factorization of the given expression.

Q: What is the general form of the factorization of the expression 4x2+bx−454x^2 + bx - 45?

A: The general form of the factorization is (hx+k)(x+j)(hx + k)(x + j), where h,k,h, k, and jj are integer constants.

Q: How do we find the values of h,k,h, k, and jj?

A: To find the values of h,k,h, k, and jj, we need to equate the coefficients of the terms in the given expression 4x2+bx−454x^2 + bx - 45 with the coefficients of the terms in the factorized form (hx+k)(x+j)(hx + k)(x + j). We have:

  • h=4h = 4
  • hj+k=bhj + k = b
  • kj=−45kj = -45

Q: What are the possible values of jj?

A: Since h=4h = 4, we can substitute this value into the equation kj=−45kj = -45 to get:

4j=−454j = -45

Dividing both sides by 44, we get:

j=−454j = -\frac{45}{4}

However, we are told that jj is an integer. Therefore, we must have j=−9j = -9 or j=5j = 5, since these are the only integer factors of −45-45 that divide 44.

Q: What are the corresponding values of kk?

A: Since kj=−45kj = -45, we have:

  • If j=−9j = -9, then k=5k = 5.
  • If j=5j = 5, then k=−9k = -9.

Q: Why must kk be an integer?

A: Since kj=−45kj = -45, and jj is an integer, kk must also be an integer.

Q: Can we find other values of h,k,h, k, and jj?

A: No, we have found all possible values of h,k,h, k, and jj that satisfy the given conditions.

Q: How can we use this factorization to solve equations?

A: We can use this factorization to solve equations by multiplying the two binomials and equating the resulting expression with the given equation.

Q: What are some real-world applications of this factorization?

A: This factorization has many real-world applications, such as solving quadratic equations that arise in physics, engineering, and economics.

Conclusion

In this article, we have answered some frequently asked questions related to the factorization of the expression 4x2+bx−454x^2 + bx - 45. We have found that kk must be an integer, and we have also found the possible values of jj and kk. This problem is a great example of how factorization can be used to simplify complex expressions and solve equations.

Final Thoughts

In this article, we have explored the factorization of the expression 4x2+bx−454x^2 + bx - 45 and answered some frequently asked questions related to the factorization. We hope that this article has been helpful in understanding the concept of factorization and its applications.