The Equation Of Line $L_1$ Is $y = 2x - 5$. The Equation Of Line $L_2$ Is $6y + Kx - 12 = 0$. Line $L_1$ Is Perpendicular To Line $L_2$. Find The Value Of $k$. You Must Show All Your

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Introduction

In this article, we will explore the concept of perpendicular lines and how to find the value of a variable in the equation of a line. We will use the given equations of two lines, L1L_1 and L2L_2, and apply the concept of perpendicularity to find the value of kk.

The Equation of Line L1L_1

The equation of line L1L_1 is given as y=2x5y = 2x - 5. This is a linear equation in the slope-intercept form, where the slope of the line is 22 and the y-intercept is 5-5.

The Equation of Line L2L_2

The equation of line L2L_2 is given as 6y+kx12=06y + kx - 12 = 0. This is a linear equation in the general form, where the coefficients of xx and yy are kk and 66, respectively.

Perpendicular Lines

Two lines are said to be perpendicular if the product of their slopes is 1-1. In other words, if the slope of one line is mm, then the slope of the other line is 1m-\frac{1}{m}.

Finding the Slope of Line L2L_2

To find the slope of line L2L_2, we need to rewrite the equation in the slope-intercept form. We can do this by isolating yy on one side of the equation.

# Import necessary modules
import sympy as sp

# Define variables
x, y, k = sp.symbols('x y k')

# Define the equation of line L2
eq = 6*y + k*x - 12

# Solve for y
y_expr = sp.solve(eq, y)[0]

# Print the expression for y
print(y_expr)

The output of the above code is:

y=k6x+2y = -\frac{k}{6}x + 2

From this expression, we can see that the slope of line L2L_2 is k6-\frac{k}{6}.

Finding the Value of kk

Since line L1L_1 is perpendicular to line L2L_2, the product of their slopes is 1-1. We can set up an equation using this information:

2×(k6)=12 \times \left(-\frac{k}{6}\right) = -1

Simplifying this equation, we get:

k3=1-\frac{k}{3} = -1

Multiplying both sides by 3-3, we get:

k=3k = 3

Therefore, the value of kk is 33.

Conclusion

In this article, we used the concept of perpendicular lines to find the value of kk in the equation of line L2L_2. We first found the slope of line L2L_2 by rewriting the equation in the slope-intercept form. Then, we used the fact that the product of the slopes of two perpendicular lines is 1-1 to set up an equation and solve for kk. The value of kk is 33.

References

Glossary

  • Perpendicular lines: Two lines that intersect at a right angle.
  • Slope: A measure of how steep a line is.
  • Slope-intercept form: A way of writing a linear equation in the form y=mx+by = mx + b, where mm is the slope and bb is the y-intercept.
  • General form: A way of writing a linear equation in the form ax+by+c=0ax + by + c = 0, where aa, bb, and cc are constants.
    The Equation of Line L1L_1 and L2L_2: Finding the Value of kk - Q&A ====================================================================

Introduction

In our previous article, we explored the concept of perpendicular lines and how to find the value of a variable in the equation of a line. We used the given equations of two lines, L1L_1 and L2L_2, and applied the concept of perpendicularity to find the value of kk. In this article, we will answer some frequently asked questions related to the topic.

Q: What is the difference between the slope-intercept form and the general form of a linear equation?

A: The slope-intercept form of a linear equation is y=mx+by = mx + b, where mm is the slope and bb is the y-intercept. The general form of a linear equation is ax+by+c=0ax + by + c = 0, where aa, bb, and cc are constants. The slope-intercept form is useful for finding the slope and y-intercept of a line, while the general form is useful for finding the equation of a line given its slope and y-intercept.

Q: How do you find the slope of a line given its equation in the general form?

A: To find the slope of a line given its equation in the general form, you need to rewrite the equation in the slope-intercept form. This can be done by isolating yy on one side of the equation. For example, if the equation is 6y+kx12=06y + kx - 12 = 0, you can rewrite it as y=k6x+2y = -\frac{k}{6}x + 2.

Q: What is the relationship between the slopes of two perpendicular lines?

A: The slopes of two perpendicular lines are negative reciprocals of each other. In other words, if the slope of one line is mm, then the slope of the other line is 1m-\frac{1}{m}.

Q: How do you find the value of kk in the equation of a line given its slope and the slope of a perpendicular line?

A: To find the value of kk in the equation of a line given its slope and the slope of a perpendicular line, you can use the fact that the product of the slopes of two perpendicular lines is 1-1. For example, if the slope of one line is 22 and the slope of a perpendicular line is k6-\frac{k}{6}, you can set up an equation using the fact that the product of the slopes is 1-1.

Q: What is the significance of the value of kk in the equation of a line?

A: The value of kk in the equation of a line is a constant that determines the slope of the line. In the equation 6y+kx12=06y + kx - 12 = 0, the value of kk determines the slope of the line. If kk is positive, the line has a positive slope. If kk is negative, the line has a negative slope.

Q: How do you determine the equation of a line given its slope and a point on the line?

A: To determine the equation of a line given its slope and a point on the line, you can use the point-slope form of a linear equation. The point-slope form is yy1=m(xx1)y - y_1 = m(x - x_1), where (x1,y1)(x_1, y_1) is a point on the line and mm is the slope.

Conclusion

In this article, we answered some frequently asked questions related to the topic of finding the value of kk in the equation of a line. We hope that this article has been helpful in clarifying any doubts that you may have had.

References

Glossary

  • Perpendicular lines: Two lines that intersect at a right angle.
  • Slope: A measure of how steep a line is.
  • Slope-intercept form: A way of writing a linear equation in the form y=mx+by = mx + b, where mm is the slope and bb is the y-intercept.
  • General form: A way of writing a linear equation in the form ax+by+c=0ax + by + c = 0, where aa, bb, and cc are constants.
  • Point-slope form: A way of writing a linear equation in the form yy1=m(xx1)y - y_1 = m(x - x_1), where (x1,y1)(x_1, y_1) is a point on the line and mm is the slope.