The Enthalpy Of Formation For C 6 H 6 ( L C_6H_6(l C 6 ​ H 6 ​ ( L ] Is 49.0 KJ/mol 49.0 \, \text{kJ/mol} 49.0 KJ/mol . Consider The Following Reaction: 6 C ( S, graphite ) + 3 H 2 ( G ) → C 6 H 6 ( L 6 \, C(\text{s, Graphite}) + 3 \, H_2(g) \rightarrow C_6H_6(l 6 C ( S, graphite ) + 3 H 2 ​ ( G ) → C 6 ​ H 6 ​ ( L ]Is The Reaction Endothermic Or Exothermic, And What Is The

Understanding the Basics of Enthalpy of Formation

The enthalpy of formation is a measure of the energy change that occurs when one mole of a compound is formed from its constituent elements in their standard states. In the given problem, the enthalpy of formation for benzene ($C_6H_6(l)$) is $49.0 \, \text{kJ/mol}$. This value indicates the energy change that occurs when one mole of benzene is formed from its constituent elements, which are carbon (in the form of graphite) and hydrogen gas.

The Reaction and Its Thermodynamics

The reaction given is: $6 \, C(\text{s, graphite}) + 3 \, H_2(g) \rightarrow C_6H_6(l)$

To determine whether this reaction is endothermic or exothermic, we need to consider the enthalpy of formation of the products and the enthalpy of the reactants. The enthalpy of formation of the products is given as $49.0 \, \text{kJ/mol}$, which is the energy change that occurs when one mole of benzene is formed.

Calculating the Enthalpy Change of the Reaction

To calculate the enthalpy change of the reaction, we need to consider the enthalpy of formation of the reactants. The enthalpy of formation of graphite is zero, as it is the standard state of carbon. The enthalpy of formation of hydrogen gas is also zero, as it is the standard state of hydrogen.

The enthalpy change of the reaction can be calculated as follows:

$\Delta H = \Delta H_f^{\circ}(\text{products}) - \Delta H_f^{\circ}(\text{reactants})$

$\Delta H = 49.0 \, \text{kJ/mol} - 0$

$\Delta H = 49.0 \, \text{kJ/mol}$

Determining the Thermodynamics of the Reaction

Since the enthalpy change of the reaction is positive, the reaction is endothermic. This means that energy is absorbed by the system during the reaction, and the reaction requires an input of energy to proceed.

Implications of the Reaction Thermodynamics

The endothermic nature of the reaction has several implications. Firstly, it means that the reaction requires an input of energy to proceed, which can be provided in the form of heat or light. Secondly, it means that the reaction is not spontaneous, and it requires a catalyst or other external factors to proceed.

Conclusion

In conclusion, the enthalpy of formation for $C_6H_6(l)$ is $49.0 \, \text{kJ/mol}$. The reaction $6 \, C(\text{s, graphite}) + 3 \, H_2(g) \rightarrow C_6H_6(l)$ is endothermic, as indicated by the positive enthalpy change of the reaction. This means that energy is absorbed by the system during the reaction, and the reaction requires an input of energy to proceed.

Frequently Asked Questions

Q: What is the enthalpy of formation of benzene?

A: The enthalpy of formation of benzene is $49.0 \, \text{kJ/mol}$.

Q: Is the reaction endothermic or exothermic?

A: The reaction is endothermic, as indicated by the positive enthalpy change of the reaction.

Q: What is the implication of the reaction thermodynamics?

A: The endothermic nature of the reaction means that it requires an input of energy to proceed, and it is not spontaneous.

References

• [1] Petrucci, R. H., Harwood, W. S., & Herring, F. G. (2006). General chemistry: Principles and modern applications. Pearson Prentice Hall.
• [2] Atkins, P. W., & De Paula, J. (2006). Physical chemistry. Oxford University Press.

Keywords

• Enthalpy of formation
• Reaction thermodynamics
• Endothermic reaction
• Exothermic reaction
• Thermodynamics of chemical reactions
  

Understanding the Basics of Enthalpy of Formation

The enthalpy of formation is a measure of the energy change that occurs when one mole of a compound is formed from its constituent elements in their standard states. In the given problem, the enthalpy of formation for benzene ($C_6H_6(l)$) is $49.0 \, \text{kJ/mol}$. This value indicates the energy change that occurs when one mole of benzene is formed from its constituent elements, which are carbon (in the form of graphite) and hydrogen gas.

Q&A: Enthalpy of Formation and Reaction Thermodynamics

Q: What is the enthalpy of formation of benzene?

A: The enthalpy of formation of benzene is $49.0 \, \text{kJ/mol}$.

Q: Is the reaction endothermic or exothermic?

A: The reaction is endothermic, as indicated by the positive enthalpy change of the reaction.

Q: What is the implication of the reaction thermodynamics?

A: The endothermic nature of the reaction means that it requires an input of energy to proceed, and it is not spontaneous.

Q: How is the enthalpy change of the reaction calculated?

A: The enthalpy change of the reaction can be calculated as follows:

$\Delta H = \Delta H_f^{\circ}(\text{products}) - \Delta H_f^{\circ}(\text{reactants})$

$\Delta H = 49.0 \, \text{kJ/mol} - 0$

$\Delta H = 49.0 \, \text{kJ/mol}$

Q: What is the significance of the enthalpy of formation in chemical reactions?

A: The enthalpy of formation is a measure of the energy change that occurs when one mole of a compound is formed from its constituent elements in their standard states. It is an important concept in understanding the thermodynamics of chemical reactions.

Q: Can you provide an example of an exothermic reaction?

A: Yes, an example of an exothermic reaction is the combustion of methane:

$CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(l)$

In this reaction, the enthalpy change is negative, indicating that energy is released during the reaction.

Q: What is the difference between endothermic and exothermic reactions?

A: Endothermic reactions are those that absorb energy from the surroundings, while exothermic reactions are those that release energy to the surroundings.

Q: Can you provide an example of an endothermic reaction?

A: Yes, an example of an endothermic reaction is the dissociation of water:

$2H_2O(l) \rightarrow 2H_2(g) + O_2(g)$

In this reaction, the enthalpy change is positive, indicating that energy is absorbed during the reaction.

Conclusion

In conclusion, the enthalpy of formation for $C_6H_6(l)$ is $49.0 \, \text{kJ/mol}$. The reaction $6 \, C(\text{s, graphite}) + 3 \, H_2(g) \rightarrow C_6H_6(l)$ is endothermic, as indicated by the positive enthalpy change of the reaction. This means that energy is absorbed by the system during the reaction, and the reaction requires an input of energy to proceed.

Frequently Asked Questions

Q: What is the enthalpy of formation of benzene?

A: The enthalpy of formation of benzene is $49.0 \, \text{kJ/mol}$.

Q: Is the reaction endothermic or exothermic?

A: The reaction is endothermic, as indicated by the positive enthalpy change of the reaction.

Q: What is the implication of the reaction thermodynamics?

A: The endothermic nature of the reaction means that it requires an input of energy to proceed, and it is not spontaneous.

References

• [1] Petrucci, R. H., Harwood, W. S., & Herring, F. G. (2006). General chemistry: Principles and modern applications. Pearson Prentice Hall.
• [2] Atkins, P. W., & De Paula, J. (2006). Physical chemistry. Oxford University Press.

Keywords

• Enthalpy of formation
• Reaction thermodynamics
• Endothermic reaction
• Exothermic reaction
• Thermodynamics of chemical reactions