The Chemical Equation Below Shows The Combustion Of Propane C 3 H 8 C_3H_8 C 3 H 8 :${ C_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O }$The Molar Mass Of Oxygen Gas O 2 O_2 O 2 Is 32.00 G/mol 32.00 \, \text{g/mol} 32.00 G/mol . The Molar Mass Of C 3 H 8 C_3H_8 C 3 H 8

Mar 11, 2025 by ADMIN 273 views

The Chemical Equation of Propane Combustion: Understanding the Molar Mass and Chemical Reaction

Chemical equations are a fundamental concept in chemistry, allowing us to understand and predict the reactions that occur between different substances. One such equation is the combustion of propane, which is represented by the chemical equation: $C_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O$ . In this article, we will delve into the details of this equation, focusing on the molar mass of oxygen gas ( $O_2$ ) and propane ( $C_3H_8$ ), and explore the significance of these values in the context of the chemical reaction.

The Molar Mass of Oxygen Gas ( $O_2$ )

The molar mass of a substance is defined as the mass of one mole of that substance, expressed in grams per mole (g/mol). For oxygen gas ( $O_2$ ), the molar mass is given as $32.00 \, \text{g/mol}$ . This value is a fundamental constant in chemistry, and it plays a crucial role in determining the amount of oxygen required for a particular reaction.

To understand the significance of the molar mass of oxygen gas, let's consider the chemical equation for the combustion of propane: $C_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O$ . In this equation, five moles of oxygen gas ( $O_2$ ) are required to react with one mole of propane ( $C_3H_8$ ). Given that the molar mass of oxygen gas is $32.00 \, \text{g/mol}$ , we can calculate the total mass of oxygen gas required for the reaction.

Calculating the Mass of Oxygen Gas Required

To calculate the mass of oxygen gas required for the reaction, we need to multiply the number of moles of oxygen gas by its molar mass. In this case, we have five moles of oxygen gas, so the total mass of oxygen gas required is:

$5 \, \text{moles} \times 32.00 \, \text{g/mol} = 160.00 \, \text{g}$

This means that 160.00 grams of oxygen gas are required to react with one mole of propane ( $C_3H_8$ ).

The Molar Mass of Propane ( $C_3H_8$ )

The molar mass of propane ( $C_3H_8$ ) is a critical value in the context of the chemical equation for its combustion. To calculate the molar mass of propane, we need to sum the atomic masses of its constituent atoms: three carbon atoms ( $C$ ) and eight hydrogen atoms ( $H$ ).

The atomic mass of carbon ( $C$ ) is $12.01 \, \text{g/mol}$ , and the atomic mass of hydrogen ( $H$ ) is $1.008 \, \text{g/mol}$ . Therefore, the molar mass of propane ( $C_3H_8$ ) can be calculated as follows:

$3 \, \text{atoms} \times 12.01 \, \text{g/mol} = 36.03 \, \text{g/mol}$ (for carbon) $8 \, \text{atoms} \times 1.008 \, \text{g/mol} = 8.064 \, \text{g/mol}$ (for hydrogen) Total molar mass of propane = $36.03 \, \text{g/mol} + 8.064 \, \text{g/mol} = 44.094 \, \text{g/mol}$

Understanding the Chemical Equation

Now that we have calculated the molar mass of oxygen gas ( $O_2$ ) and propane ( $C_3H_8$ ), let's revisit the chemical equation for the combustion of propane: $C_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O$ . In this equation, one mole of propane ( $C_3H_8$ ) reacts with five moles of oxygen gas ( $O_2$ ) to produce three moles of carbon dioxide ( $CO_2$ ) and four moles of water ( $H_2O$ ).

The molar mass of propane ( $C_3H_8$ ) is $44.094 \, \text{g/mol}$ , and the molar mass of oxygen gas ( $O_2$ ) is $32.00 \, \text{g/mol}$ . Therefore, the total mass of oxygen gas required for the reaction is:

$5 \, \text{moles} \times 32.00 \, \text{g/mol} = 160.00 \, \text{g}$

This means that 160.00 grams of oxygen gas are required to react with one mole of propane ( $C_3H_8$ ).

In conclusion, the chemical equation for the combustion of propane ( $C_3H_8$ ) is a fundamental concept in chemistry, and understanding the molar mass of oxygen gas ( $O_2$ ) and propane ( $C_3H_8$ ) is crucial in determining the amount of oxygen required for the reaction. By calculating the molar mass of propane ( $C_3H_8$ ) and oxygen gas ( $O_2$ ), we can determine the total mass of oxygen gas required for the reaction, which is essential in understanding the chemical equation.

[1] CRC Handbook of Chemistry and Physics, 97th Edition, 2016.
[2] Chemical Equations and Reactions, 2nd Edition, 2018.

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Molar Mass Calculator: A tool for calculating the molar mass of a substance.
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Frequently Asked Questions (FAQs) about the Combustion of Propane

The combustion of propane is a fundamental concept in chemistry, and understanding the chemical equation and molar masses involved is crucial in determining the amount of oxygen required for the reaction. In this article, we will address some frequently asked questions (FAQs) about the combustion of propane, providing a deeper understanding of the chemical equation and its significance.

Q: What is the chemical equation for the combustion of propane?

A: The chemical equation for the combustion of propane is: $C_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O$ .

Q: What is the molar mass of propane ( $C_3H_8$ )?

A: The molar mass of propane ( $C_3H_8$ ) is $44.094 \, \text{g/mol}$ .

Q: What is the molar mass of oxygen gas ( $O_2$ )?

A: The molar mass of oxygen gas ( $O_2$ ) is $32.00 \, \text{g/mol}$ .

Q: How much oxygen gas is required for the combustion of one mole of propane?

A: Five moles of oxygen gas are required for the combustion of one mole of propane.

Q: What is the total mass of oxygen gas required for the combustion of one mole of propane?

A: The total mass of oxygen gas required for the combustion of one mole of propane is $160.00 \, \text{g}$ .

Q: What are the products of the combustion of propane?

A: The products of the combustion of propane are three moles of carbon dioxide ( $CO_2$ ) and four moles of water ( $H_2O$ ).

Q: Why is the molar mass of propane important in the context of the chemical equation?

A: The molar mass of propane is important in the context of the chemical equation because it determines the amount of oxygen required for the reaction. By knowing the molar mass of propane, we can calculate the total mass of oxygen gas required for the reaction.

Q: Can the chemical equation for the combustion of propane be balanced?

A: Yes, the chemical equation for the combustion of propane can be balanced. The balanced equation is: $C_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O$ .

Q: What is the significance of the chemical equation for the combustion of propane?

A: The chemical equation for the combustion of propane is significant because it represents a fundamental reaction in chemistry. Understanding the chemical equation and the molar masses involved is crucial in determining the amount of oxygen required for the reaction.

In conclusion, the combustion of propane is a fundamental concept in chemistry, and understanding the chemical equation and molar masses involved is crucial in determining the amount of oxygen required for the reaction. By addressing some frequently asked questions (FAQs) about the combustion of propane, we have provided a deeper understanding of the chemical equation and its significance.

[1] CRC Handbook of Chemistry and Physics, 97th Edition, 2016.
[2] Chemical Equations and Reactions, 2nd Edition, 2018.

Chemical Equation Balancer: A tool for balancing chemical equations.
Molar Mass Calculator: A tool for calculating the molar mass of a substance.
Chemistry Online Resources: A collection of online resources for chemistry students.