The Area Of A Rectangle Is $66 \, \text{yd}^2$, And The Length Of The Rectangle Is 7 Yd Less Than Three Times The Width. Find The Dimensions Of The Rectangle.

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Introduction

In this article, we will explore the problem of finding the dimensions of a rectangle given its area and a relationship between its length and width. The area of a rectangle is given by the formula A=lwA = lw, where AA is the area, ll is the length, and ww is the width. We will use this formula to find the dimensions of the rectangle.

Problem Statement

The area of a rectangle is 66 yd266 \, \text{yd}^2, and the length of the rectangle is 7 yd less than three times the width. Let's denote the width as ww and the length as ll. We can write the relationship between the length and the width as l=3wβˆ’7l = 3w - 7.

Formulating the Equation

We know that the area of the rectangle is 66 yd266 \, \text{yd}^2, so we can write the equation lw=66lw = 66. Substituting the expression for the length l=3wβˆ’7l = 3w - 7 into this equation, we get (3wβˆ’7)w=66(3w - 7)w = 66.

Solving the Equation

Expanding the left-hand side of the equation, we get 3w2βˆ’7w=663w^2 - 7w = 66. Rearranging the terms, we get 3w2βˆ’7wβˆ’66=03w^2 - 7w - 66 = 0. This is a quadratic equation in ww.

Using the Quadratic Formula

To solve the quadratic equation 3w2βˆ’7wβˆ’66=03w^2 - 7w - 66 = 0, we can use the quadratic formula: w=βˆ’bΒ±b2βˆ’4ac2aw = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}. In this case, a=3a = 3, b=βˆ’7b = -7, and c=βˆ’66c = -66. Plugging these values into the formula, we get w=βˆ’(βˆ’7)Β±(βˆ’7)2βˆ’4(3)(βˆ’66)2(3)w = \frac{-(-7) \pm \sqrt{(-7)^2 - 4(3)(-66)}}{2(3)}.

Simplifying the Expression

Simplifying the expression under the square root, we get w=7Β±49+7926w = \frac{7 \pm \sqrt{49 + 792}}{6}. This simplifies to w=7Β±8416w = \frac{7 \pm \sqrt{841}}{6}.

Finding the Value of ww

The square root of 841 is 29, so we can simplify the expression to w=7Β±296w = \frac{7 \pm 29}{6}. This gives us two possible values for ww: w=7+296w = \frac{7 + 29}{6} and w=7βˆ’296w = \frac{7 - 29}{6}.

Calculating the Values of ww

Calculating the values of ww, we get w=366w = \frac{36}{6} and w=βˆ’226w = \frac{-22}{6}. Simplifying these expressions, we get w=6w = 6 and w=βˆ’113w = -\frac{11}{3}.

Finding the Value of ll

Since the width ww cannot be negative, we discard the solution w=βˆ’113w = -\frac{11}{3}. To find the value of the length ll, we substitute the value of ww into the expression l=3wβˆ’7l = 3w - 7. This gives us l=3(6)βˆ’7l = 3(6) - 7.

Calculating the Value of ll

Calculating the value of ll, we get l=18βˆ’7l = 18 - 7. This simplifies to l=11l = 11.

Conclusion

In this article, we found the dimensions of a rectangle given its area and a relationship between its length and width. The width of the rectangle is 6 yd, and the length is 11 yd.

The Final Answer

Introduction

In our previous article, we explored the problem of finding the dimensions of a rectangle given its area and a relationship between its length and width. In this article, we will answer some common questions related to the problem.

Q: What is the formula for the area of a rectangle?

A: The formula for the area of a rectangle is A=lwA = lw, where AA is the area, ll is the length, and ww is the width.

Q: How do I find the dimensions of a rectangle given its area and a relationship between its length and width?

A: To find the dimensions of a rectangle given its area and a relationship between its length and width, you can use the formula A=lwA = lw and substitute the expression for the length ll into the equation. This will give you a quadratic equation in ww, which you can solve using the quadratic formula.

Q: What is the quadratic formula?

A: The quadratic formula is w=βˆ’bΒ±b2βˆ’4ac2aw = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, where aa, bb, and cc are the coefficients of the quadratic equation.

Q: How do I simplify the expression under the square root in the quadratic formula?

A: To simplify the expression under the square root in the quadratic formula, you can first simplify the expression inside the square root by combining like terms. Then, you can factor the expression inside the square root, if possible, or use the square root property to simplify the expression.

Q: What is the square root property?

A: The square root property states that if x2=kx^2 = k, then x=Β±kx = \pm \sqrt{k}.

Q: How do I find the value of ll given the value of ww?

A: To find the value of ll given the value of ww, you can substitute the value of ww into the expression l=3wβˆ’7l = 3w - 7.

Q: What if the value of ww is negative?

A: If the value of ww is negative, it means that the solution is extraneous and should be discarded.

Q: Can I use the quadratic formula to solve a quadratic equation with complex solutions?

A: Yes, you can use the quadratic formula to solve a quadratic equation with complex solutions. However, you will need to use the complex conjugate property to simplify the expression.

Q: What is the complex conjugate property?

A: The complex conjugate property states that if a+bia + bi is a complex number, then its complex conjugate is aβˆ’bia - bi.

Conclusion

In this article, we answered some common questions related to finding the dimensions of a rectangle given its area and a relationship between its length and width. We hope that this article has been helpful in clarifying any confusion you may have had.

The Final Answer

The final answer is: 6,11\boxed{6, 11}