Solve The System Of Equations:1. $3x = -3 + 6y$2. − 1 3 X + 8 = Y -\frac{1}{3}x + 8 = Y − 3 1 ​ X + 8 = Y

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Introduction

In mathematics, a system of equations is a set of two or more equations that are solved simultaneously to find the values of the variables. In this article, we will focus on solving a system of two linear equations with two variables. We will use the given equations:

  1. 3x=3+6y3x = -3 + 6y
  2. 13x+8=y-\frac{1}{3}x + 8 = y

Our goal is to find the values of xx and yy that satisfy both equations.

Step 1: Write Down the Equations

The first step is to write down the given equations.

Equation 1: 3x=3+6y3x = -3 + 6y

This equation represents a linear relationship between xx and yy. We can see that xx is multiplied by 3, and yy is multiplied by 6.

Equation 2: 13x+8=y-\frac{1}{3}x + 8 = y

This equation also represents a linear relationship between xx and yy. We can see that xx is multiplied by 13-\frac{1}{3}, and the constant term is 8.

Step 2: Solve One of the Equations for One Variable

To solve the system of equations, we can start by solving one of the equations for one variable. Let's solve Equation 1 for xx.

Solving Equation 1 for xx

We can isolate xx by dividing both sides of the equation by 3.

3x3=3+6y3\frac{3x}{3} = \frac{-3 + 6y}{3}

This simplifies to:

x=1+2yx = -1 + 2y

Now we have Equation 1 solved for xx.

Step 3: Substitute the Expression for xx into the Other Equation

Next, we can substitute the expression for xx into Equation 2.

Substituting the Expression for xx into Equation 2

We can substitute x=1+2yx = -1 + 2y into Equation 2:

13(1+2y)+8=y-\frac{1}{3}(-1 + 2y) + 8 = y

This simplifies to:

1323y+8=y\frac{1}{3} - \frac{2}{3}y + 8 = y

Step 4: Simplify the Equation

Now we can simplify the equation by combining like terms.

Simplifying the Equation

We can combine the constant terms:

13+8=y23y\frac{1}{3} + 8 = y - \frac{2}{3}y

This simplifies to:

253=13y\frac{25}{3} = \frac{1}{3}y

Step 5: Solve for yy

Now we can solve for yy by multiplying both sides of the equation by 3.

Solving for yy

25=y25 = y

Now we have found the value of yy.

Step 6: Substitute the Value of yy into One of the Original Equations

Next, we can substitute the value of yy into one of the original equations to find the value of xx.

Substituting the Value of yy into Equation 1

We can substitute y=25y = 25 into Equation 1:

3x=3+6(25)3x = -3 + 6(25)

This simplifies to:

3x=3+1503x = -3 + 150

Step 7: Solve for xx

Now we can solve for xx by dividing both sides of the equation by 3.

Solving for xx

x=1473x = \frac{147}{3}

This simplifies to:

x=49x = 49

Conclusion

In this article, we have solved the system of equations using the given equations:

  1. 3x=3+6y3x = -3 + 6y
  2. 13x+8=y-\frac{1}{3}x + 8 = y

We have found the values of xx and yy that satisfy both equations. The final answer is:

x=49x = 49 y=25y = 25

Final Answer

Introduction

In our previous article, we solved the system of equations using the given equations:

  1. 3x=3+6y3x = -3 + 6y
  2. 13x+8=y-\frac{1}{3}x + 8 = y

We found the values of xx and yy that satisfy both equations. In this article, we will provide a Q&A guide to help you understand the solution and answer any questions you may have.

Q: What is a system of equations?

A: A system of equations is a set of two or more equations that are solved simultaneously to find the values of the variables.

Q: How do I know if a system of equations has a solution?

A: To determine if a system of equations has a solution, you can use the following methods:

  • Check if the equations are consistent (i.e., they have the same solution).
  • Check if the equations are inconsistent (i.e., they have no solution).
  • Use the method of substitution or elimination to solve the system of equations.

Q: What is the method of substitution?

A: The method of substitution involves solving one of the equations for one variable and then substituting that expression into the other equation.

Q: What is the method of elimination?

A: The method of elimination involves adding or subtracting the equations to eliminate one of the variables.

Q: How do I choose which method to use?

A: You can choose which method to use based on the following factors:

  • The complexity of the equations.
  • The number of variables.
  • The type of equations (e.g., linear, quadratic).

Q: What if I get stuck while solving the system of equations?

A: If you get stuck while solving the system of equations, you can try the following:

  • Check your work for errors.
  • Use a different method (e.g., substitution, elimination).
  • Ask for help from a teacher or tutor.

Q: Can I use a calculator to solve the system of equations?

A: Yes, you can use a calculator to solve the system of equations. However, it's always a good idea to check your work by hand to ensure that the solution is correct.

Q: How do I know if the solution is correct?

A: To check if the solution is correct, you can plug the values of xx and yy back into the original equations and verify that they are true.

Q: What if the solution is not unique?

A: If the solution is not unique, it means that there are multiple solutions to the system of equations. In this case, you can use the method of substitution or elimination to find the other solutions.

Conclusion

In this article, we have provided a Q&A guide to help you understand the solution to the system of equations and answer any questions you may have. We hope that this guide has been helpful in clarifying any doubts you may have had.

Final Answer

The final answer is 49,25\boxed{49, 25}.