Solve The Equation: $-\frac{\sqrt{3}}{3} - 2 \tan \theta = -\tan \theta$

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**Solve the Equation: $-\frac{\sqrt{3}}{3} - 2 \tan \theta = -\tan \theta$** ===========================================================

Introduction

In this article, we will be solving a trigonometric equation involving the tangent function. The equation is 332tanθ=tanθ-\frac{\sqrt{3}}{3} - 2 \tan \theta = -\tan \theta. We will use various trigonometric identities and properties to simplify and solve the equation.

Understanding the Equation

The given equation is 332tanθ=tanθ-\frac{\sqrt{3}}{3} - 2 \tan \theta = -\tan \theta. We can see that the equation involves the tangent function, which is a fundamental trigonometric function. The tangent function is defined as the ratio of the sine and cosine functions.

Step 1: Isolate the Tangent Function

To solve the equation, we need to isolate the tangent function. We can start by adding tanθ\tan \theta to both sides of the equation.

332tanθ+tanθ=tanθ+tanθ-\frac{\sqrt{3}}{3} - 2 \tan \theta + \tan \theta = -\tan \theta + \tan \theta

This simplifies to:

33tanθ=0-\frac{\sqrt{3}}{3} - \tan \theta = 0

Step 2: Simplify the Equation

Next, we can simplify the equation by adding 33\frac{\sqrt{3}}{3} to both sides.

33+33tanθ=0+33-\frac{\sqrt{3}}{3} + \frac{\sqrt{3}}{3} - \tan \theta = 0 + \frac{\sqrt{3}}{3}

This simplifies to:

tanθ=33-\tan \theta = \frac{\sqrt{3}}{3}

Step 3: Solve for the Tangent Function

To solve for the tangent function, we can multiply both sides of the equation by 1-1.

tanθ=33\tan \theta = -\frac{\sqrt{3}}{3}

Step 4: Find the Value of θ\theta

To find the value of θ\theta, we can use the inverse tangent function. The inverse tangent function is denoted by tan1x\tan^{-1}x.

θ=tan1(33)\theta = \tan^{-1}\left(-\frac{\sqrt{3}}{3}\right)

Q&A

Q: What is the tangent function?

A: The tangent function is a fundamental trigonometric function defined as the ratio of the sine and cosine functions.

Q: How do we isolate the tangent function in the equation?

A: We can add tanθ\tan \theta to both sides of the equation to isolate the tangent function.

Q: What is the inverse tangent function?

A: The inverse tangent function is denoted by tan1x\tan^{-1}x and is used to find the value of θ\theta.

Q: What is the value of θ\theta in the equation?

A: The value of θ\theta is tan1(33)\tan^{-1}\left(-\frac{\sqrt{3}}{3}\right).

Q: What is the range of the tangent function?

A: The range of the tangent function is all real numbers.

Q: What is the domain of the tangent function?

A: The domain of the tangent function is all real numbers except for odd multiples of π2\frac{\pi}{2}.

Q: How do we simplify the equation?

A: We can add 33\frac{\sqrt{3}}{3} to both sides of the equation to simplify it.

Q: What is the final answer to the equation?

A: The final answer to the equation is tanθ=33\tan \theta = -\frac{\sqrt{3}}{3}.

Conclusion

In this article, we solved the equation 332tanθ=tanθ-\frac{\sqrt{3}}{3} - 2 \tan \theta = -\tan \theta using various trigonometric identities and properties. We isolated the tangent function, simplified the equation, and found the value of θ\theta. We also answered several questions related to the tangent function and its properties.

Frequently Asked Questions

Q: What is the tangent function?

A: The tangent function is a fundamental trigonometric function defined as the ratio of the sine and cosine functions.

Q: How do we isolate the tangent function in the equation?

A: We can add tanθ\tan \theta to both sides of the equation to isolate the tangent function.

Q: What is the inverse tangent function?

A: The inverse tangent function is denoted by tan1x\tan^{-1}x and is used to find the value of θ\theta.

Q: What is the value of θ\theta in the equation?

A: The value of θ\theta is tan1(33)\tan^{-1}\left(-\frac{\sqrt{3}}{3}\right).

Q: What is the range of the tangent function?

A: The range of the tangent function is all real numbers.

Q: What is the domain of the tangent function?

A: The domain of the tangent function is all real numbers except for odd multiples of π2\frac{\pi}{2}.

Q: How do we simplify the equation?

A: We can add 33\frac{\sqrt{3}}{3} to both sides of the equation to simplify it.

Q: What is the final answer to the equation?

A: The final answer to the equation is tanθ=33\tan \theta = -\frac{\sqrt{3}}{3}.