Solve The Equation For { A$} . . . {K = 4a + 9ab\} A. { A = K(4 + 9b)$}$B. { A = 4(K + 9b)$}$C. { A = \frac{4 + 9b}{K}$}$D. { A = \frac{K}{4 + 9b}$}$

by ADMIN 150 views

Introduction

In algebra, solving equations is a crucial skill that helps us find the value of unknown variables. In this article, we will focus on solving the equation K=4a+9abK = 4a + 9ab for the variable aa. We will explore the different options provided and determine the correct solution.

Understanding the Equation

The given equation is K=4a+9abK = 4a + 9ab. To solve for aa, we need to isolate the variable aa on one side of the equation. The equation involves two variables, aa and bb, and a constant KK.

Option A: a = K(4 + 9b)

Let's start by analyzing option A: a=K(4+9b)a = K(4 + 9b). To determine if this is the correct solution, we need to substitute the expression for aa back into the original equation and check if it holds true.

Substituting a=K(4+9b)a = K(4 + 9b) into the original equation, we get:

K=4(K(4+9b))+9(K(4+9b))bK = 4(K(4 + 9b)) + 9(K(4 + 9b))b

Expanding and simplifying the equation, we get:

K=4K(4+9b)+9K(4+9b)bK = 4K(4 + 9b) + 9K(4 + 9b)b

K=16K+36Kb+36Kb+81Kb2K = 16K + 36Kb + 36Kb + 81Kb^2

K=16K+72Kb+81Kb2K = 16K + 72Kb + 81Kb^2

Subtracting 16K16K from both sides, we get:

−16K=72Kb+81Kb2-16K = 72Kb + 81Kb^2

Dividing both sides by −16K-16K, we get:

1=−92b−8116b21 = -\frac{9}{2}b - \frac{81}{16}b^2

This equation does not hold true for all values of bb, so option A is not the correct solution.

Option B: a = 4(K + 9b)

Next, let's analyze option B: a=4(K+9b)a = 4(K + 9b). To determine if this is the correct solution, we need to substitute the expression for aa back into the original equation and check if it holds true.

Substituting a=4(K+9b)a = 4(K + 9b) into the original equation, we get:

K=4(4(K+9b))+9(4(K+9b))bK = 4(4(K + 9b)) + 9(4(K + 9b))b

Expanding and simplifying the equation, we get:

K=16(K+9b)+36(K+9b)bK = 16(K + 9b) + 36(K + 9b)b

K=16K+144Kb+36Kb+324Kb2K = 16K + 144Kb + 36Kb + 324Kb^2

K=16K+180Kb+324Kb2K = 16K + 180Kb + 324Kb^2

Subtracting 16K16K from both sides, we get:

−16K=180Kb+324Kb2-16K = 180Kb + 324Kb^2

Dividing both sides by −16K-16K, we get:

1=−454b−814b21 = -\frac{45}{4}b - \frac{81}{4}b^2

This equation does not hold true for all values of bb, so option B is not the correct solution.

Option C: a = \frac{4 + 9b}{K}

Next, let's analyze option C: a=4+9bKa = \frac{4 + 9b}{K}. To determine if this is the correct solution, we need to substitute the expression for aa back into the original equation and check if it holds true.

Substituting a=4+9bKa = \frac{4 + 9b}{K} into the original equation, we get:

K=4(4+9bK)+9(4+9bK)bK = 4\left(\frac{4 + 9b}{K}\right) + 9\left(\frac{4 + 9b}{K}\right)b

Expanding and simplifying the equation, we get:

K=16+36bK+36+81bKbK = \frac{16 + 36b}{K} + \frac{36 + 81b}{K}b

Multiplying both sides by KK, we get:

K2=16+36b+36b+81b2K^2 = 16 + 36b + 36b + 81b^2

K2=16+72b+81b2K^2 = 16 + 72b + 81b^2

Subtracting 1616 from both sides, we get:

K2−16=72b+81b2K^2 - 16 = 72b + 81b^2

This equation does not hold true for all values of bb, so option C is not the correct solution.

Option D: a = \frac{K}{4 + 9b}

Finally, let's analyze option D: a=K4+9ba = \frac{K}{4 + 9b}. To determine if this is the correct solution, we need to substitute the expression for aa back into the original equation and check if it holds true.

Substituting a=K4+9ba = \frac{K}{4 + 9b} into the original equation, we get:

K=4(K4+9b)+9(K4+9b)bK = 4\left(\frac{K}{4 + 9b}\right) + 9\left(\frac{K}{4 + 9b}\right)b

Expanding and simplifying the equation, we get:

K=4K4+9b+36K4+9bbK = \frac{4K}{4 + 9b} + \frac{36K}{4 + 9b}b

Multiplying both sides by (4+9b)(4 + 9b), we get:

K(4+9b)=4K+36KbK(4 + 9b) = 4K + 36Kb

Expanding and simplifying the equation, we get:

4K+9Kb=4K+36Kb4K + 9Kb = 4K + 36Kb

Subtracting 4K4K from both sides, we get:

9Kb=36Kb9Kb = 36Kb

Dividing both sides by 9Kb9Kb, we get:

1=41 = 4

This equation does not hold true for all values of bb, so option D is not the correct solution.

Conclusion

After analyzing all the options, we can conclude that none of the options provided is the correct solution to the equation K=4a+9abK = 4a + 9ab for the variable aa. However, we can try to find the correct solution by isolating the variable aa on one side of the equation.

To solve for aa, we can start by subtracting 9ab9ab from both sides of the equation:

K−9ab=4aK - 9ab = 4a

Next, we can divide both sides of the equation by 44:

K−9ab4=a\frac{K - 9ab}{4} = a

Therefore, the correct solution to the equation K=4a+9abK = 4a + 9ab for the variable aa is:

a=K−9ab4a = \frac{K - 9ab}{4}

This solution can be further simplified by factoring out the common term bb:

a=K4+9ba = \frac{K}{4 + 9b}

Introduction

In our previous article, we explored the equation K=4a+9abK = 4a + 9ab and found the correct solution for the variable aa. In this article, we will provide a Q&A guide to help you understand the solution and apply it to different scenarios.

Q: What is the correct solution to the equation K=4a+9abK = 4a + 9ab for the variable aa?

A: The correct solution to the equation K=4a+9abK = 4a + 9ab for the variable aa is:

a=K4+9ba = \frac{K}{4 + 9b}

Q: How do I apply the solution to a specific problem?

A: To apply the solution to a specific problem, you need to substitute the values of KK and bb into the equation. For example, if K=10K = 10 and b=2b = 2, you can substitute these values into the equation:

a=104+9(2)a = \frac{10}{4 + 9(2)}

a=104+18a = \frac{10}{4 + 18}

a=1022a = \frac{10}{22}

a=511a = \frac{5}{11}

Q: What if the equation has multiple variables?

A: If the equation has multiple variables, you need to isolate the variable aa on one side of the equation. For example, if the equation is:

K=4a+9ab+2cK = 4a + 9ab + 2c

You can start by subtracting 2c2c from both sides of the equation:

K−2c=4a+9abK - 2c = 4a + 9ab

Next, you can divide both sides of the equation by 44:

K−2c4=a+9ab4\frac{K - 2c}{4} = a + \frac{9ab}{4}

Finally, you can subtract 9ab4\frac{9ab}{4} from both sides of the equation:

K−2c4−9ab4=a\frac{K - 2c}{4} - \frac{9ab}{4} = a

Therefore, the correct solution to the equation K=4a+9ab+2cK = 4a + 9ab + 2c for the variable aa is:

a=K−2c4−9ab4a = \frac{K - 2c}{4} - \frac{9ab}{4}

Q: How do I check if the solution is correct?

A: To check if the solution is correct, you need to substitute the expression for aa back into the original equation and check if it holds true. For example, if the solution is:

a=K4+9ba = \frac{K}{4 + 9b}

You can substitute this expression into the original equation:

K=4(K4+9b)+9(K4+9b)bK = 4\left(\frac{K}{4 + 9b}\right) + 9\left(\frac{K}{4 + 9b}\right)b

Expanding and simplifying the equation, you should get:

K=KK = K

This confirms that the solution is correct.

Q: What if I get a different solution?

A: If you get a different solution, it may be due to a mistake in the calculation or a misunderstanding of the equation. You should recheck your work and make sure that you have isolated the variable aa correctly. If you are still unsure, you can try to simplify the equation or use a different method to solve for aa.

Conclusion

In this article, we provided a Q&A guide to help you understand the solution to the equation K=4a+9abK = 4a + 9ab for the variable aa. We also discussed how to apply the solution to different scenarios and how to check if the solution is correct. By following these steps, you should be able to solve equations with multiple variables and check if the solution is correct.