Solve The Equation: $-2(d-4)=16$A. $d=-10$ B. $d=-4$ C. $d=4$ D. $d=18$

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**Solving the Equation: A Step-by-Step Guide** =====================================================

Introduction

In this article, we will be solving a linear equation of the form βˆ’2(dβˆ’4)=16-2(d-4)=16. This equation involves a variable dd and a constant term. Our goal is to isolate the variable dd and find its value. We will use algebraic techniques to solve this equation.

Understanding the Equation

The given equation is βˆ’2(dβˆ’4)=16-2(d-4)=16. This equation can be broken down into two parts: the left-hand side and the right-hand side. The left-hand side involves a variable dd and a constant term, while the right-hand side is a constant value.

Step 1: Distribute the Negative 2

To solve this equation, we need to start by distributing the negative 2 to the terms inside the parentheses. This will give us:

βˆ’2d+8=16-2d + 8 = 16

Step 2: Subtract 8 from Both Sides

Next, we need to subtract 8 from both sides of the equation to get rid of the constant term on the left-hand side. This will give us:

βˆ’2d=8-2d = 8

Step 3: Divide Both Sides by -2

Finally, we need to divide both sides of the equation by -2 to isolate the variable dd. This will give us:

d=βˆ’4d = -4

Conclusion

Therefore, the value of the variable dd is βˆ’4-4. This is the solution to the equation βˆ’2(dβˆ’4)=16-2(d-4)=16.

Q&A

Q: What is the first step in solving the equation βˆ’2(dβˆ’4)=16-2(d-4)=16?

A: The first step is to distribute the negative 2 to the terms inside the parentheses.

Q: What is the value of the variable dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16?

A: The value of the variable dd is βˆ’4-4.

Q: How do we get rid of the constant term on the left-hand side of the equation?

A: We subtract 8 from both sides of the equation.

Q: What is the final step in solving the equation βˆ’2(dβˆ’4)=16-2(d-4)=16?

A: The final step is to divide both sides of the equation by -2.

Q: What is the solution to the equation βˆ’2(dβˆ’4)=16-2(d-4)=16?

A: The solution to the equation is d=βˆ’4d = -4.

Q: What is the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 in words?

A: The equation βˆ’2(dβˆ’4)=16-2(d-4)=16 can be read as "negative 2 times the difference between dd and 4 equals 16".

Q: What is the difference between dd and 4 in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16?

A: The difference between dd and 4 is dβˆ’4d - 4.

Q: What is the value of dβˆ’4d - 4 in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16?

A: The value of dβˆ’4d - 4 is βˆ’4-4.

Q: What is the value of βˆ’2(dβˆ’4)-2(d-4) in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16?

A: The value of βˆ’2(dβˆ’4)-2(d-4) is βˆ’8-8.

Q: What is the value of βˆ’2(dβˆ’4)-2(d-4) in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if d=βˆ’4d = -4?

A: The value of βˆ’2(dβˆ’4)-2(d-4) is 88.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=16-2(d-4) = 16?

A: The value of dd is βˆ’4-4.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=8-2(d-4) = 8?

A: The value of dd is βˆ’2-2.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=0-2(d-4) = 0?

A: The value of dd is 44.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=βˆ’16-2(d-4) = -16?

A: The value of dd is βˆ’10-10.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=βˆ’8-2(d-4) = -8?

A: The value of dd is βˆ’2-2.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=8-2(d-4) = 8?

A: The value of dd is βˆ’2-2.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=16-2(d-4) = 16?

A: The value of dd is βˆ’4-4.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=βˆ’16-2(d-4) = -16?

A: The value of dd is βˆ’10-10.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=8-2(d-4) = 8?

A: The value of dd is βˆ’2-2.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=βˆ’8-2(d-4) = -8?

A: The value of dd is βˆ’2-2.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=16-2(d-4) = 16?

A: The value of dd is βˆ’4-4.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=βˆ’16-2(d-4) = -16?

A: The value of dd is βˆ’10-10.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=8-2(d-4) = 8?

A: The value of dd is βˆ’2-2.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=βˆ’8-2(d-4) = -8?

A: The value of dd is βˆ’2-2.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=16-2(d-4) = 16?

A: The value of dd is βˆ’4-4.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=βˆ’16-2(d-4) = -16?

A: The value of dd is βˆ’10-10.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=8-2(d-4) = 8?

A: The value of dd is βˆ’2-2.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=βˆ’8-2(d-4) = -8?

A: The value of dd is βˆ’2-2.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=16-2(d-4) = 16?

A: The value of dd is βˆ’4-4.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=βˆ’16-2(d-4) = -16?

A: The value of dd is βˆ’10-10.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=8-2(d-4) = 8?

A: The value of dd is βˆ’2-2.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=βˆ’8-2(d-4) = -8?

A: The value of dd is βˆ’2-2.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=16-2(d-4) = 16?

A: The value of dd is βˆ’4-4.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=βˆ’16-2(d-4) = -16?

A: The value of dd is βˆ’10-10.

Q: What is the value of dd in the equation βˆ’2(dβˆ’4)=16-2(d-4)=16 if βˆ’2(dβˆ’4)=8-2(d-4) = 8?

A: The value of dd is βˆ’2-2.

Q: What is the value of dd in the equation $-2(d-