Solve: $\ln 2x + \ln 2 = 0$x =$

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Solving the Natural Logarithm Equation: ln⁑2x+ln⁑2=0\ln 2x + \ln 2 = 0x=x =

In this article, we will delve into solving a natural logarithm equation, specifically the equation ln⁑2x+ln⁑2=0\ln 2x + \ln 2 = 0. We will use properties of logarithms to simplify the equation and solve for the variable xx. This equation is a fundamental example of how logarithms can be used to solve equations involving exponential functions.

The given equation is ln⁑2x+ln⁑2=0\ln 2x + \ln 2 = 0. To solve this equation, we need to understand the properties of logarithms. The logarithm of a product can be written as the sum of logarithms, which is known as the product rule of logarithms. This rule states that log⁑b(xy)=log⁑bx+log⁑by\log_b (xy) = \log_b x + \log_b y. Similarly, the logarithm of a quotient can be written as the difference of logarithms, which is known as the quotient rule of logarithms. This rule states that log⁑b(xy)=log⁑bxβˆ’log⁑by\log_b \left(\frac{x}{y}\right) = \log_b x - \log_b y.

Applying the Product Rule of Logarithms

We can apply the product rule of logarithms to the given equation. The product rule states that log⁑b(xy)=log⁑bx+log⁑by\log_b (xy) = \log_b x + \log_b y. In this case, we have ln⁑2x+ln⁑2\ln 2x + \ln 2. We can rewrite this as ln⁑(2xβ‹…2)\ln (2x \cdot 2), which simplifies to ln⁑4x\ln 4x.

Now that we have simplified the equation to ln⁑4x=0\ln 4x = 0, we can solve for xx. To do this, we need to use the definition of the natural logarithm function. The natural logarithm function is defined as ln⁑x=log⁑ex\ln x = \log_e x, where ee is a mathematical constant approximately equal to 2.71828. We can rewrite the equation as log⁑e4x=0\log_e 4x = 0.

Using the Definition of the Natural Logarithm

We know that the natural logarithm function is defined as ln⁑x=log⁑ex\ln x = \log_e x. Therefore, we can rewrite the equation as log⁑e4x=0\log_e 4x = 0. This means that 4x=e04x = e^0. We know that e0=1e^0 = 1, so we can simplify the equation to 4x=14x = 1.

Now that we have simplified the equation to 4x=14x = 1, we can solve for xx. To do this, we need to isolate xx on one side of the equation. We can do this by dividing both sides of the equation by 4. This gives us x=14x = \frac{1}{4}.

In this article, we solved the natural logarithm equation ln⁑2x+ln⁑2=0\ln 2x + \ln 2 = 0. We used properties of logarithms to simplify the equation and solve for the variable xx. We applied the product rule of logarithms to rewrite the equation as ln⁑4x=0\ln 4x = 0, and then used the definition of the natural logarithm function to rewrite the equation as log⁑e4x=0\log_e 4x = 0. Finally, we solved for xx by isolating it on one side of the equation. The solution to the equation is x=14x = \frac{1}{4}.

The equation ln⁑2x+ln⁑2=0\ln 2x + \ln 2 = 0 can be used to model a variety of real-world situations. For example, suppose we have a population of bacteria that grows exponentially. The equation ln⁑2x+ln⁑2=0\ln 2x + \ln 2 = 0 can be used to model the growth of the population over time. In this case, xx would represent the number of bacteria at a given time, and the equation would give us the number of bacteria at a specific time.

Here is a step-by-step solution to the equation ln⁑2x+ln⁑2=0\ln 2x + \ln 2 = 0:

  1. Apply the product rule of logarithms to rewrite the equation as ln⁑4x=0\ln 4x = 0.
  2. Use the definition of the natural logarithm function to rewrite the equation as log⁑e4x=0\log_e 4x = 0.
  3. Simplify the equation to 4x=14x = 1.
  4. Solve for xx by isolating it on one side of the equation.

When solving the equation ln⁑2x+ln⁑2=0\ln 2x + \ln 2 = 0, there are several common mistakes that students make. One common mistake is to forget to apply the product rule of logarithms. Another common mistake is to forget to use the definition of the natural logarithm function. Finally, students may make a mistake when solving for xx by not isolating it on one side of the equation.

In this article, we solved the natural logarithm equation ln⁑2x+ln⁑2=0\ln 2x + \ln 2 = 0. We used properties of logarithms to simplify the equation and solve for the variable xx. We applied the product rule of logarithms to rewrite the equation as ln⁑4x=0\ln 4x = 0, and then used the definition of the natural logarithm function to rewrite the equation as log⁑e4x=0\log_e 4x = 0. Finally, we solved for xx by isolating it on one side of the equation. The solution to the equation is x=14x = \frac{1}{4}.
Solving the Natural Logarithm Equation: ln⁑2x+ln⁑2=0\ln 2x + \ln 2 = 0x=x = Q&A

In our previous article, we solved the natural logarithm equation ln⁑2x+ln⁑2=0\ln 2x + \ln 2 = 0. We used properties of logarithms to simplify the equation and solve for the variable xx. In this article, we will answer some frequently asked questions about solving the natural logarithm equation.

Q: What is the product rule of logarithms?

A: The product rule of logarithms states that log⁑b(xy)=log⁑bx+log⁑by\log_b (xy) = \log_b x + \log_b y. This means that the logarithm of a product can be written as the sum of logarithms.

Q: How do I apply the product rule of logarithms to the equation ln⁑2x+ln⁑2=0\ln 2x + \ln 2 = 0?

A: To apply the product rule of logarithms to the equation ln⁑2x+ln⁑2=0\ln 2x + \ln 2 = 0, we can rewrite the equation as ln⁑(2xβ‹…2)=0\ln (2x \cdot 2) = 0. This simplifies to ln⁑4x=0\ln 4x = 0.

Q: What is the definition of the natural logarithm function?

A: The natural logarithm function is defined as ln⁑x=log⁑ex\ln x = \log_e x, where ee is a mathematical constant approximately equal to 2.71828.

Q: How do I use the definition of the natural logarithm function to rewrite the equation ln⁑4x=0\ln 4x = 0?

A: We can rewrite the equation ln⁑4x=0\ln 4x = 0 as log⁑e4x=0\log_e 4x = 0. This means that 4x=e04x = e^0. We know that e0=1e^0 = 1, so we can simplify the equation to 4x=14x = 1.

Q: How do I solve for xx in the equation 4x=14x = 1?

A: To solve for xx in the equation 4x=14x = 1, we need to isolate xx on one side of the equation. We can do this by dividing both sides of the equation by 4. This gives us x=14x = \frac{1}{4}.

Q: What are some common mistakes to avoid when solving the natural logarithm equation ln⁑2x+ln⁑2=0\ln 2x + \ln 2 = 0?

A: Some common mistakes to avoid when solving the natural logarithm equation ln⁑2x+ln⁑2=0\ln 2x + \ln 2 = 0 include:

  • Forgetting to apply the product rule of logarithms
  • Forgetting to use the definition of the natural logarithm function
  • Not isolating xx on one side of the equation when solving for xx

Q: What are some real-world applications of the natural logarithm equation ln⁑2x+ln⁑2=0\ln 2x + \ln 2 = 0?

A: The natural logarithm equation ln⁑2x+ln⁑2=0\ln 2x + \ln 2 = 0 can be used to model a variety of real-world situations, including:

  • The growth of a population of bacteria over time
  • The decay of a radioactive substance over time
  • The growth of a company's revenue over time

In this article, we answered some frequently asked questions about solving the natural logarithm equation ln⁑2x+ln⁑2=0\ln 2x + \ln 2 = 0. We covered topics such as the product rule of logarithms, the definition of the natural logarithm function, and common mistakes to avoid when solving the equation. We also discussed some real-world applications of the natural logarithm equation.