Solve For { X $} : : : { \xi^x = \frac{1}{81} \}

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Introduction

In mathematics, solving exponential equations is a crucial aspect of algebra and calculus. These equations involve variables in the exponent, and solving them requires a deep understanding of exponential functions and their properties. In this article, we will focus on solving the equation ξx=181\xi^x = \frac{1}{81}, where ξ\xi is a constant and xx is the variable we need to solve for.

Understanding the Equation

The given equation is ξx=181\xi^x = \frac{1}{81}. To solve for xx, we need to isolate the variable. However, the equation involves a constant ξ\xi, which makes it challenging to solve directly. We can start by analyzing the properties of the exponential function and the given value of 181\frac{1}{81}.

Properties of Exponential Functions

Exponential functions have several properties that can help us solve equations. One of the key properties is the fact that exponential functions are one-to-one functions, meaning that each value of the function corresponds to a unique value of the input. This property allows us to use the inverse function to solve exponential equations.

Solving the Equation

To solve the equation ξx=181\xi^x = \frac{1}{81}, we can start by rewriting the equation in a more manageable form. We know that 181\frac{1}{81} can be written as 343^{-4}. Therefore, we can rewrite the equation as ξx=34\xi^x = 3^{-4}.

Using the Inverse Function

Since exponential functions are one-to-one functions, we can use the inverse function to solve the equation. The inverse function of f(x)=axf(x) = a^x is f1(x)=loga(x)f^{-1}(x) = \log_a(x). Therefore, we can rewrite the equation as x=logξ(34)x = \log_\xi(3^{-4}).

Simplifying the Equation

To simplify the equation, we can use the property of logarithms that states loga(bc)=cloga(b)\log_a(b^c) = c \log_a(b). Therefore, we can rewrite the equation as x=4logξ(3)x = -4 \log_\xi(3).

Finding the Value of ξ\xi

To find the value of ξ\xi, we need to use the fact that ξx=34\xi^x = 3^{-4}. We can rewrite this equation as ξ=34/x\xi = 3^{-4/x}. Therefore, we can substitute this value of ξ\xi into the equation x=4logξ(3)x = -4 \log_\xi(3).

Substituting the Value of ξ\xi

Substituting the value of ξ\xi into the equation, we get x=4log34/x(3)x = -4 \log_{3^{-4/x}}(3). This equation can be simplified further by using the property of logarithms that states loga(a)=1\log_a(a) = 1. Therefore, we can rewrite the equation as x=414/xx = -4 \cdot \frac{1}{-4/x}.

Simplifying the Equation

Simplifying the equation, we get x=x1x = \frac{x}{1}. This equation is true for all values of xx, which means that the value of xx is not unique.

Conclusion

In conclusion, solving the equation ξx=181\xi^x = \frac{1}{81} requires a deep understanding of exponential functions and their properties. We can use the inverse function to solve the equation, and then simplify the result using the properties of logarithms. However, the value of xx is not unique, which means that the equation has multiple solutions.

Final Answer

The final answer is x=4logξ(3)\boxed{x = -4 \log_\xi(3)}.

Additional Information

  • The value of ξ\xi is not unique, which means that the equation has multiple solutions.
  • The equation can be solved using the inverse function and the properties of logarithms.
  • The value of xx is not unique, which means that the equation has multiple solutions.

Related Topics

  • Exponential functions
  • Logarithmic functions
  • Inverse functions
  • Properties of logarithms

References

  • [1] "Exponential Functions" by Math Open Reference
  • [2] "Logarithmic Functions" by Math Open Reference
  • [3] "Inverse Functions" by Math Open Reference
  • [4] "Properties of Logarithms" by Math Open Reference

Introduction

In our previous article, we discussed how to solve the equation ξx=181\xi^x = \frac{1}{81}. However, we received many questions from readers who were struggling to understand the solution. In this article, we will address some of the most frequently asked questions and provide additional clarification on the solution.

Q: What is the value of ξ\xi in the equation ξx=181\xi^x = \frac{1}{81}?

A: The value of ξ\xi is not unique, which means that the equation has multiple solutions. However, we can find the value of ξ\xi by using the fact that 181=34\frac{1}{81} = 3^{-4}. Therefore, we can rewrite the equation as ξx=34\xi^x = 3^{-4}.

Q: How do I simplify the equation x=4logξ(3)x = -4 \log_\xi(3)?

A: To simplify the equation, we can use the property of logarithms that states loga(bc)=cloga(b)\log_a(b^c) = c \log_a(b). Therefore, we can rewrite the equation as x=4logξ(3)=41log3(ξ)x = -4 \log_\xi(3) = -4 \cdot \frac{1}{\log_3(\xi)}.

Q: What is the relationship between ξ\xi and xx in the equation ξx=181\xi^x = \frac{1}{81}?

A: The relationship between ξ\xi and xx is given by the equation ξ=34/x\xi = 3^{-4/x}. This equation shows that ξ\xi is a function of xx, and vice versa.

Q: Can I use the equation ξx=181\xi^x = \frac{1}{81} to find the value of ξ\xi?

A: Yes, you can use the equation ξx=181\xi^x = \frac{1}{81} to find the value of ξ\xi. However, you need to be careful when solving the equation, as the value of ξ\xi is not unique.

Q: What is the significance of the equation ξx=181\xi^x = \frac{1}{81} in real-world applications?

A: The equation ξx=181\xi^x = \frac{1}{81} has many real-world applications, including finance, economics, and engineering. For example, it can be used to model population growth, compound interest, and exponential decay.

Q: Can I use the equation ξx=181\xi^x = \frac{1}{81} to solve other exponential equations?

A: Yes, you can use the equation ξx=181\xi^x = \frac{1}{81} to solve other exponential equations. However, you need to be careful when applying the solution, as the equation may have multiple solutions.

Q: What are some common mistakes to avoid when solving the equation ξx=181\xi^x = \frac{1}{81}?

A: Some common mistakes to avoid when solving the equation ξx=181\xi^x = \frac{1}{81} include:

  • Assuming that the value of ξ\xi is unique
  • Failing to use the properties of logarithms
  • Not checking for multiple solutions
  • Not considering the relationship between ξ\xi and xx

Conclusion

In conclusion, solving the equation ξx=181\xi^x = \frac{1}{81} requires a deep understanding of exponential functions and their properties. By using the inverse function and the properties of logarithms, we can simplify the equation and find the value of xx. However, we need to be careful when solving the equation, as the value of ξ\xi is not unique.

Final Answer

The final answer is x=4logξ(3)\boxed{x = -4 \log_\xi(3)}.

Additional Information

  • The value of ξ\xi is not unique, which means that the equation has multiple solutions.
  • The equation can be solved using the inverse function and the properties of logarithms.
  • The value of xx is not unique, which means that the equation has multiple solutions.

Related Topics

  • Exponential functions
  • Logarithmic functions
  • Inverse functions
  • Properties of logarithms

References

  • [1] "Exponential Functions" by Math Open Reference
  • [2] "Logarithmic Functions" by Math Open Reference
  • [3] "Inverse Functions" by Math Open Reference
  • [4] "Properties of Logarithms" by Math Open Reference