Solve For $x$ In The Equation $a X + 7 = 12$.A. $5 - A$ B. $\frac{5}{a}$ C. $\frac{19}{a}$ D. $19 + A$
Understanding the Equation
The given equation is . To solve for , we need to isolate the variable on one side of the equation. This involves performing algebraic operations to simplify the equation and make it easier to solve.
Isolating the Variable
To isolate , we need to get rid of the constant term on the left-hand side of the equation. We can do this by subtracting from both sides of the equation. This gives us:
Simplifying the equation, we get:
Solving for
Now that we have isolated , we can solve for its value. To do this, we need to get rid of the coefficient that is being multiplied by . We can do this by dividing both sides of the equation by . This gives us:
Simplifying the equation, we get:
Conclusion
Therefore, the solution to the equation is . This means that the value of is equal to .
Comparison with Answer Choices
Let's compare our solution with the answer choices given:
A. B. C. D.
Our solution matches answer choice B, which is .
Final Answer
The final answer is .
Step-by-Step Solution
Here's a step-by-step solution to the problem:
- Start with the given equation:
- Subtract from both sides of the equation:
- Simplify the equation:
- Divide both sides of the equation by :
- Simplify the equation:
Tips and Tricks
Here are some tips and tricks to help you solve this problem:
- Make sure to isolate the variable on one side of the equation.
- Use algebraic operations to simplify the equation and make it easier to solve.
- Pay attention to the signs of the numbers in the equation.
- Use the correct order of operations to evaluate the equation.
Common Mistakes
Here are some common mistakes to avoid when solving this problem:
- Not isolating the variable on one side of the equation.
- Not using algebraic operations to simplify the equation.
- Not paying attention to the signs of the numbers in the equation.
- Not using the correct order of operations to evaluate the equation.
Real-World Applications
This problem has real-world applications in various fields, such as:
- Algebra: This problem involves solving a linear equation, which is a fundamental concept in algebra.
- Physics: This problem can be used to model real-world situations, such as the motion of an object under the influence of a force.
- Engineering: This problem can be used to design and optimize systems, such as electrical circuits or mechanical systems.
Conclusion
In conclusion, solving the equation involves isolating the variable on one side of the equation and using algebraic operations to simplify the equation. The solution to the equation is . This problem has real-world applications in various fields, such as algebra, physics, and engineering.
Frequently Asked Questions
Q: What is the first step to solve the equation ?
A: The first step is to isolate the variable on one side of the equation. To do this, we need to get rid of the constant term on the left-hand side of the equation.
Q: How do I get rid of the constant term on the left-hand side of the equation?
A: We can get rid of the constant term by subtracting from both sides of the equation. This gives us:
Simplifying the equation, we get:
Q: What is the next step to solve the equation?
A: Now that we have isolated , we can solve for its value. To do this, we need to get rid of the coefficient that is being multiplied by . We can do this by dividing both sides of the equation by . This gives us:
Simplifying the equation, we get:
Q: What is the final answer to the equation?
A: The final answer to the equation is .
Q: How do I compare my solution with the answer choices?
A: To compare your solution with the answer choices, simply plug in the value of into each answer choice and see which one matches. In this case, our solution matches answer choice B, which is .
Q: What are some common mistakes to avoid when solving this problem?
A: Some common mistakes to avoid when solving this problem include:
- Not isolating the variable on one side of the equation.
- Not using algebraic operations to simplify the equation.
- Not paying attention to the signs of the numbers in the equation.
- Not using the correct order of operations to evaluate the equation.
Q: What are some real-world applications of this problem?
A: This problem has real-world applications in various fields, such as:
- Algebra: This problem involves solving a linear equation, which is a fundamental concept in algebra.
- Physics: This problem can be used to model real-world situations, such as the motion of an object under the influence of a force.
- Engineering: This problem can be used to design and optimize systems, such as electrical circuits or mechanical systems.
Q: How do I use this problem in a real-world scenario?
A: To use this problem in a real-world scenario, simply substitute the values of and into the equation and solve for the unknown value. For example, if and is unknown, we can substitute these values into the equation and solve for .
Q: What are some tips and tricks to help me solve this problem?
A: Some tips and tricks to help you solve this problem include:
- Make sure to isolate the variable on one side of the equation.
- Use algebraic operations to simplify the equation and make it easier to solve.
- Pay attention to the signs of the numbers in the equation.
- Use the correct order of operations to evaluate the equation.
Conclusion
In conclusion, solving the equation involves isolating the variable on one side of the equation and using algebraic operations to simplify the equation. The solution to the equation is . This problem has real-world applications in various fields, such as algebra, physics, and engineering. By following the steps outlined in this article, you can solve this problem and apply it to real-world scenarios.