Solve For $v$.$4v + 17 = 85$Simplify Your Answer As Much As Possible.$v =$

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Introduction

Solving for a variable in an algebraic equation is a fundamental concept in mathematics. In this article, we will focus on solving for the variable vv in the equation 4v+17=854v + 17 = 85. This equation is a linear equation, and we will use the method of subtraction and division to isolate the variable vv.

Understanding the Equation

The given equation is 4v+17=854v + 17 = 85. This equation states that the product of 44 and vv plus 1717 is equal to 8585. To solve for vv, we need to isolate the variable vv on one side of the equation.

Step 1: Subtract 17 from Both Sides

To isolate the term with the variable vv, we need to subtract 1717 from both sides of the equation. This will give us:

4v+17−17=85−174v + 17 - 17 = 85 - 17

Simplifying the equation, we get:

4v=684v = 68

Step 2: Divide Both Sides by 4

Now that we have isolated the term with the variable vv, we need to divide both sides of the equation by 44 to solve for vv. This will give us:

4v4=684\frac{4v}{4} = \frac{68}{4}

Simplifying the equation, we get:

v=17v = 17

Conclusion

In this article, we solved for the variable vv in the equation 4v+17=854v + 17 = 85. We used the method of subtraction and division to isolate the variable vv and found that v=17v = 17.

Final Answer

The final answer to the equation 4v+17=854v + 17 = 85 is:

v=17v = 17

Related Topics

  • Solving linear equations
  • Isolating variables
  • Algebraic manipulations

Example Problems

  • Solve for xx: 2x+5=112x + 5 = 11
  • Solve for yy: 3y−2=73y - 2 = 7
  • Solve for zz: z+4=9z + 4 = 9

Tips and Tricks

  • When solving for a variable, always isolate the variable on one side of the equation.
  • Use the order of operations (PEMDAS) to simplify the equation.
  • Check your answer by plugging it back into the original equation.

Common Mistakes

  • Forgetting to isolate the variable on one side of the equation.
  • Not simplifying the equation before solving for the variable.
  • Not checking the answer by plugging it back into the original equation.

Real-World Applications

  • Solving for a variable in an algebraic equation is a fundamental concept in mathematics and has many real-world applications, such as:
    • Physics: Solving for velocity and acceleration in motion problems.
    • Engineering: Solving for stress and strain in materials science.
    • Economics: Solving for supply and demand in market equilibrium problems.

Further Reading

  • For more information on solving linear equations, see the article "Solving Linear Equations: A Step-by-Step Guide".
  • For more information on isolating variables, see the article "Isolating Variables: A Guide to Algebraic Manipulations".
  • For more information on algebraic manipulations, see the article "Algebraic Manipulations: A Guide to Simplifying Equations".

Introduction

In our previous article, we solved for the variable vv in the equation 4v+17=854v + 17 = 85. In this article, we will answer some frequently asked questions related to solving for vv in this equation.

Q&A

Q: What is the first step in solving for vv in the equation 4v+17=854v + 17 = 85?

A: The first step in solving for vv in the equation 4v+17=854v + 17 = 85 is to subtract 1717 from both sides of the equation. This will give us 4v=684v = 68.

Q: Why do we need to subtract 1717 from both sides of the equation?

A: We need to subtract 1717 from both sides of the equation to isolate the term with the variable vv. By subtracting 1717 from both sides, we are essentially removing the constant term from the equation, which allows us to focus on solving for the variable vv.

Q: What is the next step in solving for vv in the equation 4v+17=854v + 17 = 85?

A: The next step in solving for vv in the equation 4v+17=854v + 17 = 85 is to divide both sides of the equation by 44. This will give us v=17v = 17.

Q: Why do we need to divide both sides of the equation by 44?

A: We need to divide both sides of the equation by 44 to solve for the variable vv. By dividing both sides by 44, we are essentially isolating the variable vv and finding its value.

Q: What is the final answer to the equation 4v+17=854v + 17 = 85?

A: The final answer to the equation 4v+17=854v + 17 = 85 is v=17v = 17.

Q: Can I use a calculator to solve for vv in the equation 4v+17=854v + 17 = 85?

A: Yes, you can use a calculator to solve for vv in the equation 4v+17=854v + 17 = 85. However, it's always a good idea to show your work and follow the steps outlined above to ensure that you understand the solution.

Q: What if I get a different answer when using a calculator?

A: If you get a different answer when using a calculator, it's possible that there was an error in your calculation. Double-check your work and make sure that you followed the steps outlined above.

Q: Can I use this method to solve for vv in other equations?

A: Yes, you can use this method to solve for vv in other equations. The steps outlined above are general and can be applied to any linear equation.

Related Topics

  • Solving linear equations
  • Isolating variables
  • Algebraic manipulations

Example Problems

  • Solve for xx: 2x+5=112x + 5 = 11
  • Solve for yy: 3y−2=73y - 2 = 7
  • Solve for zz: z+4=9z + 4 = 9

Tips and Tricks

  • When solving for a variable, always isolate the variable on one side of the equation.
  • Use the order of operations (PEMDAS) to simplify the equation.
  • Check your answer by plugging it back into the original equation.

Common Mistakes

  • Forgetting to isolate the variable on one side of the equation.
  • Not simplifying the equation before solving for the variable.
  • Not checking the answer by plugging it back into the original equation.

Real-World Applications

  • Solving for a variable in an algebraic equation is a fundamental concept in mathematics and has many real-world applications, such as:
    • Physics: Solving for velocity and acceleration in motion problems.
    • Engineering: Solving for stress and strain in materials science.
    • Economics: Solving for supply and demand in market equilibrium problems.

Further Reading

  • For more information on solving linear equations, see the article "Solving Linear Equations: A Step-by-Step Guide".
  • For more information on isolating variables, see the article "Isolating Variables: A Guide to Algebraic Manipulations".
  • For more information on algebraic manipulations, see the article "Algebraic Manipulations: A Guide to Simplifying Equations".