Solve For R R R In The Equation R ⋅ T 2 = 7 R \cdot T^2 = 7 R ⋅ T 2 = 7 .

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Introduction

Solving for a variable in an equation is a fundamental concept in mathematics, and it is essential to understand how to isolate the variable in a given equation. In this article, we will focus on solving for RR in the equation Rt2=7R \cdot t^2 = 7. This equation involves a quadratic term, and we will use algebraic manipulations to isolate RR.

Understanding the Equation

The given equation is Rt2=7R \cdot t^2 = 7. This equation involves a product of two variables, RR and t2t^2, which equals a constant value, 7. To solve for RR, we need to isolate RR on one side of the equation.

Isolating RR

To isolate RR, we can start by dividing both sides of the equation by t2t^2. This will cancel out the t2t^2 term on the left-hand side, leaving us with RR on the left-hand side.

R \cdot t^2 = 7
\Rightarrow \frac{R \cdot t^2}{t^2} = \frac{7}{t^2}
\Rightarrow R = \frac{7}{t^2}

Simplifying the Expression

The expression 7t2\frac{7}{t^2} can be simplified further by taking the square root of the denominator. This will give us R=7tR = \frac{\sqrt{7}}{t}.

R = \frac{7}{t^2}
\Rightarrow R = \frac{\sqrt{7}}{t}

Conclusion

In this article, we have solved for RR in the equation Rt2=7R \cdot t^2 = 7. We started by dividing both sides of the equation by t2t^2 to isolate RR, and then simplified the expression by taking the square root of the denominator. The final expression for RR is R=7tR = \frac{\sqrt{7}}{t}.

Example Use Case

Suppose we are given the value of tt as 2. We can substitute this value into the expression for RR to find the value of RR.

R = \frac{\sqrt{7}}{t}
\Rightarrow R = \frac{\sqrt{7}}{2}
\Rightarrow R = \frac{2.6457513110645907}{2}
\Rightarrow R = 1.3228756555322954

Tips and Tricks

  • When solving for a variable in an equation, it is essential to isolate the variable on one side of the equation.
  • Use algebraic manipulations, such as division and multiplication, to isolate the variable.
  • Simplify the expression by taking the square root of the denominator, if possible.

Related Topics

  • Solving for a variable in a linear equation
  • Solving for a variable in a quadratic equation
  • Algebraic manipulations

Further Reading

References

Introduction

In our previous article, we solved for RR in the equation Rt2=7R \cdot t^2 = 7. In this article, we will answer some frequently asked questions related to solving for RR in this equation.

Q: What is the first step in solving for RR in the equation Rt2=7R \cdot t^2 = 7?

A: The first step in solving for RR in the equation Rt2=7R \cdot t^2 = 7 is to divide both sides of the equation by t2t^2. This will cancel out the t2t^2 term on the left-hand side, leaving us with RR on the left-hand side.

Q: Why do we need to take the square root of the denominator when simplifying the expression for RR?

A: We need to take the square root of the denominator when simplifying the expression for RR because the denominator is a perfect square. Taking the square root of the denominator will give us a simplified expression for RR.

Q: What is the final expression for RR in the equation Rt2=7R \cdot t^2 = 7?

A: The final expression for RR in the equation Rt2=7R \cdot t^2 = 7 is R=7tR = \frac{\sqrt{7}}{t}.

Q: Can we substitute any value of tt into the expression for RR?

A: Yes, we can substitute any value of tt into the expression for RR. However, we need to make sure that the value of tt is not equal to zero, because dividing by zero is undefined.

Q: What is the value of RR when t=2t = 2?

A: When t=2t = 2, the value of RR is R=72=2.64575131106459072=1.3228756555322954R = \frac{\sqrt{7}}{2} = \frac{2.6457513110645907}{2} = 1.3228756555322954.

Q: Can we use the expression for RR to solve for tt in the equation Rt2=7R \cdot t^2 = 7?

A: Yes, we can use the expression for RR to solve for tt in the equation Rt2=7R \cdot t^2 = 7. We can rearrange the expression for RR to solve for tt, which gives us t=7Rt = \frac{\sqrt{7}}{R}.

Q: What is the value of tt when R=1R = 1?

A: When R=1R = 1, the value of tt is t=71=7=2.6457513110645907t = \frac{\sqrt{7}}{1} = \sqrt{7} = 2.6457513110645907.

Q: Can we use the expression for RR to solve for tt in the equation Rt2=7R \cdot t^2 = 7 when RR is a function of tt?

A: Yes, we can use the expression for RR to solve for tt in the equation Rt2=7R \cdot t^2 = 7 when RR is a function of tt. We can substitute the expression for RR into the equation and solve for tt.

Q: What is the value of tt when RR is a function of tt and R(t)=7tR(t) = \frac{\sqrt{7}}{t}?

A: When RR is a function of tt and R(t)=7tR(t) = \frac{\sqrt{7}}{t}, the value of tt is t=7R(t)=77t=tt = \frac{\sqrt{7}}{R(t)} = \frac{\sqrt{7}}{\frac{\sqrt{7}}{t}} = t.

Conclusion

In this article, we have answered some frequently asked questions related to solving for RR in the equation Rt2=7R \cdot t^2 = 7. We have covered topics such as the first step in solving for RR, taking the square root of the denominator, the final expression for RR, substituting values of tt, and using the expression for RR to solve for tt.

Example Use Case

Suppose we are given the value of RR as 1. We can substitute this value into the expression for tt to find the value of tt.

t = \frac{\sqrt{7}}{R}
\Rightarrow t = \frac{\sqrt{7}}{1}
\Rightarrow t = \sqrt{7}
\Rightarrow t = 2.6457513110645907

Tips and Tricks

  • When solving for a variable in an equation, it is essential to isolate the variable on one side of the equation.
  • Use algebraic manipulations, such as division and multiplication, to isolate the variable.
  • Simplify the expression by taking the square root of the denominator, if possible.
  • Use the expression for RR to solve for tt in the equation Rt2=7R \cdot t^2 = 7.

Related Topics

  • Solving for a variable in a linear equation
  • Solving for a variable in a quadratic equation
  • Algebraic manipulations

Further Reading

References