Solve For R 2 R^2 R 2 .Given: V = Π R 2 H V = \pi R^2 H V = Π R 2 H Options:A. R 2 = V ⋅ Th R^2 = V \cdot \text{th} R 2 = V ⋅ Th B. R 2 = V Π H R^2 = \frac{V}{\pi H} R 2 = Πh V ​ C. R 2 = Π H V R^2 = \frac{\pi H}{V} R 2 = V Πh ​ D. R 2 = V + Π H R^2 = V + \pi H R 2 = V + Πh

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Introduction

In mathematics, solving for a variable is a crucial skill that helps us understand and manipulate equations. In this article, we will focus on solving for r2r^2 in the given equation V=πr2hV = \pi r^2 h. We will explore the different options and determine the correct solution.

Understanding the Equation

The equation V=πr2hV = \pi r^2 h represents the volume of a cylinder, where VV is the volume, π\pi is a mathematical constant, rr is the radius, and hh is the height. To solve for r2r^2, we need to isolate the variable r2r^2 on one side of the equation.

Option A: r2=Vthr^2 = V \cdot \text{th}

This option suggests that r2r^2 is equal to the product of VV and hh. However, this is not a correct solution because it does not take into account the constant π\pi in the original equation.

Option B: r2=Vπhr^2 = \frac{V}{\pi h}

This option suggests that r2r^2 is equal to the quotient of VV and the product of π\pi and hh. To verify this solution, we can start by dividing both sides of the original equation by πh\pi h.

Vπh=πr2hπh\frac{V}{\pi h} = \frac{\pi r^2 h}{\pi h}

Simplifying the right-hand side of the equation, we get:

Vπh=r2\frac{V}{\pi h} = r^2

This confirms that option B is a correct solution.

Option C: r2=πhVr^2 = \frac{\pi h}{V}

This option suggests that r2r^2 is equal to the quotient of πh\pi h and VV. However, this is not a correct solution because it does not take into account the fact that r2r^2 is being multiplied by πh\pi h in the original equation.

Option D: r2=V+πhr^2 = V + \pi h

This option suggests that r2r^2 is equal to the sum of VV and πh\pi h. However, this is not a correct solution because it does not take into account the fact that r2r^2 is being multiplied by πh\pi h in the original equation.

Conclusion

In conclusion, the correct solution to the equation V=πr2hV = \pi r^2 h is r2=Vπhr^2 = \frac{V}{\pi h}. This solution takes into account the constant π\pi and the fact that r2r^2 is being multiplied by πh\pi h in the original equation.

Real-World Applications

Solving for r2r^2 has many real-world applications in fields such as engineering, physics, and architecture. For example, in the design of a cylindrical tank, we need to calculate the volume of the tank, which is given by the equation V=πr2hV = \pi r^2 h. By solving for r2r^2, we can determine the radius of the tank required to achieve a certain volume.

Tips and Tricks

When solving for r2r^2, it is essential to isolate the variable r2r^2 on one side of the equation. This can be done by using algebraic manipulations such as division, multiplication, and addition. Additionally, it is crucial to take into account any constants or coefficients in the original equation.

Common Mistakes

When solving for r2r^2, it is easy to make mistakes such as:

  • Failing to isolate the variable r2r^2 on one side of the equation
  • Not taking into account constants or coefficients in the original equation
  • Using incorrect algebraic manipulations

To avoid these mistakes, it is essential to carefully read and understand the original equation, and to use algebraic manipulations correctly.

Conclusion

Introduction

In our previous article, we explored the equation V=πr2hV = \pi r^2 h and solved for r2r^2. In this article, we will answer some frequently asked questions about solving for r2r^2.

Q: What is the formula for solving for r2r^2?

A: The formula for solving for r2r^2 is r2=Vπhr^2 = \frac{V}{\pi h}.

Q: What is the significance of the constant π\pi in the equation?

A: The constant π\pi is a mathematical constant that represents the ratio of a circle's circumference to its diameter. In the equation V=πr2hV = \pi r^2 h, π\pi is used to calculate the volume of a cylinder.

Q: How do I isolate the variable r2r^2 on one side of the equation?

A: To isolate the variable r2r^2 on one side of the equation, you can use algebraic manipulations such as division, multiplication, and addition. In the case of the equation V=πr2hV = \pi r^2 h, you can divide both sides of the equation by πh\pi h to get r2=Vπhr^2 = \frac{V}{\pi h}.

Q: What are some common mistakes to avoid when solving for r2r^2?

A: Some common mistakes to avoid when solving for r2r^2 include:

  • Failing to isolate the variable r2r^2 on one side of the equation
  • Not taking into account constants or coefficients in the original equation
  • Using incorrect algebraic manipulations

Q: How do I apply the formula for solving for r2r^2 in real-world situations?

A: The formula for solving for r2r^2 can be applied in various real-world situations, such as:

  • Designing a cylindrical tank: To calculate the volume of the tank, you can use the formula V=πr2hV = \pi r^2 h and solve for r2r^2.
  • Calculating the area of a circle: To calculate the area of a circle, you can use the formula A=πr2A = \pi r^2 and solve for r2r^2.

Q: What are some tips for solving for r2r^2?

A: Some tips for solving for r2r^2 include:

  • Carefully read and understand the original equation
  • Use algebraic manipulations correctly
  • Take into account constants or coefficients in the original equation
  • Check your work to ensure that the solution is correct

Q: Can I use the formula for solving for r2r^2 with different variables?

A: Yes, you can use the formula for solving for r2r^2 with different variables. For example, if you have an equation V=πr2hV = \pi r^2 h and you want to solve for hh, you can rearrange the formula to get h=Vπr2h = \frac{V}{\pi r^2}.

Conclusion

In conclusion, solving for r2r^2 is a crucial skill in mathematics that has many real-world applications. By understanding the equation V=πr2hV = \pi r^2 h and using algebraic manipulations correctly, we can determine the correct solution. We hope that this Q&A guide has been helpful in answering some of the most frequently asked questions about solving for r2r^2.