Solve For $j$.$\frac{j}{4} - 1 = 2$j =$

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Introduction

Linear equations are a fundamental concept in mathematics, and solving them is a crucial skill for students to master. In this article, we will focus on solving a specific linear equation involving the variable jj. The equation is j4−1=2\frac{j}{4} - 1 = 2, and our goal is to find the value of jj that satisfies this equation.

Understanding the Equation

Before we dive into solving the equation, let's take a closer look at its structure. The equation is a linear equation, which means it is in the form of ax+b=cax + b = c, where aa, bb, and cc are constants, and xx is the variable. In this case, the equation is j4−1=2\frac{j}{4} - 1 = 2, where jj is the variable, and the constants are 14\frac{1}{4}, −1-1, and 22.

Step 1: Add 1 to Both Sides

To solve the equation, we need to isolate the variable jj. The first step is to add 1 to both sides of the equation, which will eliminate the negative term. This gives us:

j4−1+1=2+1\frac{j}{4} - 1 + 1 = 2 + 1

Simplifying the equation, we get:

j4=3\frac{j}{4} = 3

Step 2: Multiply Both Sides by 4

Now that we have isolated the fraction, we can multiply both sides of the equation by 4 to eliminate the fraction. This gives us:

4×j4=4×34 \times \frac{j}{4} = 4 \times 3

Simplifying the equation, we get:

j=12j = 12

Conclusion

In this article, we have solved a linear equation involving the variable jj. The equation was j4−1=2\frac{j}{4} - 1 = 2, and we have found that the value of jj that satisfies this equation is j=12j = 12. We have followed a step-by-step approach to solve the equation, adding 1 to both sides and then multiplying both sides by 4 to eliminate the fraction.

Tips and Tricks

When solving linear equations, it's essential to follow the order of operations (PEMDAS):

  1. Parentheses: Evaluate expressions inside parentheses first.
  2. Exponents: Evaluate any exponential expressions next.
  3. Multiplication and Division: Evaluate multiplication and division operations from left to right.
  4. Addition and Subtraction: Finally, evaluate any addition and subtraction operations from left to right.

By following these steps and using the correct order of operations, you can solve linear equations with confidence.

Common Mistakes to Avoid

When solving linear equations, it's easy to make mistakes. Here are some common mistakes to avoid:

  • Not following the order of operations (PEMDAS)
  • Not isolating the variable correctly
  • Not checking the solution by plugging it back into the original equation

By being aware of these common mistakes, you can avoid them and ensure that your solutions are accurate.

Real-World Applications

Linear equations have numerous real-world applications. Here are a few examples:

  • Physics: Linear equations are used to describe the motion of objects under constant acceleration.
  • Engineering: Linear equations are used to design and optimize systems, such as electrical circuits and mechanical systems.
  • Economics: Linear equations are used to model economic systems and make predictions about future trends.

By understanding how to solve linear equations, you can apply this knowledge to a wide range of real-world problems.

Conclusion

Introduction

In our previous article, we explored the concept of solving linear equations and provided a step-by-step guide to finding the value of jj in the equation j4−1=2\frac{j}{4} - 1 = 2. In this article, we will continue to build on this concept by answering some frequently asked questions about solving linear equations.

Q&A

Q: What is a linear equation?

A: A linear equation is an equation in which the highest power of the variable (usually xx) is 1. It is typically written in the form of ax+b=cax + b = c, where aa, bb, and cc are constants.

Q: How do I know if an equation is linear?

A: To determine if an equation is linear, look for the following characteristics:

  • The highest power of the variable is 1.
  • The equation is in the form of ax+b=cax + b = c.
  • There are no fractional exponents or roots.

Q: What is the order of operations (PEMDAS)?

A: The order of operations (PEMDAS) is a set of rules that dictate the order in which mathematical operations should be performed. The acronym PEMDAS stands for:

  • Parentheses: Evaluate expressions inside parentheses first.
  • Exponents: Evaluate any exponential expressions next.
  • Multiplication and Division: Evaluate multiplication and division operations from left to right.
  • Addition and Subtraction: Finally, evaluate any addition and subtraction operations from left to right.

Q: How do I solve a linear equation with fractions?

A: To solve a linear equation with fractions, follow these steps:

  1. Multiply both sides of the equation by the least common multiple (LCM) of the denominators.
  2. Simplify the equation by canceling out any common factors.
  3. Isolate the variable by adding or subtracting the same value to both sides of the equation.

Q: What is the difference between a linear equation and a quadratic equation?

A: A linear equation is an equation in which the highest power of the variable is 1, while a quadratic equation is an equation in which the highest power of the variable is 2. For example:

  • Linear equation: 2x+3=52x + 3 = 5
  • Quadratic equation: x2+4x+4=0x^2 + 4x + 4 = 0

Q: Can I use a calculator to solve linear equations?

A: Yes, you can use a calculator to solve linear equations. However, it's essential to understand the underlying math and be able to verify the solution by plugging it back into the original equation.

Q: How do I check my solution to a linear equation?

A: To check your solution to a linear equation, plug the value back into the original equation and simplify. If the equation is true, then your solution is correct.

Conclusion

In this article, we have answered some frequently asked questions about solving linear equations. By understanding the basics of linear equations and following the correct order of operations, you can solve linear equations with confidence. Remember to check your solutions by plugging them back into the original equation and to use a calculator only as a tool to verify your work.

Additional Resources

For more information on solving linear equations, check out the following resources:

  • Khan Academy: Linear Equations
  • Mathway: Linear Equations
  • Wolfram Alpha: Linear Equations

Practice Problems

Try solving the following linear equations:

  1. x2+3=5\frac{x}{2} + 3 = 5
  2. 2x−4=62x - 4 = 6
  3. x3−2=1\frac{x}{3} - 2 = 1

Answer Key

  1. x=4x = 4
  2. x=5x = 5
  3. x=7x = 7