Solve For $d$.$\frac{-d}{7d+50} = \frac{1}{d+8}$There May Be 1 Or 2 Solutions.$d = \square$ Or $d = \square$

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Introduction

Solving equations involving fractions can be a challenging task, especially when dealing with variables in the denominator. In this article, we will guide you through the process of solving the equation βˆ’d7d+50=1d+8\frac{-d}{7d+50} = \frac{1}{d+8}, which may have one or two solutions. We will break down the solution into manageable steps, making it easier to understand and follow along.

Step 1: Cross-Multiply to Eliminate the Fractions

To eliminate the fractions, we will cross-multiply the two sides of the equation. This means multiplying both sides by the denominators of the fractions, which are (7d+50)(7d+50) and (d+8)(d+8).

βˆ’d7d+50=1d+8\frac{-d}{7d+50} = \frac{1}{d+8}

Cross-multiplying gives us:

βˆ’d(d+8)=1(7d+50)-d(d+8) = 1(7d+50)

Step 2: Expand and Simplify the Equation

Now, we will expand and simplify the equation by multiplying the terms inside the parentheses.

βˆ’d(d+8)=1(7d+50)-d(d+8) = 1(7d+50)

Expanding the left side gives us:

βˆ’d2βˆ’8d=7d+50-d^2 - 8d = 7d + 50

Step 3: Move All Terms to One Side of the Equation

To solve for dd, we need to move all the terms to one side of the equation. We will add d2+8dd^2 + 8d to both sides to get:

βˆ’d2βˆ’8d+7d+50=0-d^2 - 8d + 7d + 50 = 0

Simplifying the equation gives us:

βˆ’d2βˆ’d+50=0-d^2 - d + 50 = 0

Step 4: Multiply Both Sides by -1 to Simplify the Equation

To simplify the equation, we will multiply both sides by -1, which gives us:

d2+dβˆ’50=0d^2 + d - 50 = 0

Step 5: Factor the Quadratic Equation

Now, we will factor the quadratic equation to find the values of dd that satisfy the equation.

d2+dβˆ’50=0d^2 + d - 50 = 0

Factoring the equation gives us:

(d+10)(dβˆ’5)=0(d + 10)(d - 5) = 0

Step 6: Solve for dd

To find the values of dd, we will set each factor equal to zero and solve for dd.

(d+10)=0(d + 10) = 0

Solving for dd gives us:

d=βˆ’10d = -10

(dβˆ’5)=0(d - 5) = 0

Solving for dd gives us:

d=5d = 5

Conclusion

In this article, we have solved the equation βˆ’d7d+50=1d+8\frac{-d}{7d+50} = \frac{1}{d+8}, which may have one or two solutions. We have broken down the solution into manageable steps, making it easier to understand and follow along. The solutions to the equation are d=βˆ’10d = -10 and d=5d = 5. We hope this article has provided you with a clear understanding of how to solve equations involving fractions and variables in the denominator.

Final Answer

The final answer is:

d=βˆ’10d = \boxed{-10} or d=5d = \boxed{5}