Simplify The Expression To The Form \[$ A + Bi \$\]:$\[ 5i^{19} - I^{112} + 3i^{65} + 7i^{106} \\]

Introduction

In this article, we will simplify the given expression to the form a + bi. The expression is a combination of powers of the imaginary unit i. We will use the properties of i to simplify the expression and rewrite it in the desired form.

Understanding the Imaginary Unit i

The imaginary unit i is defined as the square root of -1. It is denoted by the letter i and is used to extend the real number system to the complex number system. The powers of i follow a cyclical pattern:

• i^1 = i
• i^2 = -1
• i^3 = -i
• i^4 = 1
• i^5 = i
• ...

This pattern repeats every four powers of i.

Simplifying the Expression

The given expression is:

5i^19 - i^112 + 3i^65 + 7i^106

We can simplify each term separately using the properties of i.

Simplifying i^19

Since the powers of i follow a cyclical pattern, we can find the remainder when 19 is divided by 4. The remainder is 3, so we can rewrite i^19 as i^3.

i^19 = i^3 = -i

Simplifying i^112

We can find the remainder when 112 is divided by 4. The remainder is 0, so we can rewrite i^112 as i^4.

i^112 = i^4 = 1

Simplifying i^65

We can find the remainder when 65 is divided by 4. The remainder is 1, so we can rewrite i^65 as i^1.

i^65 = i^1 = i

Simplifying i^106

We can find the remainder when 106 is divided by 4. The remainder is 2, so we can rewrite i^106 as i^2.

i^106 = i^2 = -1

Substituting the Simplified Terms

Now that we have simplified each term, we can substitute them back into the original expression.

5i^19 - i^112 + 3i^65 + 7i^106 = 5(-i) - 1 + 3i + 7(-1) = -5i - 1 + 3i - 7 = -2i - 8

Conclusion

In this article, we simplified the given expression to the form a + bi. We used the properties of the imaginary unit i to simplify each term and then substituted them back into the original expression. The simplified expression is -2i - 8.

Key Takeaways

• The powers of i follow a cyclical pattern.
• We can find the remainder when a power of i is divided by 4 to simplify it.
• The simplified expression is -2i - 8.

Further Reading

If you want to learn more about the imaginary unit i and its properties, I recommend checking out the following resources:

• Khan Academy: Imaginary Unit
• Math Is Fun: Imaginary Unit
• Wolfram MathWorld: Imaginary Unit

Final Thoughts

Introduction

In our previous article, we simplified the expression 5i^19 - i^112 + 3i^65 + 7i^106 to the form a + bi. We used the properties of the imaginary unit i to simplify each term and then substituted them back into the original expression. In this article, we will answer some frequently asked questions (FAQs) about simplifying expressions with powers of i.

Q: What is the cyclical pattern of powers of i?

A: The powers of i follow a cyclical pattern:

• i^1 = i
• i^2 = -1
• i^3 = -i
• i^4 = 1
• i^5 = i
• ...

This pattern repeats every four powers of i.

Q: How do I simplify a power of i?

A: To simplify a power of i, you need to find the remainder when the power is divided by 4. The remainder will tell you which power of i to use.

For example, if you want to simplify i^17, you can find the remainder when 17 is divided by 4. The remainder is 1, so you can rewrite i^17 as i^1.

Q: What if the remainder is 0?

A: If the remainder is 0, it means that the power of i is a multiple of 4. In this case, you can rewrite the power of i as i^4, which is equal to 1.

For example, if you want to simplify i^20, you can find the remainder when 20 is divided by 4. The remainder is 0, so you can rewrite i^20 as i^4, which is equal to 1.

Q: Can I simplify a power of i that is not a multiple of 4?

A: Yes, you can simplify a power of i that is not a multiple of 4. To do this, you need to find the remainder when the power is divided by 4. The remainder will tell you which power of i to use.

For example, if you want to simplify i^13, you can find the remainder when 13 is divided by 4. The remainder is 1, so you can rewrite i^13 as i^1.

Q: How do I handle negative powers of i?

A: To handle negative powers of i, you can use the property that i^(-n) = 1/i^n.

For example, if you want to simplify i^(-3), you can rewrite it as 1/i^3. Since i^3 = -i, you can rewrite i^(-3) as 1/(-i), which is equal to -1/i.

Q: Can I simplify a power of i that is a complex number?

A: Yes, you can simplify a power of i that is a complex number. To do this, you need to use the properties of i and the rules of exponents.

For example, if you want to simplify (i²⁾3, you can rewrite it as i^6. Since i^6 = (i²⁾3 = (-1)^3 = -1, you can simplify (i²⁾3 to -1.

Conclusion

In this article, we answered some frequently asked questions (FAQs) about simplifying expressions with powers of i. We covered topics such as the cyclical pattern of powers of i, simplifying powers of i, handling negative powers of i, and simplifying complex powers of i. We hope that this article has been helpful in answering your questions and providing you with a better understanding of simplifying expressions with powers of i.

Key Takeaways

• The powers of i follow a cyclical pattern.
• To simplify a power of i, you need to find the remainder when the power is divided by 4.
• If the remainder is 0, you can rewrite the power of i as i^4, which is equal to 1.
• To handle negative powers of i, you can use the property that i^(-n) = 1/i^n.
• To simplify a power of i that is a complex number, you need to use the properties of i and the rules of exponents.

Further Reading

If you want to learn more about simplifying expressions with powers of i, we recommend checking out the following resources:

• Khan Academy: Imaginary Unit
• Math Is Fun: Imaginary Unit
• Wolfram MathWorld: Imaginary Unit

Final Thoughts

Simplifying expressions with powers of i can be a challenging task, but with practice and patience, you can master it. Remember to use the properties of i and the rules of exponents to simplify complex powers of i. With this knowledge, you can tackle more complex expressions and become a master of simplifying expressions with powers of i.