Simplify:$\sqrt{20} \cdot \sqrt{5}$Options:A. $\sqrt{10}$B. 10C. $4 \sqrt{5}$

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Understanding the Problem

When dealing with square roots, it's essential to understand the properties of radicals and how they interact with each other. In this problem, we're given the expression 20β‹…5\sqrt{20} \cdot \sqrt{5}, and we're asked to simplify it. To simplify this expression, we need to apply the properties of radicals, specifically the property that states aβ‹…b=ab\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}.

Breaking Down the Expression

Let's break down the given expression into its prime factors. We can write 20\sqrt{20} as 22β‹…5\sqrt{2^2 \cdot 5}, and 5\sqrt{5} remains the same. Now, we can apply the property of radicals mentioned earlier to simplify the expression.

Simplifying the Expression

Using the property aβ‹…b=ab\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}, we can rewrite the expression as 22β‹…5β‹…5=22β‹…5β‹…5\sqrt{2^2 \cdot 5} \cdot \sqrt{5} = \sqrt{2^2 \cdot 5 \cdot 5}. Now, we can simplify the expression further by combining the like terms inside the square root.

Combining Like Terms

Inside the square root, we have 22β‹…5β‹…52^2 \cdot 5 \cdot 5. We can combine the like terms by multiplying the coefficients and adding the exponents. This gives us 22β‹…52\sqrt{2^2 \cdot 5^2}. Now, we can simplify the expression further by taking the square root of the product.

Simplifying the Square Root

Taking the square root of the product, we get 22β‹…52=2β‹…5=10\sqrt{2^2 \cdot 5^2} = 2 \cdot 5 = 10. However, we're not done yet. We need to consider the remaining radical, 5\sqrt{5}, which is still part of the original expression.

Combining the Remaining Radical

We can rewrite the expression as 10β‹…510 \cdot \sqrt{5}. However, we can simplify this further by recognizing that 1010 can be written as 2β‹…52 \cdot 5. This gives us 2β‹…5β‹…5=2β‹…532 \cdot 5 \cdot \sqrt{5} = 2 \cdot \sqrt{5^3}.

Simplifying the Final Expression

Now, we can simplify the final expression by taking the square root of the product. This gives us 2β‹…53=2β‹…5β‹…5=10β‹…52 \cdot \sqrt{5^3} = 2 \cdot 5 \cdot \sqrt{5} = 10 \cdot \sqrt{5}. However, we can simplify this further by recognizing that 10β‹…510 \cdot \sqrt{5} is equivalent to $10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot \sqrt{5} = 10 \cdot

Understanding the Problem

When dealing with square roots, it's essential to understand the properties of radicals and how they interact with each other. In this problem, we're given the expression 20β‹…5\sqrt{20} \cdot \sqrt{5}, and we're asked to simplify it. To simplify this expression, we need to apply the properties of radicals, specifically the property that states aβ‹…b=ab\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}.

Q&A

Q: What is the property of radicals that we need to apply to simplify the expression?

A: The property of radicals that we need to apply is aβ‹…b=ab\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}.

Q: How do we break down the expression 20\sqrt{20}?

A: We can break down 20\sqrt{20} as 22β‹…5\sqrt{2^2 \cdot 5}.

Q: What is the next step in simplifying the expression?

A: The next step is to apply the property of radicals, aβ‹…b=ab\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}, to simplify the expression.

Q: How do we simplify the expression further?

A: We can simplify the expression further by combining the like terms inside the square root.

Q: What is the final simplified expression?

A: The final simplified expression is 10β‹…510 \cdot \sqrt{5}.

Q: Can we simplify the expression further?

A: Yes, we can simplify the expression further by recognizing that 1010 can be written as 2β‹…52 \cdot 5. This gives us 2β‹…5β‹…5=2β‹…532 \cdot 5 \cdot \sqrt{5} = 2 \cdot \sqrt{5^3}.

Q: What is the final simplified expression?

A: The final simplified expression is 2β‹…53=2β‹…5β‹…5=10β‹…52 \cdot \sqrt{5^3} = 2 \cdot 5 \cdot \sqrt{5} = 10 \cdot \sqrt{5}.

Conclusion

In this article, we simplified the expression 20β‹…5\sqrt{20} \cdot \sqrt{5} by applying the properties of radicals. We broke down the expression, applied the property of radicals, and simplified the expression further by combining like terms. The final simplified expression is 10β‹…510 \cdot \sqrt{5}.

Frequently Asked Questions

Q: What is the property of radicals that we need to apply to simplify the expression?

A: The property of radicals that we need to apply is aβ‹…b=ab\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}.

Q: How do we break down the expression 20\sqrt{20}?

A: We can break down 20\sqrt{20} as 22β‹…5\sqrt{2^2 \cdot 5}.

Q: What is the next step in simplifying the expression?

A: The next step is to apply the property of radicals, aβ‹…b=ab\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}, to simplify the expression.

Q: How do we simplify the expression further?

A: We can simplify the expression further by combining the like terms inside the square root.

Q: What is the final simplified expression?

A: The final simplified expression is 10β‹…510 \cdot \sqrt{5}.

Additional Resources

Final Answer

The final answer is 10β‹…5\boxed{10 \cdot \sqrt{5}}.