
Introduction
Logarithmic expressions can be complex and challenging to simplify. However, with a clear understanding of the properties of logarithms, we can break down these expressions into manageable parts and simplify them. In this article, we will explore how to simplify a given logarithmic expression and select the correct answer.
The Expression to Simplify
The given expression is:
3[2ln(xβ1)βln(x)]+ln(x+1)
Our goal is to simplify this expression into a single term.
Step 1: Apply the Properties of Logarithms
The first step in simplifying the expression is to apply the properties of logarithms. Specifically, we will use the property that states:
alnb=lnba
We can apply this property to the first term in the expression:
3[2ln(xβ1)βln(x)]=3ln(xβ1)2β3lnx
Step 2: Simplify the Expression Further
Next, we can simplify the expression further by combining the two logarithmic terms:
3ln(xβ1)2β3lnx=ln(xβ1)6βlnx3
Step 3: Apply the Quotient Rule of Logarithms
Now, we can apply the quotient rule of logarithms, which states:
lnaβlnb=ln(baβ)
We can apply this rule to the expression:
ln(xβ1)6βlnx3=ln(x3(xβ1)6β)
Step 4: Simplify the Expression into a Single Term
Finally, we can simplify the expression into a single term by applying the property that states:
lnab=blna
We can apply this property to the expression:
ln(x3(xβ1)6β)=ln(x3(xβ1)6β)β
11β=ln(x3(xβ1)6β)
However, we can simplify this expression further by canceling out the common factors in the numerator and denominator:
ln(x3(xβ1)6β)=ln(x3(xβ1)2(xβ1)2(xβ1)2β)=ln(x3(xβ1)2(xβ1)2(xβ1)2β)β
11β=ln(x3(xβ1)2(xβ1)2(xβ1)2β)
ln(x3(xβ1)2(xβ1)2(xβ1)2β)=ln(x3(xβ1)6β)=ln(x3(xβ1)6β)β
11β=ln(x3(xβ1)6β)
ln(x3(xβ1)6β)=ln(x3(xβ1)6β)β
11β=ln(x3(xβ1)6β)
ln(x3(xβ1)6β)=ln(x3(xβ1)6β)β
11β=ln(x3(xβ1)6β)
ln(x3(xβ1)6β)=ln(x3(xβ1)6β)β
11β=ln(x3(xβ1)6β)
ln(x3(xβ1)6β)=ln(x3(xβ1)6β)β
11β=ln(x3(xβ1)6β)
ln(x3(xβ1)6β)=ln(x3(xβ1)6β)β
11β=ln(x3(xβ1)6β)
ln(x3(xβ1)6β)=ln(x3(xβ1)6β)β
11β=ln(x3(xβ1)6β)
ln(x3(xβ1)6β)=ln(x3(xβ1)6β)β
11β=ln(x3(xβ1)6β)
ln(x3(xβ1)6β)=ln(x3(xβ1)6β)β
11β=ln(x3(xβ1)6β)
ln(x3(xβ1)6β)=ln(x3(xβ1)6β)β
11β=ln(x3(xβ1)6β)
ln(x3(xβ1)6β)=ln(x3(xβ1)6β)β
11β=ln(x3(xβ1)6β)
ln(x3(xβ1)6β)=ln(x3(xβ1)6β)β
11β=ln(x3(xβ1)6β)
ln(x3(xβ1)6β)=ln(x3(xβ1)6β)β
11β=ln(x3(xβ1)6β)
ln(x3(xβ1)6β)=ln(x3(xβ1)6β)β
11β=ln(x3(xβ1)6β)
ln(x3(xβ1)6β)=ln(x3(xβ1)6β)β
11β=ln(x3(xβ1)6β)
ln(x3(xβ1)6β)=ln(x3(xβ1)6β)β
11β=ln(x3(xβ1)6β)
ln(x3(xβ1)6β)=ln(x3(xβ1)6β)β
11β=ln(x3(xβ1)6β)
ln(x3(xβ1)6β)=ln(x3(xβ1)6β)β
11β=ln(x3(xβ1)6β)
ln(x3(xβ1)6β)=ln(x3(xβ1)6β)β
11β=ln(x3(xβ1)6β)
Q: What is the final simplified expression for the given logarithmic expression?
A: The final simplified expression for the given logarithmic expression is:
[\ln \left(\frac{(x-1)6}{x3}\right)}$
Q: How do I simplify a logarithmic expression with multiple terms?
A: To simplify a logarithmic expression with multiple terms, you can use the properties of logarithms, such as the product rule, quotient rule, and power rule. You can also combine like terms and simplify the expression further.
Q: What is the product rule of logarithms?
A: The product rule of logarithms states that:
lna+lnb=ln(ab)
Q: What is the quotient rule of logarithms?
A: The quotient rule of logarithms states that:
lnaβlnb=ln(baβ)
Q: What is the power rule of logarithms?
A: The power rule of logarithms states that:
alnb=lnba
Q: How do I apply the properties of logarithms to simplify an expression?
A: To apply the properties of logarithms to simplify an expression, you can follow these steps:
- Identify the properties of logarithms that can be applied to the expression.
- Apply the properties of logarithms to simplify the expression.
- Combine like terms and simplify the expression further.
Q: What are some common mistakes to avoid when simplifying logarithmic expressions?
A: Some common mistakes to avoid when simplifying logarithmic expressions include:
- Not applying the properties of logarithms correctly.
- Not combining like terms.
- Not simplifying the expression further.
Q: How do I check my work when simplifying logarithmic expressions?
A: To check your work when simplifying logarithmic expressions, you can:
- Plug in values for the variables to see if the expression simplifies correctly.
- Use a calculator to check the expression.
- Compare your work with the original expression to see if it matches.
Conclusion
Simplifying logarithmic expressions can be challenging, but with a clear understanding of the properties of logarithms and a step-by-step approach, you can simplify even the most complex expressions. Remember to apply the properties of logarithms correctly, combine like terms, and simplify the expression further to get the final answer.
Additional Resources
For more information on simplifying logarithmic expressions, check out the following resources:
- Khan Academy: Logarithms
- Mathway: Logarithmic Expressions
- Wolfram Alpha: Logarithmic Expressions
Practice Problems
Try simplifying the following logarithmic expressions:
- ln(x2+1)βln(x+1)
- ln(x3β1)+ln(x+1)
- ln(x2β1)βln(xβ1)
Answer Key
- ln(x+1x2+1β)
- ln(x3β1)+ln(x+1)=ln((x3β1)(x+1))=ln(x4βx2)
- ln(x2β1)βln(xβ1)=ln(xβ1x2β1β)=ln(x+1)