
Introduction
In this article, we will guide you through the process of solving a given equation step by step. The equation is (4x)31ββx=0. We will break down the solution into manageable steps, making it easier to understand and follow along.
Step 1: Isolate the Variable
The first step in solving this equation is to isolate the variable x. To do this, we need to get rid of the fraction by multiplying both sides of the equation by the denominator, which is 3. This will give us:
(4x)31ββx=0
3Γ(4x)31ββ3x=0
3(4x)31ββ3x=0β
Step 2: Simplify the Equation
The second step is to simplify the equation by combining like terms. We can start by factoring out the common term 3 from the first term:
3(4x)31ββ3x=0
3(4x)31ββ3x=3(4x)31ββ3x
3(4x)31ββ3x=3(4x)31ββ3xβ
Step 3: Solve for x
Now that we have simplified the equation, we can solve for x. To do this, we need to isolate x on one side of the equation. We can start by adding 3x to both sides of the equation:
3(4x)31ββ3x=0
3(4x)31β=3x
3(4x)31β=3xβ
Next, we can divide both sides of the equation by 3 to get:
(4x)31β=x
Step 4: Cube Both Sides
The next step is to cube both sides of the equation to get rid of the cube root. This will give us:
(4x)31β=x
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
(4x)31β=xβ
((4x)31β)3=x3
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**Q&A: Solving the Equation $(4x)^{\frac{1}{3}} - x = 0$**
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**Q: What is the first step in solving the equation $(4x)^{\frac{1}{3}} - x = 0$?**
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A: The first step in solving this equation is to isolate the variable $x$. To do this, we need to get rid of the fraction by multiplying both sides of the equation by the denominator, which is $3$. This will give us:
$(4x)^{\frac{1}{3}} - x = 0
3Γ(4x)31ββ3x=0
Q: What is the second step in solving the equation (4x)31ββx=0?
A: The second step is to simplify the equation by combining like terms. We can start by factoring out the common term 3 from the first term:
3(4x)31ββ3x=0
3(4x)31ββ3x=3(4x)31ββ3x
Q: How do we solve for x in the equation (4x)31ββx=0?
A: To solve for x, we need to isolate x on one side of the equation. We can start by adding 3x to both sides of the equation:
3(4x)31ββ3x=0
3(4x)31β=3x
Next, we can divide both sides of the equation by 3 to get:
(4x)31β=x
Q: What is the next step in solving the equation (4x)31ββx=0?
A: The next step is to cube both sides of the equation to get rid of the cube root. This will give us:
(4x)31β=x
((4x)31β)3=x3
Q: How do we simplify the equation after cubing both sides?
A: After cubing both sides, we can simplify the equation by expanding the left-hand side:
((4x)31β)3=x3
(4x)1=x3
4x=x3
Q: What is the final step in solving the equation (4x)31ββx=0?
A: The final step is to solve for x by isolating it on one side of the equation. We can start by dividing both sides of the equation by x:
4x=x3
x4xβ=xx3β
4=x2
Q: What is the solution to the equation (4x)31ββx=0?
A: The solution to the equation is x=Β±2.
Conclusion
In this article, we have walked through the steps to solve the equation (4x)31ββx=0. We have isolated the variable x, simplified the equation, and solved for x by cubing both sides and isolating it on one side of the equation. The solution to the equation is x=Β±2.