Rewrite The Equation To Simplify Or Make Sense.Solve The Equation:$\cos X - \cos^3 X = \tan X (\cos X - \cos X \sin^2 X$\]

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Introduction

Trigonometric equations can be complex and challenging to solve, but with the right approach, they can be simplified and made more manageable. In this article, we will focus on rewriting the given equation to simplify or make sense. We will use trigonometric identities and formulas to manipulate the equation and arrive at a solution.

The Given Equation

The given equation is:

cos⁑xβˆ’cos⁑3x=tan⁑x(cos⁑xβˆ’cos⁑xsin⁑2x)\cos x - \cos^3 x = \tan x (\cos x - \cos x \sin^2 x)

Step 1: Simplify the Right-Hand Side

To simplify the right-hand side of the equation, we can start by using the trigonometric identity:

tan⁑x=sin⁑xcos⁑x\tan x = \frac{\sin x}{\cos x}

Substituting this into the equation, we get:

cos⁑xβˆ’cos⁑3x=sin⁑xcos⁑x(cos⁑xβˆ’cos⁑xsin⁑2x)\cos x - \cos^3 x = \frac{\sin x}{\cos x} (\cos x - \cos x \sin^2 x)

Step 2: Simplify the Expression Inside the Parentheses

We can simplify the expression inside the parentheses by factoring out cos⁑x\cos x:

cos⁑xβˆ’cos⁑xsin⁑2x=cos⁑x(1βˆ’sin⁑2x)\cos x - \cos x \sin^2 x = \cos x (1 - \sin^2 x)

Using the trigonometric identity:

1βˆ’sin⁑2x=cos⁑2x1 - \sin^2 x = \cos^2 x

We can rewrite the expression as:

cos⁑xβˆ’cos⁑xsin⁑2x=cos⁑xcos⁑2x\cos x - \cos x \sin^2 x = \cos x \cos^2 x

Step 3: Substitute the Simplified Expression Back into the Equation

Substituting the simplified expression back into the equation, we get:

cos⁑xβˆ’cos⁑3x=sin⁑xcos⁑x(cos⁑xcos⁑2x)\cos x - \cos^3 x = \frac{\sin x}{\cos x} (\cos x \cos^2 x)

Step 4: Simplify the Right-Hand Side Further

We can simplify the right-hand side further by canceling out the cos⁑x\cos x term:

cos⁑xβˆ’cos⁑3x=sin⁑xcos⁑2x\cos x - \cos^3 x = \sin x \cos^2 x

Step 5: Factor Out cos⁑x\cos x from the Left-Hand Side

We can factor out cos⁑x\cos x from the left-hand side of the equation:

cos⁑x(1βˆ’cos⁑2x)=sin⁑xcos⁑2x\cos x (1 - \cos^2 x) = \sin x \cos^2 x

Step 6: Simplify the Expression Inside the Parentheses

We can simplify the expression inside the parentheses by using the trigonometric identity:

1βˆ’cos⁑2x=sin⁑2x1 - \cos^2 x = \sin^2 x

We can rewrite the expression as:

cos⁑xsin⁑2x=sin⁑xcos⁑2x\cos x \sin^2 x = \sin x \cos^2 x

Step 7: Divide Both Sides by cos⁑x\cos x

We can divide both sides of the equation by cos⁑x\cos x to get:

sin⁑2x=tan⁑xcos⁑x\sin^2 x = \tan x \cos x

Step 8: Simplify the Right-Hand Side

We can simplify the right-hand side by using the trigonometric identity:

tan⁑x=sin⁑xcos⁑x\tan x = \frac{\sin x}{\cos x}

Substituting this into the equation, we get:

sin⁑2x=sin⁑xcos⁑xcos⁑x\sin^2 x = \frac{\sin x}{\cos x} \cos x

Step 9: Cancel Out the cos⁑x\cos x Term

We can cancel out the cos⁑x\cos x term on both sides of the equation:

sin⁑2x=sin⁑x\sin^2 x = \sin x

Step 10: Solve for sin⁑x\sin x

We can solve for sin⁑x\sin x by dividing both sides of the equation by sin⁑x\sin x:

sin⁑x=1\sin x = 1

Conclusion

In this article, we have simplified the given trigonometric equation by using various trigonometric identities and formulas. We have arrived at the solution sin⁑x=1\sin x = 1, which is a valid solution for the given equation.

Final Answer

The final answer is 1\boxed{1}.

Note

Q: What is the given equation?

A: The given equation is cos⁑xβˆ’cos⁑3x=tan⁑x(cos⁑xβˆ’cos⁑xsin⁑2x)\cos x - \cos^3 x = \tan x (\cos x - \cos x \sin^2 x).

Q: How do I simplify the right-hand side of the equation?

A: To simplify the right-hand side of the equation, you can start by using the trigonometric identity tan⁑x=sin⁑xcos⁑x\tan x = \frac{\sin x}{\cos x}. Substituting this into the equation, you get cos⁑xβˆ’cos⁑3x=sin⁑xcos⁑x(cos⁑xβˆ’cos⁑xsin⁑2x)\cos x - \cos^3 x = \frac{\sin x}{\cos x} (\cos x - \cos x \sin^2 x).

Q: How do I simplify the expression inside the parentheses?

A: You can simplify the expression inside the parentheses by factoring out cos⁑x\cos x. This gives you cos⁑xβˆ’cos⁑xsin⁑2x=cos⁑x(1βˆ’sin⁑2x)\cos x - \cos x \sin^2 x = \cos x (1 - \sin^2 x). Using the trigonometric identity 1βˆ’sin⁑2x=cos⁑2x1 - \sin^2 x = \cos^2 x, you can rewrite the expression as cos⁑xβˆ’cos⁑xsin⁑2x=cos⁑xcos⁑2x\cos x - \cos x \sin^2 x = \cos x \cos^2 x.

Q: How do I substitute the simplified expression back into the equation?

A: You can substitute the simplified expression back into the equation by replacing the original expression with the simplified one. This gives you cos⁑xβˆ’cos⁑3x=sin⁑xcos⁑x(cos⁑xcos⁑2x)\cos x - \cos^3 x = \frac{\sin x}{\cos x} (\cos x \cos^2 x).

Q: How do I simplify the right-hand side further?

A: You can simplify the right-hand side further by canceling out the cos⁑x\cos x term. This gives you cos⁑xβˆ’cos⁑3x=sin⁑xcos⁑2x\cos x - \cos^3 x = \sin x \cos^2 x.

Q: How do I factor out cos⁑x\cos x from the left-hand side?

A: You can factor out cos⁑x\cos x from the left-hand side of the equation by grouping the terms. This gives you cos⁑x(1βˆ’cos⁑2x)=sin⁑xcos⁑2x\cos x (1 - \cos^2 x) = \sin x \cos^2 x.

Q: How do I simplify the expression inside the parentheses?

A: You can simplify the expression inside the parentheses by using the trigonometric identity 1βˆ’cos⁑2x=sin⁑2x1 - \cos^2 x = \sin^2 x. This gives you cos⁑xsin⁑2x=sin⁑xcos⁑2x\cos x \sin^2 x = \sin x \cos^2 x.

Q: How do I divide both sides by cos⁑x\cos x?

A: You can divide both sides of the equation by cos⁑x\cos x to get sin⁑2x=tan⁑xcos⁑x\sin^2 x = \tan x \cos x.

Q: How do I simplify the right-hand side?

A: You can simplify the right-hand side by using the trigonometric identity tan⁑x=sin⁑xcos⁑x\tan x = \frac{\sin x}{\cos x}. Substituting this into the equation, you get sin⁑2x=sin⁑xcos⁑xcos⁑x\sin^2 x = \frac{\sin x}{\cos x} \cos x.

Q: How do I cancel out the cos⁑x\cos x term?

A: You can cancel out the cos⁑x\cos x term on both sides of the equation by dividing both sides by cos⁑x\cos x. This gives you sin⁑2x=sin⁑x\sin^2 x = \sin x.

Q: How do I solve for sin⁑x\sin x?

A: You can solve for sin⁑x\sin x by dividing both sides of the equation by sin⁑x\sin x. This gives you sin⁑x=1\sin x = 1.

Q: What is the final answer?

A: The final answer is 1\boxed{1}.

Q: What is the given equation?

A: The given equation is cos⁑xβˆ’cos⁑3x=tan⁑x(cos⁑xβˆ’cos⁑xsin⁑2x)\cos x - \cos^3 x = \tan x (\cos x - \cos x \sin^2 x).

Q: How do I simplify the equation?

A: You can simplify the equation by using various trigonometric identities and formulas. The steps to simplify the equation are:

  1. Simplify the right-hand side of the equation.
  2. Simplify the expression inside the parentheses.
  3. Substitute the simplified expression back into the equation.
  4. Simplify the right-hand side further.
  5. Factor out cos⁑x\cos x from the left-hand side.
  6. Simplify the expression inside the parentheses.
  7. Divide both sides by cos⁑x\cos x.
  8. Simplify the right-hand side.
  9. Cancel out the cos⁑x\cos x term.
  10. Solve for sin⁑x\sin x.

Q: What is the solution to the equation?

A: The solution to the equation is sin⁑x=1\sin x = 1.

Q: What is the final answer?

A: The final answer is 1\boxed{1}.