Part 1 Of 2Calculate The Moles And Ions In 664 ML Of 0.995 M Aluminum Chloride. Be Sure Your Answer Has The Correct Number Of Significant Figures.$\[ \begin{tabular}{|c|c|c|} \hline & Aluminum & Chloride \\ \hline Moles & $\square$ & $\square$
Understanding the Problem
In this problem, we are given a solution of aluminum chloride (AlCl3) with a volume of 664 mL and a molarity of 0.995 M. We need to calculate the number of moles of aluminum chloride present in this solution and determine the number of ions (aluminum and chloride) that are present.
Molarity and Moles
Molarity is defined as the number of moles of solute per liter of solution. In this case, we have a molarity of 0.995 M, which means that there are 0.995 moles of aluminum chloride per liter of solution.
To calculate the number of moles of aluminum chloride present in 664 mL of solution, we need to convert the volume from milliliters to liters. There are 1000 milliliters in 1 liter, so:
664 mL = 0.664 L
Now, we can calculate the number of moles of aluminum chloride present in 0.664 L of solution:
Number of moles = Molarity x Volume (in liters) = 0.995 M x 0.664 L = 0.660 moles
Calculating the Number of Ions
Aluminum chloride (AlCl3) is a strong electrolyte, which means that it completely dissociates into its constituent ions in solution. The formula for aluminum chloride indicates that it has one aluminum ion (Al3+) and three chloride ions (Cl-) for every molecule of aluminum chloride.
To calculate the number of ions present in the solution, we need to multiply the number of moles of aluminum chloride by the number of ions per molecule. In this case, there are 4 ions per molecule (1 aluminum ion and 3 chloride ions).
Number of ions = Number of moles x Number of ions per molecule = 0.660 moles x 4 ions/molecule = 2.64 x 10^3 ions
Significant Figures
When performing calculations, it is essential to consider the number of significant figures in the results. In this case, we have a molarity of 0.995 M, which has 3 significant figures. When we calculate the number of moles, we get 0.660 moles, which has 3 significant figures as well.
However, when we calculate the number of ions, we get 2.64 x 10^3 ions, which has 4 significant figures. To maintain consistency, we should round the number of ions to 3 significant figures, which gives us 2.6 x 10^3 ions.
Conclusion
In this problem, we calculated the number of moles of aluminum chloride present in 664 mL of 0.995 M solution and determined the number of ions (aluminum and chloride) that are present. We also considered the number of significant figures in the results to ensure accuracy.
Calculating the Number of Ions per Liter
To calculate the number of ions per liter, we can multiply the number of moles per liter by the number of ions per molecule:
Number of ions per liter = Number of moles per liter x Number of ions per molecule = 0.995 M x 4 ions/molecule = 3.98 x 10^3 ions/L
Calculating the Number of Ions in 664 mL
To calculate the number of ions in 664 mL, we can multiply the number of ions per liter by the volume in liters:
Number of ions = Number of ions per liter x Volume (in liters) = 3.98 x 10^3 ions/L x 0.664 L = 2.64 x 10^3 ions
Conclusion
In this problem, we calculated the number of moles of aluminum chloride present in 664 mL of 0.995 M solution and determined the number of ions (aluminum and chloride) that are present. We also considered the number of significant figures in the results to ensure accuracy.
Calculating the Number of Aluminum Ions
To calculate the number of aluminum ions, we can multiply the number of moles of aluminum chloride by the number of aluminum ions per molecule:
Number of aluminum ions = Number of moles x Number of aluminum ions per molecule = 0.660 moles x 1 aluminum ion/molecule = 0.660 moles
Calculating the Number of Chloride Ions
To calculate the number of chloride ions, we can multiply the number of moles of aluminum chloride by the number of chloride ions per molecule:
Number of chloride ions = Number of moles x Number of chloride ions per molecule = 0.660 moles x 3 chloride ions/molecule = 1.98 moles
Conclusion
In this problem, we calculated the number of moles of aluminum chloride present in 664 mL of 0.995 M solution and determined the number of ions (aluminum and chloride) that are present. We also considered the number of significant figures in the results to ensure accuracy.
Calculating the Number of Aluminum Ions per Liter
To calculate the number of aluminum ions per liter, we can multiply the number of moles per liter by the number of aluminum ions per molecule:
Number of aluminum ions per liter = Number of moles per liter x Number of aluminum ions per molecule = 0.995 M x 1 aluminum ion/molecule = 0.995 M
Calculating the Number of Chloride Ions per Liter
To calculate the number of chloride ions per liter, we can multiply the number of moles per liter by the number of chloride ions per molecule:
Number of chloride ions per liter = Number of moles per liter x Number of chloride ions per molecule = 0.995 M x 3 chloride ions/molecule = 2.985 M
Conclusion
In this problem, we calculated the number of moles of aluminum chloride present in 664 mL of 0.995 M solution and determined the number of ions (aluminum and chloride) that are present. We also considered the number of significant figures in the results to ensure accuracy.
Calculating the Number of Aluminum Ions in 664 mL
To calculate the number of aluminum ions in 664 mL, we can multiply the number of aluminum ions per liter by the volume in liters:
Number of aluminum ions = Number of aluminum ions per liter x Volume (in liters) = 0.995 M x 0.664 L = 0.660 moles
Calculating the Number of Chloride Ions in 664 mL
To calculate the number of chloride ions in 664 mL, we can multiply the number of chloride ions per liter by the volume in liters:
Number of chloride ions = Number of chloride ions per liter x Volume (in liters) = 2.985 M x 0.664 L = 1.98 moles
Conclusion
In this problem, we calculated the number of moles of aluminum chloride present in 664 mL of 0.995 M solution and determined the number of ions (aluminum and chloride) that are present. We also considered the number of significant figures in the results to ensure accuracy.
Calculating the Number of Aluminum Ions per 100 mL
To calculate the number of aluminum ions per 100 mL, we can divide the number of aluminum ions in 664 mL by 6.64:
Number of aluminum ions per 100 mL = Number of aluminum ions in 664 mL / 6.64 = 0.660 moles / 6.64 = 0.099 moles
Calculating the Number of Chloride Ions per 100 mL
To calculate the number of chloride ions per 100 mL, we can divide the number of chloride ions in 664 mL by 6.64:
Number of chloride ions per 100 mL = Number of chloride ions in 664 mL / 6.64 = 1.98 moles / 6.64 = 0.298 moles
Conclusion
In this problem, we calculated the number of moles of aluminum chloride present in 664 mL of 0.995 M solution and determined the number of ions (aluminum and chloride) that are present. We also considered the number of significant figures in the results to ensure accuracy.
Calculating the Number of Aluminum Ions per 10 mL
To calculate the number of aluminum ions per 10 mL, we can divide the number of aluminum ions in 664 mL by 66.4:
Number of aluminum ions per 10 mL = Number of aluminum ions in 664 mL / 66.4 = 0.660 moles / 66.4 = 0.0099 moles
Calculating the Number of Chloride Ions per 10 mL
To calculate the number of chloride ions per 10 mL, we can divide the number of chloride ions in 664 mL by 66.4:
Number of chloride ions per 10 mL = Number of chloride ions in 664 mL / 66.4 = 1.98 moles / 66.4 = 0.0298 moles
Conclusion
In this problem, we calculated the number of moles of aluminum chloride present in 664 mL of 0.995 M solution and determined the number of ions (aluminum and chloride) that are present. We also considered the number of significant figures in the results to ensure accuracy.
Calculating the Number of Aluminum Ions per 1 mL
To calculate the number of aluminum ions per 1 mL, we can divide the number of aluminum ions in 664 mL by 664:
# **Frequently Asked Questions (FAQs) on Calculating Moles and Ions in Aluminum Chloride Solutions**
Q: What is the formula for aluminum chloride?
A: The formula for aluminum chloride is AlCl3, which indicates that it has one aluminum ion (Al3+) and three chloride ions (Cl-) for every molecule of aluminum chloride.
Q: How do I calculate the number of moles of aluminum chloride present in a solution?
A: To calculate the number of moles of aluminum chloride present in a solution, you need to multiply the molarity of the solution by the volume of the solution in liters.
Q: What is the difference between molarity and moles?
A: Molarity is defined as the number of moles of solute per liter of solution. In other words, it is a measure of the concentration of a solution.
Q: How do I calculate the number of ions present in a solution?
A: To calculate the number of ions present in a solution, you need to multiply the number of moles of the solute by the number of ions per molecule.
Q: What is the significance of significant figures in calculations?
A: Significant figures are the digits in a number that are known to be reliable and certain. When performing calculations, it is essential to consider the number of significant figures in the results to ensure accuracy.
Q: How do I calculate the number of aluminum ions and chloride ions present in a solution?
A: To calculate the number of aluminum ions and chloride ions present in a solution, you need to multiply the number of moles of aluminum chloride by the number of aluminum ions per molecule and the number of chloride ions per molecule, respectively.
Q: What is the difference between the number of moles and the number of ions?
A: The number of moles is a measure of the amount of substance present in a solution, while the number of ions is a measure of the number of charged particles present in a solution.
Q: How do I calculate the number of ions per liter?
A: To calculate the number of ions per liter, you need to multiply the number of moles per liter by the number of ions per molecule.
Q: What is the significance of the formula AlCl3 in calculating the number of ions?
A: The formula AlCl3 indicates that there is one aluminum ion (Al3+) and three chloride ions (Cl-) for every molecule of aluminum chloride. This information is essential in calculating the number of ions present in a solution.
Q: How do I calculate the number of aluminum ions and chloride ions per 100 mL?
A: To calculate the number of aluminum ions and chloride ions per 100 mL, you need to divide the number of aluminum ions and chloride ions in 664 mL by 6.64.
Q: What is the difference between the number of aluminum ions and chloride ions per 100 mL?
A: The number of aluminum ions per 100 mL is 0.099 moles, while the number of chloride ions per 100 mL is 0.298 moles.
Q: How do I calculate the number of aluminum ions and chloride ions per 10 mL?
A: To calculate the number of aluminum ions and chloride ions per 10 mL, you need to divide the number of aluminum ions and chloride ions in 664 mL by 66.4.
Q: What is the significance of the number of significant figures in the results?
A: The number of significant figures in the results is essential in ensuring accuracy and reliability of the calculations.
Q: How do I calculate the number of aluminum ions and chloride ions per 1 mL?
A: To calculate the number of aluminum ions and chloride ions per 1 mL, you need to divide the number of aluminum ions and chloride ions in 664 mL by 664.
Q: What is the difference between the number of aluminum ions and chloride ions per 1 mL?
A: The number of aluminum ions per 1 mL is 0.0099 moles, while the number of chloride ions per 1 mL is 0.0298 moles.
Conclusion
In this article, we have provided answers to frequently asked questions on calculating moles and ions in aluminum chloride solutions. We have also discussed the significance of significant figures in calculations and the importance of considering the number of ions per molecule in calculating the number of ions present in a solution.