Nitrogen Gas Reacts With Oxygen Gas To Form Dinitrogen Trioxide Gas. How Many Moles And Grams Of Oxygen Gas Will React With 72.5 G Of Nitrogen Gas To Produce Dinitrogen Trioxide? Balance The Equation First.$\ldots N_2(g) + \ldots O_2(g) \rightarrow

Mar 11, 2025 by ADMIN 249 views

**Nitrogen Gas Reacts with Oxygen Gas to Form Dinitrogen Trioxide Gas: A Comprehensive Analysis**

Introduction

Nitrogen gas (N2) and oxygen gas (O2) are two of the most abundant elements in the Earth's atmosphere. When these two gases react, they form dinitrogen trioxide (N2O3), a compound that plays a crucial role in various chemical reactions. In this article, we will explore the reaction between nitrogen gas and oxygen gas to form dinitrogen trioxide, balance the chemical equation, and determine the number of moles and grams of oxygen gas required to react with 72.5 g of nitrogen gas.

Balancing the Chemical Equation

The unbalanced chemical equation for the reaction between nitrogen gas and oxygen gas to form dinitrogen trioxide is:

$\ldots N_2(g) + \ldots O_2(g) \rightarrow N_2O_3(g)$

To balance the equation, we need to ensure that the number of atoms of each element is the same on both the reactant and product sides. The balanced equation is:

$2N_2(g) + 5O_2(g) \rightarrow 2N_2O_3(g)$

Understanding the Reaction

In the balanced equation, 2 moles of nitrogen gas react with 5 moles of oxygen gas to produce 2 moles of dinitrogen trioxide. The reaction is a combustion reaction, where oxygen gas is used to oxidize the nitrogen gas, resulting in the formation of dinitrogen trioxide.

Calculating the Number of Moles of Oxygen Gas

To determine the number of moles of oxygen gas required to react with 72.5 g of nitrogen gas, we need to follow these steps:

Calculate the number of moles of nitrogen gas: The molar mass of nitrogen gas (N2) is 28.01 g/mol. We can calculate the number of moles of nitrogen gas using the formula:

moles = mass / molar mass

moles = 72.5 g / 28.01 g/mol = 2.59 mol

Determine the mole ratio of nitrogen gas to oxygen gas: From the balanced equation, we can see that 2 moles of nitrogen gas react with 5 moles of oxygen gas. Therefore, the mole ratio of nitrogen gas to oxygen gas is 2:5.
Calculate the number of moles of oxygen gas: Using the mole ratio, we can calculate the number of moles of oxygen gas required to react with 2.59 mol of nitrogen gas:

moles of oxygen gas = (5/2) × moles of nitrogen gas moles of oxygen gas = (5/2) × 2.59 mol = 6.48 mol

Calculating the Mass of Oxygen Gas

To determine the mass of oxygen gas required to react with 72.5 g of nitrogen gas, we need to multiply the number of moles of oxygen gas by its molar mass (32.00 g/mol):

mass of oxygen gas = moles of oxygen gas × molar mass mass of oxygen gas = 6.48 mol × 32.00 g/mol = 207.36 g

Conclusion

In conclusion, when 72.5 g of nitrogen gas reacts with oxygen gas to form dinitrogen trioxide, 6.48 moles of oxygen gas are required. The mass of oxygen gas required is 207.36 g. The balanced chemical equation for the reaction is:

$2N_2(g) + 5O_2(g) \rightarrow 2N_2O_3(g)$

This analysis demonstrates the importance of balancing chemical equations and understanding the mole ratio of reactants in a chemical reaction.

References

CRC Handbook of Chemistry and Physics, 97th ed. (2016)
Chemical Equations and Reactions, 2nd ed. (2018)
General Chemistry: Principles and Modern Applications, 11th ed. (2018)

Additional Resources

Chemical Equation Balancer: A tool for balancing chemical equations
Molar Mass Calculator: A tool for calculating the molar mass of a substance
Chemical Reaction Simulator: A tool for simulating chemical reactions
Nitrogen Gas Reacts with Oxygen Gas to Form Dinitrogen Trioxide Gas: A Comprehensive Analysis ===========================================================

Q&A: Frequently Asked Questions

Q: What is the balanced chemical equation for the reaction between nitrogen gas and oxygen gas to form dinitrogen trioxide? A: The balanced chemical equation for the reaction is:

$2N_2(g) + 5O_2(g) \rightarrow 2N_2O_3(g)$

Q: How many moles of oxygen gas are required to react with 72.5 g of nitrogen gas? A: To determine the number of moles of oxygen gas required, we need to follow these steps:

Calculate the number of moles of nitrogen gas: moles = mass / molar mass = 72.5 g / 28.01 g/mol = 2.59 mol
Determine the mole ratio of nitrogen gas to oxygen gas: 2 moles of nitrogen gas react with 5 moles of oxygen gas
Calculate the number of moles of oxygen gas: moles of oxygen gas = (5/2) × moles of nitrogen gas = (5/2) × 2.59 mol = 6.48 mol

Q: What is the mass of oxygen gas required to react with 72.5 g of nitrogen gas? A: To determine the mass of oxygen gas required, we need to multiply the number of moles of oxygen gas by its molar mass (32.00 g/mol):

mass of oxygen gas = moles of oxygen gas × molar mass = 6.48 mol × 32.00 g/mol = 207.36 g

Q: What is the role of oxygen gas in the reaction? A: Oxygen gas is used to oxidize the nitrogen gas, resulting in the formation of dinitrogen trioxide.

Q: What is the significance of balancing chemical equations? A: Balancing chemical equations is crucial in understanding the mole ratio of reactants and products in a chemical reaction. It helps to ensure that the number of atoms of each element is the same on both the reactant and product sides.

Q: How can I calculate the number of moles of a substance? A: To calculate the number of moles of a substance, you need to divide the mass of the substance by its molar mass.

Q: What is the molar mass of nitrogen gas (N2)? A: The molar mass of nitrogen gas (N2) is 28.01 g/mol.

Q: What is the molar mass of oxygen gas (O2)? A: The molar mass of oxygen gas (O2) is 32.00 g/mol.

Q: How can I determine the mole ratio of reactants in a chemical reaction? A: To determine the mole ratio of reactants, you need to balance the chemical equation and identify the coefficients of the reactants.

Q: What is the importance of understanding chemical reactions? A: Understanding chemical reactions is crucial in various fields, including chemistry, biology, and engineering. It helps to predict the outcome of a reaction, identify potential hazards, and develop new products and processes.

Conclusion

In conclusion, the reaction between nitrogen gas and oxygen gas to form dinitrogen trioxide is a complex process that requires a thorough understanding of chemical equations and reactions. By balancing the chemical equation and determining the mole ratio of reactants, we can predict the outcome of the reaction and identify potential hazards. This analysis demonstrates the importance of understanding chemical reactions and their applications in various fields.

References

CRC Handbook of Chemistry and Physics, 97th ed. (2016)
Chemical Equations and Reactions, 2nd ed. (2018)
General Chemistry: Principles and Modern Applications, 11th ed. (2018)

Additional Resources

Chemical Equation Balancer: A tool for balancing chemical equations
Molar Mass Calculator: A tool for calculating the molar mass of a substance
Chemical Reaction Simulator: A tool for simulating chemical reactions