Jo Loaned Al $15. She Had $15 Left. Solve The Equation 15 = S − 15 15 = S - 15 15 = S − 15 To Find How Much Money Jo Had Before She Made The Loan.A. $0 B. $15 C. $30 D. $60

Introduction

In this article, we will be solving a simple algebraic equation to find the initial amount of money Jo had before making a loan to Al. The equation provided is $15 = s - 15$, where $s$ represents the initial amount of money Jo had. We will use basic algebraic techniques to isolate the variable $s$ and find its value.

Understanding the Equation

The equation $15 = s - 15$ can be read as "15 is equal to the initial amount of money Jo had minus 15". This equation is a linear equation in one variable, where the variable is $s$. Our goal is to solve for $s$.

Isolating the Variable

To isolate the variable $s$, we need to get rid of the constant term $-15$ that is being subtracted from $s$. We can do this by adding 15 to both sides of the equation. This will cancel out the $-15$ on the right-hand side of the equation.

15 = s - 15
15 + 15 = s - 15 + 15
30 = s

Solving for $s$

By adding 15 to both sides of the equation, we have isolated the variable $s$. The equation now becomes $30 = s$. This means that the initial amount of money Jo had is $30.

Conclusion

In conclusion, we have solved the equation $15 = s - 15$ to find the initial amount of money Jo had before making the loan to Al. The solution to the equation is $s = 30$. This means that Jo had $30 initially.

Answer

The correct answer is:

• C. $30

Discussion

This problem is a simple algebraic equation that requires basic algebraic techniques to solve. The equation is linear in one variable, and we used the technique of adding a constant term to both sides of the equation to isolate the variable. This problem is a good example of how algebra can be used to solve real-world problems, such as finding the initial amount of money someone had before making a loan.

Related Problems

If you are interested in solving more problems like this, here are a few related problems:

• Solve the equation $20 = x + 10$ to find the value of $x$.
• Solve the equation $5 = y - 2$ to find the value of $y$.
• Solve the equation $10 = z - 5$ to find the value of $z$.

Introduction

In our previous article, we solved the equation $15 = s - 15$ to find the initial amount of money Jo had before making a loan to Al. The solution to the equation was $s = 30$. In this article, we will provide a Q&A guide to help you understand the problem and its solution.

Q: What is the equation $15 = s - 15$ trying to solve?

A: The equation $15 = s - 15$ is trying to find the initial amount of money Jo had before making a loan to Al. The variable $s$ represents the initial amount of money Jo had.

Q: How do we solve the equation $15 = s - 15$?

A: To solve the equation $15 = s - 15$, we need to isolate the variable $s$. We can do this by adding 15 to both sides of the equation. This will cancel out the $-15$ on the right-hand side of the equation.

Q: What happens when we add 15 to both sides of the equation?

A: When we add 15 to both sides of the equation, we get:

15 = s - 15
15 + 15 = s - 15 + 15
30 = s

Q: What does the equation $30 = s$ mean?

A: The equation $30 = s$ means that the initial amount of money Jo had is $30.

Q: Why is it important to isolate the variable $s$?

A: It is important to isolate the variable $s$ because it allows us to find the value of $s$. In this case, the value of $s$ is $30, which represents the initial amount of money Jo had.

Q: Can we use this method to solve other equations?

A: Yes, we can use this method to solve other equations. The method of adding a constant term to both sides of the equation is a basic algebraic technique that can be used to solve many types of equations.

Q: What are some common mistakes to avoid when solving equations?

A: Some common mistakes to avoid when solving equations include:

• Not isolating the variable
• Adding or subtracting the wrong terms
• Not checking the solution

Q: How can we check the solution to an equation?

A: We can check the solution to an equation by plugging the value of the variable back into the original equation. If the equation is true, then the solution is correct.

Conclusion

In conclusion, solving the equation $15 = s - 15$ requires basic algebraic techniques, including isolating the variable and adding a constant term to both sides of the equation. By following these steps, we can find the initial amount of money Jo had before making a loan to Al. We hope this Q&A guide has helped you understand the problem and its solution.

Related Resources

If you are interested in learning more about algebra and solving equations, here are some related resources:

• Algebra for Dummies: A comprehensive guide to algebra, including equations, functions, and graphs.
• Solving Equations: A step-by-step guide to solving equations, including linear and quadratic equations.
• Math Help: A website that provides math help and resources, including algebra and solving equations.

Final Thoughts

Solving equations is an important skill in mathematics, and it requires practice and patience. By following the steps outlined in this article, you can learn how to solve equations and become more confident in your math skills.